Class 11 Physics MCQs | Chapter 15: Waves – Part 1 (Most Expected Questions for Exams)

Explanation: A wave is a disturbance that transfers energy from one point to another without the transport of matter. The particles of the medium only oscillate about their mean positions. Option A is incorrect because particles do not move permanently. Option C is irrelevant, and Option D is wrong because matter is not transferred.

Explanation: Sound is a mechanical wave that requires a medium to propagate. Light, X-rays, and gamma rays are electromagnetic waves, which do not require a medium. Mechanical waves involve particle oscillations, while electromagnetic waves involve oscillations of electric and magnetic fields.

Explanation: For mechanical waves, a disturbance must be produced in a medium. The medium must have inertia (mass) and elasticity (restoring force) to propagate the disturbance. Without these, wave motion cannot sustain.

Explanation: In air, sound waves propagate as longitudinal waves where particles oscillate parallel to the direction of propagation. Transverse waves involve perpendicular oscillations (like in strings). Electromagnetic waves are not mechanical, and surface waves are different phenomena (e.g., water waves).

Explanation: The speed of sound in a medium is given by $v = \sqrt{\frac{E}{\rho}}$, where $E$ is the elastic modulus and $\rho$ is density. Temperature and pressure affect the speed indirectly by changing these properties, but the fundamental dependence is on elasticity and density.

Explanation: On a stretched string, displacement of particles is perpendicular to wave propagation, making it transverse. Sound in air and P-waves are longitudinal. Light is transverse but not mechanical (it is electromagnetic).

Explanation: This distinction is fundamental: longitudinal = parallel oscillations, transverse = perpendicular oscillations. Options A and B are reversed. Option D is incorrect because it states both are perpendicular.

Explanation: Waves have measurable properties such as wavelength (distance between crests), frequency (oscillations per second), and amplitude (maximum displacement). Mass is not a property of the wave itself but of the medium’s particles.

Explanation: The basic wave equation is $v = f \lambda$. This means the speed of a wave is the product of its frequency and wavelength. Options B and D are incorrect because they divide, while C has meaningless subtraction.

Explanation: Using $v = f \lambda$: $v = 200 \times 1.7 = 340 \, \text{m/s}$. This value matches the approximate speed of sound in air. Option A is too small, option B is less than correct, and option D is too large.

Explanation: Waves are defined as disturbances that propagate through a medium or space, transferring energy without the permanent transfer of matter. The medium’s particles oscillate about equilibrium, but do not migrate with the wave. Option A and C confuse matter with energy transfer, while D is limited to vibrations, not wave propagation.

Explanation: Waves have measurable properties such as amplitude (maximum displacement), wavelength (distance between two crests/troughs), and frequency (number of oscillations per second). Mass is not an inherent property of a wave but of the medium. Thus, it is not a wave characteristic.

Explanation: Mechanical waves propagate in media due to the restoring force of elasticity (to bring displaced particles back) and inertia (resistance to change). Gravitational and nuclear forces are irrelevant here, while electromagnetic forces govern electromagnetic waves.

Explanation: When a wave crosses a boundary, its speed and wavelength change depending on the medium, but frequency remains unchanged because it is determined by the source of the wave. Direction may also change due to refraction.

Explanation: In sound waves, larger amplitude means louder sound; in light waves, larger amplitude corresponds to higher intensity or brightness. Frequency determines pitch or color, not loudness/brightness. Wavelength and speed describe propagation, not intensity.

Explanation: A progressive wave carries energy as it propagates through a medium, with particles oscillating about equilibrium. A standing wave (Option C) does not transfer energy across the medium. Options A and D are incorrect descriptions.

Explanation: In sound, pitch is set by frequency (higher frequency = higher pitch). In light, color is determined by frequency (or equivalently wavelength in vacuum). Amplitude affects intensity, not pitch or color. Speed is medium-dependent and does not change the nature of sound or light.

Explanation: Frequency is defined as the number of oscillations per unit time, usually measured in Hertz (Hz). Wavelength is spatial, amplitude measures displacement, and speed is the rate at which wavefronts travel.

Explanation: Frequency $f = \frac{1}{T}$. Here, $f = \frac{1}{0.02} = 50 \, \text{Hz}$. Thus, the wave completes 50 oscillations per second. The other options are incorrect calculations.

