Timer: Off
Random: Off
201. What is meant by instantaneous velocity?
ⓐ. The velocity of an object at a particular instant
ⓑ. The average velocity over a long duration
ⓒ. The maximum velocity an object can achieve
ⓓ. The velocity of an object when it stops
Correct Answer: The velocity of an object at a particular instant
Explanation: Instantaneous velocity refers to the velocity of an object at a specific moment in time.
202. How is instantaneous velocity different from average velocity?
ⓐ. Instantaneous velocity is always greater than average velocity
ⓑ. Instantaneous velocity includes direction, while average velocity does not
ⓒ. Average velocity is calculated over a long period, while instantaneous velocity is at a specific moment
ⓓ. Average velocity is always constant, while instantaneous velocity varies
Correct Answer: Average velocity is calculated over a long period, while instantaneous velocity is at a specific moment
Explanation: Average velocity is the total displacement divided by the total time taken, while instantaneous velocity is the velocity at a particular instant.
203. If a car is moving at a steady velocity of 50 km/h eastward, what is its instantaneous velocity at any given moment?
ⓐ. 0 km/h
ⓑ. 25 km/h eastward
ⓒ. 50 km/h eastward
ⓓ. 100 km/h eastward
Correct Answer: 50 km/h eastward
Explanation: Instantaneous velocity refers to the velocity of an object at any specific moment. If the car is moving at a steady 50 km/h eastward, its instantaneous velocity remains 50 km/h eastward at any time during the steady motion.
204. Which term describes the velocity of an object at an exact moment in time?
ⓐ. Average velocity
ⓑ. Instantaneous velocity
ⓒ. Terminal velocity
ⓓ. Maximum velocity
Correct Answer: Instantaneous velocity
Explanation: Instantaneous velocity is the velocity of an object at an exact moment in time.
205. How is instantaneous velocity typically measured?
ⓐ. By dividing total distance by total time
ⓑ. By dividing total displacement by total time
ⓒ. By dividing total displacement by instantaneous time
ⓓ. By measuring displacement covered in a very short interval of time
Correct Answer: By measuring displacement covered in a very short interval of time
Explanation: Instantaneous velocity is determined by measuring the displacement an object covers in an infinitesimally small interval of time.
206. If a sprinter covers 200 meters north in 20 seconds, what is their instantaneous velocity?
ⓐ. 5 m/s north
ⓑ. 10 m/s north
ⓒ. 15 m/s north
ⓓ. 20 m/s north
Correct Answer: 10 m/s north
Explanation: Instantaneous velocity = Displacement / Time = 200 m / 20 s = 10 m/s north.
207. Which quantity describes the velocity of an object at a particular moment in time?
ⓐ. Average velocity
ⓑ. Speed
ⓒ. Acceleration
ⓓ. Instantaneous velocity
Correct Answer: Instantaneous velocity
Explanation: Instantaneous velocity refers to the velocity of an object at an exact moment in time.
208. What does the term ‘instantaneous’ mean in the context of instantaneous velocity?
ⓐ. Extremely fast
ⓑ. At a specific moment
ⓒ. Always changing
ⓓ. Average over a long period
Correct Answer: At a specific moment
Explanation: ‘Instantaneous’ means at a specific moment or instant in time.
209. If a ball is thrown upwards and its velocity at the highest point is 0 m/s, what is this velocity called?
ⓐ. Average velocity
ⓑ. Terminal velocity
ⓒ. Instantaneous velocity
ⓓ. Constant velocity
Correct Answer: Instantaneous velocity
Explanation: The velocity of the ball at the precise moment it reaches its highest point, which is 0 m/s in this case, is its instantaneous velocity.
210. Which term describes the velocity of an object at a particular instant of time?
ⓐ. Constant velocity
ⓑ. Average velocity
ⓒ. Instantaneous velocity
ⓓ. Terminal velocity
Correct Answer: Instantaneous velocity
Explanation: Instantaneous velocity is the velocity of an object at a particular instant of time, not averaged over time.
211. In a velocity-time graph, what does the slope of the graph represent?
ⓐ. Distance
ⓑ. Acceleration
ⓒ. Displacement
ⓓ. Speed
Correct Answer: Acceleration
Explanation: In a velocity-time graph, the slope represents the acceleration of the object. A steeper slope indicates a greater acceleration, either positive or negative.
212. If a car is moving with a constant velocity of 40 km/h, what would its velocity-time graph look like?
ⓐ. A horizontal line at 40 km/h
ⓑ. A diagonal line sloping upward
ⓒ. A diagonal line sloping downward
ⓓ. A vertical line
Correct Answer: A horizontal line at 40 km/h
Explanation: A constant velocity means the velocity-time graph will be a horizontal line parallel to the time axis at the value of 40 km/h.
213. What type of motion does a horizontal line on a velocity-time graph represent?
ⓐ. Accelerated motion
ⓑ. Decelerated motion
ⓒ. Constant velocity
ⓓ. Variable velocity
Correct Answer: Constant velocity
Explanation: A horizontal line on a velocity-time graph represents constant velocity, where the velocity of the object does not change over time.