Explanation: In waves, particles vibrate around their equilibrium positions and transfer energy to adjacent particles. This chain of oscillations moves energy forward while the medium’s particles themselves do not migrate. Option A and D are misconceptions; Option C contradicts the idea of propagation.

Explanation: Mechanical waves require a material medium for propagation, and sound waves are classic examples. Radio waves, X-rays, and infrared radiation are electromagnetic waves, which do not require a medium.

Explanation: Mechanical waves (e.g., sound, water waves) need a material medium for propagation. Electromagnetic waves (light, radio waves) can propagate through vacuum because they consist of oscillating electric and magnetic fields.

Explanation: Diffraction is the bending of waves around obstacles or openings and occurs for all types of waves, including sound (mechanical) and light (electromagnetic). Polarization is specific to transverse waves like light. Beats arise from mechanical wave interference in sound. Elasticity is a medium property, not wave behavior.

Explanation: Visible light is part of the electromagnetic spectrum. Water waves and seismic S-waves are mechanical waves, and sound in air is a longitudinal mechanical wave.

Explanation: The essential role of waves is energy transfer. Mechanical waves transfer energy via oscillations of particles, while electromagnetic waves transfer energy through oscillations of electric and magnetic fields. Only mechanical waves need a medium.

Explanation: All electromagnetic waves, including light, travel at the speed of light in vacuum: $c = 3 \times 10^8 \, \text{m/s}$. Sound and mechanical waves are much slower. Mechanical wave speed depends on medium’s elasticity and density, not electromagnetic waves.

Explanation: Seismic P-waves are mechanical waves traveling through Earth. Microwaves, gamma rays, and ultraviolet rays belong to the electromagnetic spectrum.

Explanation: Transverse mechanical waves depend on oscillations of medium particles perpendicular to propagation. Electromagnetic waves rely on oscillations of electric and magnetic fields. Options A and B are true for both. Option D is true only for EM waves.

Explanation: Sound in air propagates via compressions and rarefactions, making it a longitudinal mechanical wave. Electromagnetic classification is incorrect, and transverse option applies to light or water ripples, not sound.

Explanation: Electromagnetic waves consist of time-varying electric and magnetic fields, each inducing the other, allowing self-propagation even in vacuum. Mechanical waves cannot do this as they need a medium.

Explanation: Wavelength is calculated using $\lambda = \frac{v}{f}$. Substituting $v = 340 \, \text{m/s}, f = 500 \, \text{Hz}$, we get $\lambda = \frac{340}{500} = 0.68 \, \text{m}$.

Explanation: Speed of wave $v = f \lambda = 4 \times 2 = 8 \, \text{m/s}$. Therefore, the correct speed is 8 m/s.

Explanation: Using $v = f \lambda$, with $v = c = 3 \times 10^8 \, \text{m/s}$, $\lambda = \frac{3 \times 10^8}{5 \times 10^{14}} = 6 \times 10^{-7} \, \text{m}$. This corresponds to visible light.

Explanation: Frequency is given by $f = \frac{v}{\lambda} = \frac{6000}{150} = 40 \, \text{Hz}$.

Explanation: Wavelength $\lambda = \frac{c}{f} = \frac{3 \times 10^8}{100 \times 10^6} = 3 \, \text{m}$.

Explanation: $\lambda = \frac{v}{f} = \frac{20}{50} = 0.4 \, \text{m}$.

Explanation: Frequency $f = \frac{v}{\lambda} = \frac{340}{0.85} = 400 \, \text{Hz}$.

Explanation: The speed of electromagnetic waves in vacuum is constant at $c = 3 \times 10^8 \, \text{m/s}$. Doubling frequency halves wavelength, but speed remains unchanged.

Explanation: General form is $y = A \sin(\omega t – kx)$. Here $k = 0.2\pi$. Since $k = \frac{2\pi}{\lambda}$, we get $\lambda = \frac{2\pi}{0.2\pi} = 10 \, \text{m}$.

Explanation: $f = \frac{c}{\lambda} = \frac{3 \times 10^8}{0.03} = 1 \times 10^{10} \, \text{Hz}$. This lies in the microwave region.

Explanation: Amplitude is the maximum displacement of the particles of the medium from their mean positions due to wave motion. It indicates the energy carried by the wave—greater amplitude means greater energy. Frequency is the number of oscillations per unit time, wavelength is the distance between two successive crests or troughs, and speed is the rate of propagation of the wave. None of these describe maximum displacement except amplitude.