214. If a cyclist starts from rest and accelerates uniformly, what does their velocity-time graph look like?
ⓐ. A straight line sloping upward
ⓑ. A straight line sloping downward
ⓒ. A curved line
ⓓ. A horizontal line
Correct Answer: A straight line sloping upward
Explanation: Uniform acceleration results in a velocity-time graph that is a straight line sloping upward, indicating increasing velocity over time.
215. If an object is moving with a constant negative acceleration, what does its velocity-time graph look like?
ⓐ. A straight line sloping upward
ⓑ. A straight line sloping downward
ⓒ. A horizontal line
ⓓ. A curved line
Correct Answer: A straight line sloping downward
Explanation: A constant negative acceleration results in a velocity-time graph that is a straight line sloping downward, indicating decreasing velocity over time.
216. What does the area under a velocity-time graph represent?
ⓐ. Displacement
ⓑ. Speed
ⓒ. Acceleration
ⓓ. Distance
Correct Answer: Displacement
Explanation: The area under a velocity-time graph represents the displacement of the object. It is calculated by finding the area enclosed between the graph line and the time axis.
217. If a car starts from rest and accelerates uniformly, what does the shape of its velocity-time graph resemble?
ⓐ. A straight line
ⓑ. A curve
ⓒ. A zigzag line
ⓓ. A loop
Correct Answer: A straight line
Explanation: Uniform acceleration results in a velocity-time graph that is a straight line, indicating a constant rate of change of velocity.
218. Which graph represents an object moving with increasing speed?
ⓐ. A line sloping upward
ⓑ. A line sloping downward
ⓒ. A horizontal line
ⓓ. A vertical line
Correct Answer: A line sloping upward
Explanation: A line sloping upward on a velocity-time graph indicates that the object’s speed is increasing over time.
219. In a velocity-time graph, what does a negative slope indicate?
ⓐ. Acceleration
ⓑ. Deceleration
ⓒ. Constant velocity
ⓓ. Rest
Correct Answer: Deceleration
Explanation: A negative slope on a velocity-time graph indicates deceleration, where the object is slowing down over time.
220. If an object moves with a varying velocity, what does its velocity-time graph look like?
ⓐ. A straight line
ⓑ. A curve
ⓒ. A zigzag line
ⓓ. A loop
Correct Answer: A curve
Explanation: Varying velocity results in a velocity-time graph that is curved, indicating changes in velocity over time.
221. How is instantaneous velocity calculated from a position-time graph?
ⓐ. By finding the slope of the tangent to the curve at a specific point
ⓑ. By finding the area under the curve
ⓒ. By dividing total displacement by total time
ⓓ. By subtracting initial velocity from final velocity
Correct Answer: By finding the slope of the tangent to the curve at a specific point
Explanation: Instantaneous velocity from a position-time graph is determined by finding the slope of the tangent to the curve at the desired point.
222. If a car moves along a straight road and its position-time graph is a straight line, how can you find its instantaneous velocity?
ⓐ. By calculating the average velocity
ⓑ. By dividing total displacement by total time
ⓒ. By finding the slope of the line
ⓓ. By dividing total distance by total time
Correct Answer: By finding the slope of the line
Explanation: For a straight line on a position-time graph, instantaneous velocity is found by determining the slope of the line, which represents the constant velocity of the car.
223. In a velocity-time graph, how is instantaneous velocity calculated?
ⓐ. By finding the slope of the curve
ⓑ. By finding the area under the curve
ⓒ. By dividing total displacement by total time
ⓓ. By subtracting initial velocity from final velocity
Correct Answer: By finding the slope of the curve
Explanation: Instantaneous velocity in a velocity-time graph is found by determining the slope of the curve at the desired point, which represents the rate of change of velocity at that instant.
224. If an object’s velocity changes with time, how can you determine its instantaneous velocity?
ⓐ. By calculating the average velocity over a short interval
ⓑ. By dividing total displacement by total time
ⓒ. By measuring the maximum velocity reached
ⓓ. By dividing total distance by total time
Correct Answer: By calculating the average velocity over a short interval
Explanation: For changing velocity, instantaneous velocity can be approximated by calculating the average velocity over a very short interval of time.
225. What does the term ‘instantaneous’ refer to in the context of instantaneous velocity?
ⓐ. The highest velocity reached by an object
ⓑ. The velocity at a particular instant in time
ⓒ. The average velocity over a long period
ⓓ. The constant velocity of an object
Correct Answer: The velocity at a particular instant in time
Explanation: ‘Instantaneous’ in the context of velocity refers to the velocity of an object at an exact moment or instant in time.
226. If a ball is thrown vertically upwards and reaches its highest point where its velocity is 0 m/s, what is its instantaneous velocity at that point?
ⓐ. 0 m/s
ⓑ. Maximum velocity achieved
ⓒ. Average velocity during upward motion
ⓓ. Instantaneous velocity at its highest point
Correct Answer: 0 m/s
Explanation: At the highest point of its motion, the ball momentarily stops before descending. Therefore, its instantaneous velocity at that point is 0 m/s.
227. How is instantaneous velocity different from average velocity?
ⓐ. Instantaneous velocity is always greater than average velocity
ⓑ. Instantaneous velocity includes direction, while average velocity does not
ⓒ. Average velocity is calculated over a long period, while instantaneous velocity is at a specific moment
ⓓ. Average velocity is always constant, while instantaneous velocity varies
Correct Answer: Average velocity is calculated over a long period, while instantaneous velocity is at a specific moment
Explanation: Average velocity is the total displacement divided by the total time taken, whereas instantaneous velocity is the velocity at a particular instant.
228. If a cyclist covers 50 meters in 10 seconds, how can you find their instantaneous velocity?
ⓐ. By calculating the average velocity
ⓑ. By dividing total displacement by total time
ⓒ. By finding the slope of the curve on a position-time graph
ⓓ. By dividing total distance by total time
Correct Answer: By finding the slope of the curve on a position-time graph
Explanation: Instantaneous velocity from a position-time graph is found by determining the slope of the curve at the desired point, representing the velocity at that specific time.
229. Which quantity is essential for determining instantaneous velocity from a velocity-time graph?
ⓐ. Slope of the tangent to the curve
ⓑ. Area under the curve
ⓒ. Total displacement
ⓓ. Average velocity
Correct Answer: Slope of the tangent to the curve
Explanation: Instantaneous velocity from a velocity-time graph is determined by finding the slope of the tangent to the curve at the desired point, indicating the rate of change of velocity at that instant.
230. If a car accelerates uniformly from rest and its velocity reaches 20 m/s after 5 seconds, what is its instantaneous velocity at that moment?
ⓐ. 0 m/s
ⓑ. 10 m/s
ⓒ. 15 m/s
ⓓ. 20 m/s
Correct Answer: 20 m/s
Explanation: Instantaneous velocity at any moment can be found by determining the velocity at that specific time instant.
231. What is acceleration defined as?
ⓐ. The rate of change of velocity
ⓑ. The rate of change of displacement
ⓒ. The rate of change of speed
ⓓ. The rate of change of time
Correct Answer: The rate of change of velocity
Explanation: Acceleration is defined as the rate of change of velocity with respect to time.
232. How is acceleration calculated if velocity changes uniformly?
ⓐ. By dividing total displacement by total time
ⓑ. By finding the area under the velocity-time graph
ⓒ. By dividing change in velocity by total time
ⓓ. By subtracting initial velocity from final velocity
Correct Answer: By dividing change in velocity by total time
Explanation: Acceleration can be calculated by dividing the change in velocity (final velocity – initial velocity) by the total time taken.
233. If an object moves in a straight line and its velocity changes from 10 m/s to 30 m/s in 5 seconds, what is its acceleration?
ⓐ. 4 m/s²
ⓑ. 6 m/s²
ⓒ. 8 m/s²
ⓓ. 10 m/s²
Correct Answer: 6 m/s²
Explanation: Acceleration = (Change in velocity) / (Time taken) = (30 m/s – 10 m/s) / 5 s = 20 m/s / 5 s = 6 m/s².
234. Which physical quantity does acceleration measure?
ⓐ. Distance covered
ⓑ. Speed
ⓒ. Rate of change of velocity
ⓓ. Time taken
Correct Answer: Rate of change of velocity
Explanation: Acceleration measures how quickly the velocity of an object changes over time.
235. What does a negative acceleration indicate?
ⓐ. Increase in velocity
ⓑ. Decrease in velocity
ⓒ. Constant velocity
ⓓ. No velocity
Correct Answer: Decrease in velocity
Explanation: Negative acceleration (deceleration) indicates a decrease in velocity over time.
236. In which scenario does acceleration occur?
ⓐ. A stationary object
ⓑ. An object moving at a constant speed
ⓒ. An object changing direction
ⓓ. An object with constant velocity
Correct Answer: An object changing direction
Explanation: Acceleration occurs when an object changes its velocity, either by speeding up, slowing down, or changing direction.
237. If a car’s velocity changes from 20 m/s to 30 m/s in 4 seconds, what is its acceleration?
ⓐ. 2.5 m/s²
ⓑ. 2.0 m/s²
ⓒ. 2.25 m/s²
ⓓ. 5.0 m/s²
Correct Answer: 2.5 m/s²
Explanation: Acceleration = (Change in velocity) / (Time taken) = (30 m/s – 20 m/s) / 4 s = 10 m/s / 4 s = 2.5 m/s².
238. What is the acceleration of a car that decelerates uniformly from 30 m/s to 10 m/s in 5 seconds?
ⓐ. 4 m/s²
ⓑ. 5 m/s²
ⓒ. -4 m/s²
ⓓ. -5 m/s²
Correct Answer: -4 m/s²
Explanation: Acceleration = (Change in velocity) / (Time taken) = (10 m/s – 30 m/s) / 5 s = -20 m/s / 5 s = -4 m/s². Since it is deceleration, the acceleration is negative.
239. Which term describes the rate at which velocity changes?
ⓐ. Speed
ⓑ. Distance
ⓒ. Acceleration
ⓓ. Time
Correct Answer: Acceleration
Explanation: Acceleration is the rate at which an object’s velocity changes over time.