Explanation: In sound waves, particles oscillate about their mean position. The maximum displacement from equilibrium is called amplitude. It is directly related to loudness. Option A refers to wavelength, option B refers to pressure amplitude (a related concept but not the same), and option D refers to speed of propagation, not amplitude.

Explanation: Frequency is the reciprocal of time period: $f = \frac{1}{T}$. Substituting $T = 0.01 \, \text{s}$, we get $f = \frac{1}{0.01} = 100 \, \text{Hz}$. Thus, the wave makes 100 oscillations every second. This relation is fundamental and helps in converting between frequency and time period.

Explanation: The relation between speed, frequency, and wavelength is $v = f \lambda$. Substituting $f = 60 \, \text{Hz}, \lambda = 5 \, \text{m}$, we get $v = 60 \times 5 = 300 \, \text{m/s}$. Option B is correct. Other values correspond to incorrect multiplication.

Explanation: Beat frequency is given by the difference in frequencies of the two sources: $f_b = |f_1 – f_2|$. Here, $f_b = |250 – 255| = 5 \, \text{Hz}$. This means the sound will fluctuate in loudness 5 times per second. The beat frequency helps in tuning musical instruments.

Explanation: Wavelength is the spatial period of the wave—the distance over which the wave repeats. For transverse waves, it is the distance between crests or troughs. For longitudinal waves, it is the distance between compressions or rarefactions. Time period relates to oscillations, not distance. Wave speed describes rate of travel, not spatial repetition.

Explanation: Using the relation $f = \frac{v}{\lambda}$,

we have $f = \frac{340}{1.7} = 200 \, \text{Hz}$. This frequency lies in the audible range. Option A and B underestimate the ratio, while option D is slightly higher than the exact value.

Explanation: Energy of a wave is proportional to the square of amplitude: $E \propto A^2$. If amplitude doubles, $E$ increases by $2^2 = 4$ times. Frequency and wavelength influence speed but not energy stored in oscillations.

Explanation: General wave equation is $y = A \sin(\omega t – kx)$.

Here, $\omega = 100\pi$.

Since $\omega = 2\pi f$,

we get $f = \frac{\omega}{2\pi} = \frac{100\pi}{2\pi} = 50 \, \text{Hz}$.

This frequency is within the audible range.

Explanation: Wave speed is $v = f \lambda$.

Substituting $f = 20 \, \text{Hz}, \lambda = 2 \, \text{m}$,

we get $v = 20 \times 2 = 40 \, \text{m/s}$.

Amplitude does not affect speed—it only affects energy. Thus the correct answer is 40 m/s.

Explanation: The relation is $v = f \lambda$.

Here, $v = 340 \, \text{m/s}$.

Also, $f = 170 \, \text{Hz}$.

So, $\lambda = \frac{v}{f}$.

$\lambda = \frac{340}{170} $.

$\lambda = 2.0 \, \text{m} $.

Thus the wavelength is 2.0 m.

Explanation: The relation is $v = f \lambda$.

Here, $v = 100 \, \text{m/s}$.

Also, $\lambda = 0.5 \, \text{m}$.

So, $f = \frac{v}{\lambda}$.

$f = \frac{100}{0.5}$.

$f = 200 \, \text{Hz}$.

Thus the frequency is 200 Hz.

Explanation: The relation is $f = \frac{1}{T}$.

Here, $T = 0.02 \, \text{s}$.

So, $f = \frac{1}{0.02}$.

$f = 50 \, \text{Hz}$.

Thus the frequency is 50 Hz.

Explanation: General form: $y = A \sin(\omega t – kx)$.

Here, wave number $k = 0.5\pi$.

Relation is $k = \frac{2\pi}{\lambda}$.

So, $\lambda = \frac{2\pi}{k}$.

$\lambda = \frac{2\pi}{0.5\pi}$.

$\lambda = 4 \, \text{m}$.

Thus the wavelength is 4 m.

Explanation: The relation is $v = f \lambda$.

Here, $v = 60 \, \text{m/s}$.

Also, $f = 15 \, \text{Hz}$.

So, $\lambda = \frac{v}{f}$.

$\lambda = \frac{60}{15}$.

$\lambda = 4 \, \text{m}$.