240. If a rocket accelerates uniformly from rest at 20 m/s², what is its velocity after 10 seconds?
ⓐ. 10 m/s
ⓑ. 100 m/s
ⓒ. 200 m/s
ⓓ. 300 m/s
Correct Answer: 200 m/s
Explanation: Velocity = Acceleration × Time = 20 m/s² × 10 s = 200 m/s.
241. What does positive acceleration indicate?
ⓐ. Increase in velocity
ⓑ. Decrease in velocity
ⓒ. Constant velocity
ⓓ. No velocity change
Correct Answer: Increase in velocity
Explanation: Positive acceleration indicates that the velocity of an object is increasing over time.
242. If a car is speeding up uniformly from 10 m/s to 30 m/s in 5 seconds, what type of acceleration does it have?
ⓐ. Positive acceleration
ⓑ. Negative acceleration
ⓒ. Zero acceleration
ⓓ. Constant acceleration
Correct Answer: Positive acceleration
Explanation: When the velocity of an object increases over time, it experiences positive acceleration.
243. What does negative acceleration represent?
ⓐ. Increase in velocity
ⓑ. Decrease in velocity
ⓒ. Constant velocity
ⓓ. No velocity change
Correct Answer: Decrease in velocity
Explanation: Negative acceleration (deceleration) indicates that the velocity of an object is decreasing over time.
244. If a car slows down uniformly from 20 m/s to 10 m/s in 4 seconds, what type of acceleration does it have?
ⓐ. Positive acceleration
ⓑ. Negative acceleration
ⓒ. Zero acceleration
ⓓ. Constant acceleration
Correct Answer: Negative acceleration
Explanation: When the velocity of an object decreases over time, it experiences negative acceleration.
245. Which scenario represents zero acceleration?
ⓐ. A car accelerating from rest
ⓑ. A car moving at a constant speed
ⓒ. A car decelerating uniformly
ⓓ. A car changing direction
Correct Answer: A car moving at a constant speed
Explanation: Zero acceleration occurs when the velocity of an object remains constant over time.
246. In which situation is the acceleration negative?
ⓐ. A ball rolling downhill
ⓑ. A car accelerating from rest
ⓒ. A plane taking off
ⓓ. A rocket in space
Correct Answer: A ball rolling downhill
Explanation: Acceleration is negative when the object is slowing down or decelerating, such as a ball rolling downhill against gravity.
247. If an object’s velocity changes from -20 m/s to -10 m/s in 2 seconds, what type of acceleration does it have?
ⓐ. Positive acceleration
ⓑ. Negative acceleration
ⓒ. Zero acceleration
ⓓ. Constant acceleration
Correct Answer: Positive acceleration
Explanation: When the velocity of an object increases, even if it is negative, over time, it experiences positive acceleration.
248. Which term describes a situation where acceleration is positive?
ⓐ. Increasing velocity
ⓑ. Decreasing velocity
ⓒ. Constant velocity
ⓓ. No velocity change
Correct Answer: Increasing velocity
Explanation: Positive acceleration describes a situation where the velocity of an object is increasing over time.
249. What is the acceleration of an object that maintains a constant velocity of 10 m/s?
ⓐ. 0 m/s²
ⓑ. 5 m/s²
ⓒ. 10 m/s²
ⓓ. -10 m/s²
Correct Answer: 0 m/s²
Explanation: Constant velocity means there is no change in velocity over time, hence zero acceleration.
250. If a rocket is launched into space and its velocity remains constant after leaving Earth’s atmosphere, what type of acceleration does it have?
ⓐ. Positive acceleration
ⓑ. Negative acceleration
ⓒ. Zero acceleration
ⓓ. Variable acceleration
Correct Answer: Zero acceleration
Explanation: Constant velocity (including zero velocity change) means there is no acceleration.
251. What does average acceleration measure?
ⓐ. Rate of change of velocity over a short interval
ⓑ. Rate of change of velocity over a long interval
ⓒ. Rate of change of displacement over a short interval
ⓓ. Rate of change of displacement over a long interval
Correct Answer: Rate of change of velocity over a long interval
Explanation: Average acceleration is calculated over a longer interval of time, representing the overall change in velocity.
252. How is average acceleration calculated if an object’s velocity changes uniformly?
ⓐ. By dividing total displacement by total time
ⓑ. By finding the area under the velocity-time graph
ⓒ. By dividing change in velocity by total time
ⓓ. By subtracting initial velocity from final velocity
Correct Answer: By dividing change in velocity by total time
Explanation: Average acceleration can be calculated by dividing the change in velocity by the total time taken.
253. If a car accelerates uniformly from 10 m/s to 30 m/s in 5 seconds, what is its average acceleration?
ⓐ. 2 m/s²
ⓑ. 4 m/s²
ⓒ. 8 m/s²
ⓓ. 10 m/s²
Correct Answer: 4 m/s²
Explanation: Average acceleration = (Change in velocity) / (Time taken) = (30 m/s – 10 m/s) / 5 s = 20 m/s / 5 s = 4 m/s².
254. What does instantaneous acceleration represent?
ⓐ. Rate of change of velocity over a short interval
ⓑ. Rate of change of velocity over a long interval
ⓒ. Rate of change of displacement over a short interval
ⓓ. Rate of change of displacement over a long interval
Correct Answer: Rate of change of velocity over a short interval
Explanation: Instantaneous acceleration represents the rate of change of velocity at an exact moment or instant in time.
255. How is instantaneous acceleration determined from a velocity-time graph?
ⓐ. By finding the slope of the tangent to the curve
ⓑ. By finding the area under the curve
ⓒ. By dividing total displacement by total time
ⓓ. By subtracting initial velocity from final velocity
Correct Answer: By finding the slope of the tangent to the curve
Explanation: Instantaneous acceleration from a velocity-time graph is determined by finding the slope of the tangent to the curve at the desired point.
256. If a car’s velocity changes from 20 m/s to 30 m/s in 4 seconds, what is its average acceleration?
ⓐ. 2.5 m/s²
ⓑ. 2.0 m/s²
ⓒ. 2.25 m/s²
ⓓ. 5.0 m/s²
Correct Answer: 2.5 m/s²
Explanation: Average acceleration = (Change in velocity) / (Time taken) = (30 m/s – 20 m/s) / 4 s = 10 m/s / 4 s = 2.5 m/s².
257. In which situation is average acceleration zero?
ⓐ. A car speeding up uniformly
ⓑ. A car maintaining constant velocity
ⓒ. A car decelerating uniformly
ⓓ. A car changing direction
Correct Answer: A car maintaining constant velocity
Explanation: Average acceleration is zero when an object’s velocity remains constant over time.
258. What is the average acceleration of an object that slows down uniformly from 30 m/s to 10 m/s in 5 seconds?
ⓐ. 4 m/s²
ⓑ. 5 m/s²
ⓒ. -4 m/s²
ⓓ. -5 m/s²
Correct Answer: -4 m/s²
Explanation: Average acceleration = (Change in velocity) / (Time taken) = (10 m/s – 30 m/s) / 5 s = -20 m/s / 5 s = -4 m/s².
259. If a rocket accelerates uniformly from rest at 20 m/s², what is its velocity after 10 seconds?
ⓐ. 10 m/s
ⓑ. 100 m/s
ⓒ. 200 m/s
ⓓ. 300 m/s
Correct Answer: 200 m/s
Explanation: Velocity = Acceleration × Time = 20 m/s² × 10 s = 200 m/s.
260. What is the instantaneous acceleration of an object that maintains a constant velocity of 10 m/s?
ⓐ. 0 m/s²
ⓑ. 5 m/s²
ⓒ. 10 m/s²
ⓓ. -10 m/s²
Correct Answer: 0 m/s²
Explanation: Instantaneous acceleration is zero when an object maintains a constant velocity, indicating no change in velocity over time.
261. How is acceleration represented on a velocity-time graph?
ⓐ. Slope of the tangent to the curve
ⓑ. Area under the curve
ⓒ. Slope of the chord between two points
ⓓ. Area above the curve
Correct Answer: Slope of the tangent to the curve
Explanation: Acceleration on a velocity-time graph is represented by the slope of the tangent to the curve at any point, indicating the rate of change of velocity.
262. What does a straight line on a velocity-time graph indicate about acceleration?
ⓐ. Constant acceleration
ⓑ. Zero acceleration
ⓒ. Negative acceleration
ⓓ. Non-uniform acceleration
Correct Answer: Constant acceleration
Explanation: A straight line on a velocity-time graph indicates constant acceleration, where velocity changes uniformly over time.
263. If a velocity-time graph is horizontal, what does it imply about acceleration?
ⓐ. Zero acceleration
ⓑ. Constant acceleration
ⓒ. Negative acceleration
ⓓ. Non-uniform acceleration
Correct Answer: Zero acceleration
Explanation: A horizontal velocity-time graph indicates zero acceleration, meaning the velocity remains constant over time.
264. How is acceleration related to the steepness of a velocity-time graph?
ⓐ. Greater steepness indicates greater acceleration
ⓑ. Lesser steepness indicates greater acceleration
ⓒ. Steepness does not relate to acceleration
ⓓ. Steepness indicates constant acceleration
Correct Answer: Greater steepness indicates greater acceleration
Explanation: The steepness (slope) of a velocity-time graph indicates the magnitude of acceleration. Greater steepness implies greater acceleration.
265. What does a downward sloping line on a velocity-time graph represent about acceleration?
ⓐ. Increasing acceleration
ⓑ. Decreasing acceleration
ⓒ. Negative acceleration
ⓓ. Positive acceleration
Correct Answer: Negative acceleration
Explanation: A downward sloping line on a velocity-time graph indicates negative acceleration (deceleration), where velocity decreases over time.
266. If a velocity-time graph curves upwards, what does it suggest about acceleration?
ⓐ. Increasing acceleration
ⓑ. Decreasing acceleration
ⓒ. Negative acceleration
ⓓ. Uniform acceleration
Correct Answer: Increasing acceleration
Explanation: An upward curve on a velocity-time graph suggests increasing acceleration, where velocity increases at an increasing rate.