Thus the wavelength is 4 m.

Explanation: The relation is $v = f \lambda$.

Here, $v = 20 \, \text{m/s}$.

Also, $\lambda = 0.25 \, \text{m}$.

So, $f = \frac{v}{\lambda}$.

$f = \frac{20}{0.25}$.

$f = 80 \, \text{Hz}$.

Thus the frequency is 80 Hz.

Explanation: The relation is $v = f \lambda$.

Here, $f = 440 \, \text{Hz}$.

Also, $\lambda = 0.78 \, \text{m}$.

So, $v = 440 \times 0.78$.

$v = 343.2 \, \text{m/s}$.

Approximating, $v \approx 340 \, \text{m/s}$.

Thus the speed is 340 m/s.

Explanation: First, frequency $f = \frac{1}{T}$.

Here, $T = 0.01 \, \text{s}$.

So, $f = \frac{1}{0.01}$.

$f = 100 \, \text{Hz}$.

Now, $v = f \lambda$.

$v = 100 \times 2$.

$v = 200 \, \text{m/s}$.

Thus the speed is 200 m/s.

Explanation: The relation is $v = f \lambda$.

Here, $v = 1500 \, \text{m/s}$.

Also, $f = 300 \, \text{Hz}$.

So, $\lambda = \frac{v}{f}$.

$\lambda = \frac{1500}{300}$.

$\lambda = 5 \, \text{m}$.

Thus the wavelength is 5 m.

Explanation: General form: $y = A \sin(\omega t – kx)$.

Here, $\omega = 400\pi$.

We know $\omega = 2\pi f$.

So, $f = \frac{\omega}{2\pi}$.

$f = \frac{400\pi}{2\pi}$.

$f = 200 \, \text{Hz}$.

Thus the frequency is 200 Hz.

Explanation: In transverse waves, particles oscillate at right angles to the direction of wave propagation.

For example, in waves on a string, particles move up and down, while the wave travels horizontally.

Option A describes longitudinal waves.

Option B is incorrect because oscillations are not opposite but perpendicular.

Option D describes circular polarization, not general transverse motion.

Explanation: Electromagnetic waves such as light are transverse waves.

The electric and magnetic fields oscillate perpendicular to the direction of propagation.

Sound waves and pressure waves in gases are longitudinal.

Seismic P-waves are longitudinal; seismic S-waves are transverse.

Explanation: Seismic S-waves (secondary waves) are shear or transverse waves.

They move the ground perpendicular to the direction of travel.

P-waves (primary waves) are longitudinal.

Rayleigh and surface waves are more complex but not purely transverse.

Explanation: The relation is $v = f \lambda$.

Here, $f = 50 \, \text{Hz}$.

Also, $\lambda = 2 \, \text{m}$.

So, $v = 50 \times 2$.

$v = 100 \, \text{m/s}$.

Thus the wave speed is 100 m/s.

Explanation: For transverse waves to propagate, the medium must support shear stress.

This is why solids can carry transverse waves but fluids (liquids and gases) cannot.

Compressibility (A) allows longitudinal waves.

Inertia and density (C, D) influence wave speed but not wave type.

Explanation: Transverse waves require resistance to shear deformation.

Gases cannot sustain shear stress, so they cannot propagate transverse mechanical waves.

They can only propagate longitudinal waves.

Options A, C, and D are misconceptions.

Explanation: Surface water waves are not purely transverse; particles move in nearly circular paths.

This combines both longitudinal (back-and-forth) and transverse (up-and-down) motions.

Option A and B oversimplify the motion, while D is incorrect.

Explanation: General form: $y = A \sin(\omega t – kx)$.

Here, $\omega = 200\pi$.

We know $\omega = 2\pi f$.

So, $f = \frac{\omega}{2\pi}$.

$f = \frac{200\pi}{2\pi}$.

$f = 100 \, \text{Hz}$.

Thus the frequency is 100 Hz.

Explanation: In the electromagnetic spectrum, wavelength decreases from radio waves to gamma rays.

X-rays have very short wavelengths, shorter than infrared and microwaves.

Radio waves have the longest wavelength.

Thus the correct option is X-rays.

Explanation: The relation is $v = f \lambda$.

Here, $f = 5 \, \text{Hz}$.

Also, $\lambda = 2 \, \text{m}$.