267. How is acceleration represented on a displacement-time graph?
ⓐ. Slope of the tangent to the curve
ⓑ. Area under the curve
ⓒ. Slope of the chord between two points
ⓓ. Area above the curve
Correct Answer: Slope of the chord between two points
Explanation: Acceleration on a displacement-time graph is represented by the slope of the chord between two points, indicating the change in velocity over time.
268. What does a curved line on a velocity-time graph indicate about acceleration?
ⓐ. Constant acceleration
ⓑ. Variable acceleration
ⓒ. Negative acceleration
ⓓ. Zero acceleration
Correct Answer: Variable acceleration
Explanation: A curved line on a velocity-time graph indicates variable acceleration, where the rate of change of velocity is not constant over time.
269. If a velocity-time graph is vertical, what does it imply about acceleration?
ⓐ. Zero acceleration
ⓑ. Infinite acceleration
ⓒ. Constant acceleration
ⓓ. Non-uniform acceleration
Correct Answer: Infinite acceleration
Explanation: A vertical velocity-time graph implies infinite acceleration, where velocity changes instantaneously over time.
270. In which scenario does a velocity-time graph show negative acceleration?
ⓐ. A car accelerating uniformly
ⓑ. A car moving with constant velocity
ⓒ. A car decelerating uniformly
ⓓ. A car changing direction
Correct Answer: A car decelerating uniformly
Explanation: A velocity-time graph shows negative acceleration (deceleration) when the slope of the graph is downward, indicating a decrease in velocity over time.
271. How is acceleration related to velocity in terms of direction?
ⓐ. Acceleration is always in the same direction as velocity
ⓑ. Acceleration is always opposite to velocity
ⓒ. Acceleration can be in the same or opposite direction as velocity
ⓓ. Acceleration has no relation to the direction of velocity
Correct Answer: Acceleration can be in the same or opposite direction as velocity
Explanation: Acceleration can be in the same direction as velocity (for speeding up) or opposite direction (for slowing down).
272. When does an object have maximum positive acceleration?
ⓐ. When velocity is increasing
ⓑ. When velocity is decreasing
ⓒ. When velocity is constant
ⓓ. When there is no velocity
Correct Answer: When velocity is increasing
Explanation: Maximum positive acceleration occurs when the velocity of an object is increasing at the fastest rate.
273. What is the acceleration of an object moving with constant velocity?
ⓐ. Zero
ⓑ. Positive
ⓒ. Negative
ⓓ. Variable
Correct Answer: Zero
Explanation: Acceleration is zero when the velocity of an object remains constant.
274. If acceleration and velocity have opposite signs, what is happening to the object?
ⓐ. It is speeding up
ⓑ. It is slowing down
ⓒ. It is moving with constant velocity
ⓓ. It is not moving
Correct Answer: It is slowing down
Explanation: When acceleration and velocity have opposite signs, the object is decelerating or slowing down.
275. What is the relationship between velocity and acceleration for an object moving in a straight line?
ⓐ. Velocity is directly proportional to acceleration
ⓑ. Velocity is inversely proportional to acceleration
ⓒ. Velocity and acceleration are independent
ⓓ. Velocity and acceleration are always equal
Correct Answer: Velocity and acceleration are independent
Explanation: Velocity and acceleration are independent quantities. Acceleration affects the change in velocity but does not determine the velocity directly.
276. If an object has a positive velocity and negative acceleration, what is happening to its speed?
ⓐ. Speed is increasing
ⓑ. Speed is decreasing
ⓒ. Speed remains constant
ⓓ. Speed is zero
Correct Answer: Speed is decreasing
Explanation: Negative acceleration with positive velocity indicates the object is slowing down.
277. When does an object have maximum negative acceleration?
ⓐ. When velocity is increasing
ⓑ. When velocity is decreasing
ⓒ. When velocity is constant
ⓓ. When there is no velocity
Correct Answer: When velocity is decreasing
Explanation: Maximum negative acceleration occurs when the velocity of an object is decreasing at the fastest rate.
278. What happens to an object with zero acceleration?
ⓐ. Its velocity remains constant
ⓑ. Its velocity changes randomly
ⓒ. Its velocity changes direction
ⓓ. Its velocity becomes zero
Correct Answer: Its velocity remains constant
Explanation: Zero acceleration means there is no change in velocity over time.
279. If an object is moving with constant acceleration, what happens to its velocity?
ⓐ. It remains constant
ⓑ. It decreases uniformly
ⓒ. It increases uniformly
ⓓ. It changes direction
Correct Answer: It increases uniformly
Explanation: Constant acceleration means the velocity of the object changes uniformly over time.
280. What does a negative velocity with positive acceleration indicate about an object’s motion?
ⓐ. Object is moving in the negative direction and slowing down
ⓑ. Object is moving in the negative direction and speeding up
ⓒ. Object is moving in the positive direction and slowing down
ⓓ. Object is moving in the positive direction and speeding up
Correct Answer: Object is moving in the negative direction and speeding up
Explanation: Negative velocity with positive acceleration indicates the object is moving in the negative direction and its speed is increasing.