So, $v = 5 \times 2$.

$v = 10 \, \text{m/s}$.

Thus the wave speed is 10 m/s.

Explanation: In longitudinal waves, the particles of the medium oscillate back and forth in the same direction as the wave travels.

This produces compressions (regions of high pressure) and rarefactions (regions of low pressure).

Option A is for transverse waves.

Option B is for surface water waves.

Option D is incorrect as wave motion is orderly.

Explanation: Sound waves in air are longitudinal, consisting of alternating compressions and rarefactions.

Light waves are electromagnetic and transverse.

String waves are transverse.

Seismic S-waves are shear waves and transverse.

Explanation: Seismic P-waves (Primary waves) are longitudinal and travel by compressing and stretching rock layers.

They are the fastest seismic waves and can travel through solids, liquids, and gases.

S-waves are transverse, Love waves are surface waves, and water waves are mixed.

Explanation: We use $v = f \lambda$.

Here, $v = 340 \, \text{m/s}$.

Also, $f = 256 \, \text{Hz}$.

So, $\lambda = \frac{v}{f}$.

$\lambda = \frac{340}{256} $.

$\lambda \approx 1.33 \, \text{m} $.

Thus the wavelength is about 1.33 m.

Explanation: Fluids can be compressed and expanded, so they support longitudinal pressure waves.

They cannot resist shear deformation, so transverse waves cannot propagate in them.

Options B, C, and D are incorrect because they misrepresent fluid properties.

Explanation: Compressions are regions where particles are closest together, producing high pressure and density.

Rarefactions are regions of low pressure and density.

Options A and D do not define compressions, and B actually describes rarefactions.

Explanation: We use $v = f \lambda$.

Here, $v = 340 \, \text{m/s}$.

Also, $f = 512 \, \text{Hz}$.

So, $\lambda = \frac{v}{f}$.

$\lambda = \frac{340}{512} $.

$\lambda \approx 0.55 \, \text{m} $.

Thus the wavelength is 0.55 m.

Explanation: When a wave passes from one medium to another, its speed and wavelength change due to different medium properties.

Frequency remains constant because it is determined by the source.

Amplitude may also change depending on boundary conditions.

Explanation: In a longitudinal sound wave, pressure variation $P$ is related to displacement amplitude $y$ as $P = \rho v \omega y$.

Here, $\rho$ = density of medium, $v$ = speed of sound, and $\omega = 2\pi f$.

This shows that pressure amplitude increases with higher frequency and displacement.

Explanation: Formula: $P = \rho v \omega y$.

Here, $\rho = 1000 \, \text{kg/m}^3$.

$v = 1500 \, \text{m/s}$.

$\omega = 2000 \, \text{rad/s}$.

$y = 10^{-6} \, \text{m}$.

So, $P = 1000 \times 1500 \times 2000 \times 10^{-6}$.

$P = 1000 \times 1500 \times 0.002$.

$P = 1000 \times 3$.

$P = 3000 \, \text{Pa}$.

Correcting: That gives 3000 Pa, which doesn’t match options. Likely a scale mismatch. Let’s recalc:

$P = (1000)(1500)(2000)(10^{-6})$.

$P = 3 \times 10^3 \, \text{Pa}$.

Thus, the accurate answer is **3000 Pa**, but since not listed, the closest is between 2 Pa and 4 Pa.

Explanation: In transverse waves, particles oscillate perpendicular to propagation (e.g., string waves, light).

In longitudinal waves, particles oscillate parallel to propagation (e.g., sound, P-waves).

Option A is reversed, C applies to surface waves, and D is incorrect.

Explanation: Seismic waves can be transverse (S-waves) or longitudinal (P-waves).

Light and radio are always electromagnetic (transverse).

Sound is always longitudinal in gases and liquids.

Explanation: Compressions and rarefactions (density/pressure variations) are characteristics of longitudinal waves.

Transverse waves show crests and troughs.

Thus option B is correct.

Explanation: When waves convert from one type to another, frequency remains constant since it depends only on the source.

Wavelength and speed differ in each medium.

Amplitude may also vary depending on energy transfer.

Explanation: Both wave types have measurable wavelength, frequency, and obey $v = f\lambda$.

The key difference is particle displacement direction: perpendicular for transverse, parallel for longitudinal.

Explanation: Light is an electromagnetic wave that is always transverse.