281. Which kinematic equation relates displacement, initial velocity, acceleration, and time?
ⓐ. \( s = ut + \frac{1}{2}at^2 \)
ⓑ. \( v = u + at \)
ⓒ. \( v^2 = u^2 + 2as \)
ⓓ. \( s = \frac{1}{2}(u + v)t \)
Correct Answer: \( s = ut + \frac{1}{2}at^2 \)
Explanation: This equation relates displacement \( s \), initial velocity \( u \), acceleration \( a \), and time \( t \).
282. What is the kinematic equation for final velocity \( v \) in terms of initial velocity \( u \), acceleration \( a \), and displacement \( s \)?
ⓐ. \( v = u + at \)
ⓑ. \( v = u + \frac{1}{2}at^2 \)
ⓒ. \( v^2 = u^2 + 2as \)
ⓓ. \( v = \frac{1}{2}(u + v)t \)
Correct Answer: \( v^2 = u^2 + 2as \)
Explanation: This equation relates final velocity \( v \), initial velocity \( u \), acceleration \( a \), and displacement \( s \).
283. Which kinematic equation can be used to find displacement \( s \) when initial velocity \( u \), final velocity \( v \), and time \( t \) are known?
ⓐ. \( s = ut + \frac{1}{2}at^2 \)
ⓑ. \( v = u + at \)
ⓒ. \( v^2 = u^2 + 2as \)
ⓓ. \( s = \frac{1}{2}(u + v)t \)
Correct Answer: \( s = \frac{1}{2}(u + v)t \)
Explanation: This equation calculates displacement \( s \) when initial velocity \( u \), final velocity \( v \), and time \( t \) are given.
284. Which kinematic equation represents the relationship between final velocity \( v \), initial velocity \( u \), acceleration \( a \), and time \( t \)?
ⓐ. \( v = u + at \)
ⓑ. \( v = u + \frac{1}{2}at^2 \)
ⓒ. \( v^2 = u^2 + 2as \)
ⓓ. \( s = \frac{1}{2}(u + v)t \)
Correct Answer: \( v = u + at \)
Explanation: This equation gives the final velocity \( v \) in terms of initial velocity \( u \), acceleration \( a \), and time \( t \).
285. What is the kinematic equation that relates displacement \( s \), initial velocity \( u \), final velocity \( v \), and acceleration \( a \)?
ⓐ. \( s = ut + \frac{1}{2}at^2 \)
ⓑ. \( v = u + at \)
ⓒ. \( v^2 = u^2 + 2as \)
ⓓ. \( s = \frac{1}{2}(u + v)t \)
Correct Answer: \( v^2 = u^2 + 2as \)
Explanation: This equation relates displacement \( s \), initial velocity \( u \), final velocity \( v \), and acceleration \( a \).
286. Which kinematic equation can be derived by eliminating time \( t \) from the equations \( v = u + at \) and \( s = ut + \frac{1}{2}at^2 \)?
ⓐ. \( v^2 = u^2 + 2as \)
ⓑ. \( s = \frac{1}{2}(u + v)t \)
ⓒ. \( v = u + at \)
ⓓ. \( s = ut + \frac{1}{2}at^2 \)
Correct Answer: \( v^2 = u^2 + 2as \)
Explanation: This equation is derived by eliminating time \( t \) from the equations \( v = u + at \) and \( s = ut + \frac{1}{2}at^2 \).
287. Which kinematic equation involves the average velocity \( \bar{v} \), initial velocity \( u \), final velocity \( v \), and displacement \( s \)?
ⓐ. \( \bar{v} = \frac{u + v}{2} \)
ⓑ. \( v = u + at \)
ⓒ. \( v^2 = u^2 + 2as \)
ⓓ. \( s = ut + \frac{1}{2}at^2 \)
Correct Answer: \( \bar{v} = \frac{u + v}{2} \)
Explanation: This equation represents the average velocity \( \bar{v} \) as the average of initial velocity \( u \) and final velocity \( v \).
288. What is the kinematic equation that connects displacement \( s \), average velocity \( \bar{v} \), and time \( t \)?
ⓐ. \( s = ut + \frac{1}{2}at^2 \)
ⓑ. \( v = u + at \)
ⓒ. \( \bar{v} = \frac{u + v}{2} \)
ⓓ. \( s = \bar{v} \cdot t \)
Correct Answer: \( s = \bar{v} \cdot t \)
Explanation: Displacement \( s \) can be found by multiplying average velocity \( \bar{v} \) and time \( t \).
289. Which kinematic equation represents the relationship between displacement \( s \), initial velocity \( u \), acceleration \( a \), and time \( t \)?
ⓐ. \( s = ut + \frac{1}{2}at^2 \)
ⓑ. \( v = u + at \)
ⓒ. \( v^2 = u^2 + 2as \)
ⓓ. \( s = \frac{1}{2}(u + v)t \)
Correct Answer: \( s = ut + \frac{1}{2}at^2 \)
Explanation: This equation calculates displacement \( s \) using initial velocity \( u \), acceleration \( a \), and time \( t \).
290. If an object starts from rest and accelerates uniformly, which kinematic equation can be used to find its displacement after time \( t \)?
ⓐ. \( s = ut + \frac{1}{2}at^2 \)
ⓑ. \( v = u + at \)
ⓒ. \( v^2 = u^2 + 2as \)
ⓓ. \( s = \frac{1}{2}(u + v)t \)
Correct Answer: \( s = ut + \frac{1}{2}at^2 \)
Explanation: When an object starts from rest (initial velocity \( u = 0 \)) and accelerates uniformly, displacement \( s \) after time \( t \) can be found using this equation.
291. What does the equation \( v = u + at \) represent?
ⓐ. Relationship between final velocity, initial velocity, acceleration, and time
ⓑ. Relationship between displacement, initial velocity, acceleration, and time
ⓒ. Relationship between average velocity, initial velocity, acceleration, and time
ⓓ. Relationship between force, mass, acceleration, and time
Correct Answer: Relationship between final velocity, initial velocity, acceleration, and time
Explanation: This equation relates the final velocity \( v \), initial velocity \( u \), acceleration \( a \), and time \( t \).
292. If an object starts from rest, what is its initial velocity \( u \) in terms of final velocity \( v \), acceleration \( a \), and time \( t \)?
ⓐ. \( u = v – at \)
ⓑ. \( u = v + at \)
ⓒ. \( u = \frac{v}{t} – a \)
ⓓ. \( u = \frac{v}{t} + a \)
Correct Answer: \( u = v – at \)
Explanation: When an object starts from rest (\( u = 0 \)), its initial velocity \( u \) can be found using this equation.
293. What does \( v \) stand for in the equation \( v = u + at \)?
ⓐ. Average velocity
ⓑ. Final velocity
ⓒ. Instantaneous velocity
ⓓ. Initial velocity
Correct Answer: Final velocity
Explanation: \( v \) represents the final velocity in the equation \( v = u + at \).
294. In the equation \( v = u + at \), what does \( a \) represent?
ⓐ. Average velocity
ⓑ. Acceleration
ⓒ. Displacement
ⓓ. Time
Correct Answer: Acceleration
Explanation: \( a \) represents acceleration in the equation \( v = u + at \).
295. If an object has a negative initial velocity \( u \) and positive acceleration \( a \), what happens to its final velocity \( v \)?
ⓐ. \( v \) is negative
ⓑ. \( v \) is positive
ⓒ. \( v \) remains zero
ⓓ. \( v \) depends on time
Correct Answer: \( v \) is positive
Explanation: Positive acceleration with negative initial velocity means the object is speeding up, hence \( v \) will be positive.
296. Which quantity can be calculated directly from the equation \( v = u + at \)?
ⓐ. Displacement \( s \)
ⓑ. Time \( t \)
ⓒ. Acceleration \( a \)
ⓓ. Final velocity \( v \)
Correct Answer: Final velocity \( v \)
Explanation: The equation \( v = u + at \) directly calculates the final velocity \( v \) of an object.
297. What happens to an object’s final velocity \( v \) if it starts from rest (\( u = 0 \)) and accelerates uniformly?
ⓐ. \( v \) remains zero
ⓑ. \( v \) decreases
ⓒ. \( v \) increases
ⓓ. \( v \) depends on acceleration
Correct Answer: \( v \) increases
Explanation: Starting from rest (\( u = 0 \)) and accelerating uniformly means the final velocity \( v \) increases over time.
298. What is the equation for initial velocity \( u \) derived from \( v = u + at \)?
ⓐ. \( u = v – at \)
ⓑ. \( u = v + at \)
ⓒ. \( u = \frac{v}{t} – a \)
ⓓ. \( u = \frac{v}{t} + a \)
Correct Answer: \( u = v – at \)
Explanation: Rearranging \( v = u + at \) gives \( u = v – at \) when solving for initial velocity \( u \).
299. If an object has a positive initial velocity \( u \) and negative acceleration \( a \), what happens to its final velocity \( v \)?
ⓐ. \( v \) is negative
ⓑ. \( v \) is positive
ⓒ. \( v \) remains zero
ⓓ. \( v \) depends on time
Correct Answer: \( v \) is negative
Explanation: Negative acceleration with positive initial velocity means the object is slowing down, hence \( v \) will be negative.
300. Which kinematic quantity remains constant if an object moves with uniform acceleration?
ⓐ. Displacement \( s \)
ⓑ. Time \( t \)
ⓒ. Initial velocity \( u \)
ⓓ. Acceleration \( a \)
Correct Answer: Acceleration \( a \)
Explanation: If an object moves with uniform acceleration, the acceleration \( a \) remains constant throughout its motion.
You are now on Class 11 Physics MCQs – Chapter 3: Motion in a Straight Line (Part 3). This collection of questions is created to match the NCERT/CBSE syllabus and is extremely helpful for students preparing for board exams, JEE, NEET, and other entrance exams. The entire chapter features 350 multiple-choice questions with clear explanations, divided into 4 systematic parts. In this third section, you will practice another 100 MCQs with answers, focusing on application-based and tricky concepts from Motion in a Straight Line.
- 👉 This is Part 3 — 100 advanced-level MCQs with solutions.
- 👉 Great for competitive exam aspirants who want to improve problem-solving skills.
- 👉 You can easily browse other classes, subjects, and Physics chapters through the navigation bar above.
- 👉 Attempt all 4 parts for complete coverage of 350 MCQs.