Sound and P-waves are longitudinal.

Compression in springs is longitudinal.

Explanation: Polarization is restriction of vibration to one direction, possible only for transverse waves (light, EM waves).

Longitudinal waves cannot be polarized since oscillations are always along propagation.

Explanation: For sound wave, use $\lambda = \frac{v}{f}$.

Here, $v = 340 \, \text{m/s}$.

Also, $f = 20 \, \text{Hz}$.

So, $\lambda = \frac{340}{20}$.

$\lambda = 17 \, \text{m}$.

Thus wavelength is 17 m.

Explanation: Electromagnetic waves (light, radio, X-rays) are transverse and can propagate in vacuum.

Mechanical waves (both transverse and longitudinal) require a medium.

Thus option C is correct.

Explanation: For longitudinal wave: $v = f\lambda$.

Here, $v = 300 \, \text{m/s}$ (given directly).

For transverse wave: $v = f\lambda = 150 \times 2 = 300 \, \text{m/s}$.

Both speeds equal **300 m/s** actually. Correct answer is **C. Both equal**.

Thus both waves travel with equal speeds in their respective media, even though mechanisms differ.

Explanation: The standard mathematical form of a progressive wave traveling along +x is:

$y(x,t) = A \sin(kx – \omega t + \phi)$.

Here, $A$ is amplitude, $k = \frac{2\pi}{\lambda}$ is wave number, $\omega = 2\pi f$ is angular frequency, and $\phi$ is initial phase.

Options C and D miss spatial or temporal dependence, while B describes a wave in the –x direction.

Explanation: In the general wave equation, $y = A \sin(kx – \omega t)$, the constant $A$ indicates amplitude, i.e., the maximum displacement of particles from equilibrium.

The wave number $k$ relates to wavelength, angular frequency $\omega$ relates to time oscillation, and $t$ is the time variable.

Explanation: General form: $y = A \sin(kx – \omega t)$.

Here, angular frequency $\omega = 200\pi$.

We know $\omega = 2\pi f$.

So, $f = \frac{\omega}{2\pi}$.

$f = \frac{200\pi}{2\pi}$.

$f = 100 \, \text{Hz}$.

Thus, the wave has frequency 100 Hz.

Explanation: Wave number is given by coefficient of $x$.

Here, $k = 4\pi$.

We know $k = \frac{2\pi}{\lambda}$.

So, $\lambda = \frac{2\pi}{k}$.

$\lambda = \frac{2\pi}{4\pi}$.

$\lambda = 0.5 \, \text{m}$.

Correction: That equals **0.5 m**, so correct option is **B. 0.50 m**.

Explanation: The quantity $(kx – \omega t)$ is called the phase of the wave.

It determines the state of oscillation at a given position and time.

Amplitude is determined by $A$.

Energy depends on amplitude squared.

Frequency is given by $\omega = 2\pi f$, not directly by the phase term.

Explanation: Wave speed is given by $v = \frac{\omega}{k}$.

Here, $\omega = 40\pi$.

Also, $k = 0.2\pi$.

So, $v = \frac{40\pi}{0.2\pi}$.

$v = \frac{40}{0.2}$.

$v = 200$.

Thus the correct speed is $200 \, \text{m/s}$. Correct option is **C**.

Explanation: Equation: $y = A \sin(2\pi (0.5x – 100t))$.

Comparing with $y = A \sin(kx – \omega t)$:

Here, $\omega = 2\pi f$.

From term $-100t$ inside $2\pi$, we get $f = 100 \, \text{Hz}$.

Thus the wave has frequency 100 Hz.

Explanation: General form:

For wave in +x direction: $y = A \sin(kx – \omega t)$.

For wave in –x direction: $y = A \sin(kx + \omega t)$.

Thus option B is correct. Options A and C represent +x direction, option D is pure time oscillation without propagation.

Explanation: Equation is in form $y = A \cos(kx – \omega t)$.

Here, the coefficient of $x$ is $k = 20$.

The coefficient of $t$ is $\omega = 200$.

Thus option A is correct.

Explanation: Wave speed is given by $v = \frac{\omega}{k}$.

Here, $k = 10$.

Also, $\omega = 300$.

So, $v = \frac{300}{10}$.

$v = 30 \, \text{m/s}$.

Thus the wave speed is 30 m/s.