Moving Charges And Magnetism Mock Test – Class 12 Physics
GKaim: Measure | Improve | Achieve

Moving Charges and Magnetism Mock Test – Class 12 Physics

Progressive Test — Guest First Round

0%

Moving Charges and Magnetism – Progressive Test

Welcome to the Progressive Test.

Click Start Test to begin the loaded practice round.

Good luck!

1 / 50

1. A long straight wire carries current . The magnetic field at a distance from it has magnitude

2 / 50

2. A magnetic field acts on two particles moving with the same speed at the same angle to . Particle P has charge , and particle Q has charge , with equal masses. Comparing the magnetic forces at entry,

3 / 50

3. The SI unit of magnetic dipole moment of a current loop is

4 / 50

4. In the Ampere-law derivation of the magnetic field inside a long solenoid, a rectangular Amperian loop is chosen with one long side inside the solenoid and one long side outside. The outside contribution is neglected because

5 / 50

5. The electric part and magnetic part of the Lorentz force differ in an important way. The electric force

6 / 50

6. The magnetic field on the axis of a single circular current loop of radius , at a distance from its centre, is

7 / 50

7. The quantity in the magnetic force relation for a straight current-carrying conductor represents

8 / 50

8. The torque on a magnetic dipole moment in a uniform magnetic field is represented by

9 / 50

9. A current loop of area is placed in a magnetic field . Its plane makes an angle with . The torque magnitude is

10 / 50

10. Study the table for two long parallel wires carrying currents and .

Row Current directions Magnetic force
P Same direction Attractive
Q Opposite directions Repulsive
R Same direction Force per unit length
S Opposite directions Attractive

The row that contains an incorrect statement is

11 / 50

11. The instantaneous power delivered by magnetic force on a moving charge is

12 / 50

12. Study the table about field roles in a cyclotron.

Row Part of cyclotron Main role
P Magnetic field in the dees Bends the path into circular arcs
Q Electric field across the gap Accelerates the charged particle
R Alternating oscillator Maintains proper timing of acceleration
S Magnetic field inside the dees Directly increases kinetic energy by doing work

The row that gives an incorrect role is

13 / 50

13. For a circular loop carrying current , let be the magnetic field at its centre. At an axial point where , the magnetic field is

14 / 50

14. A proton enters a region of uniform magnetic field with velocity perpendicular to . The magnetic force is directed

15 / 50

15. If the separation between two long parallel wires is doubled while both currents remain unchanged, the force per unit length becomes

16 / 50

16. For a non-relativistic charged particle in a cyclotron, the cyclotron frequency is

17 / 50

17. A wire of length carries a current of in a magnetic field of . The angle between the wire and the field is . The force on the wire is

18 / 50

18. Use the graph description below.

A graph of axial magnetic field of a circular current loop is plotted against axial distance from the centre. The current and radius are fixed, and both positive and negative values of are considered.

The graph is symmetric about because

19 / 50

19. Study the table about galvanometer conversion formulas.

Row Conversion Added resistance
P Ammeter of range in parallel
Q Voltmeter of range in series
R Ammeter of range in series
S Voltmeter of range Effective resistance is large

The row that wrongly matches the conversion is

20 / 50

20. A charged particle enters a uniform magnetic field with fixed speed at an angle to . If is increased from to , the radius of the helical path changes by the factor

21 / 50

21. A coil has turns, area , and carries current . It is placed in a uniform magnetic field of with its area vector perpendicular to the field. The torque on the coil is

22 / 50

22. Two long parallel wires P and Q are placed horizontally. P carries current to the right and Q carries current to the left. The magnetic interaction between them is

23 / 50

23. A closed path is chosen near a long straight wire, but the wire lies outside the closed path. For that path, Ampere’s law gives

24 / 50

24. A voltmeter is made by adding a series resistance to a galvanometer. If the added resistance is smaller than the required value for a given voltage range, the voltmeter will

25 / 50

25. At a point on the axis of a circular current loop, the magnetic field is maximum when the point is

26 / 50

26. A positive ion moves to the right between crossed fields. The electric field is upward, and the ion is observed to move undeflected. The magnetic force on the ion must be

27 / 50

27. A region has magnetic field lines drawn very close together near point P and widely separated near point Q. The best interpretation is that

28 / 50

28. The magnetic force on a moving charge is zero in both parallel and anti-parallel motion because

29 / 50

29. A loudspeaker is often mentioned with motors and galvanometers because its basic working also involves

30 / 50

30. A charged particle moves in a circular path under a uniform magnetic field with constant speed. Its acceleration is non-zero because

31 / 50

31. In the non-relativistic operation of a cyclotron, the particle moves in spirals of increasing radius. The radius increases mainly because

32 / 50

32. A magnetic-relations sheet lists the following pairs.

Row Situation Useful relation
P Velocity selector
Q Long solenoid interior
R Long straight wire field
S Magnetic field doing work on a charge

The row that should be removed from the relation sheet is

33 / 50

33. A magnetic dipole of moment is placed in a uniform magnetic field of . The increase in potential energy when it is turned from to is

34 / 50

34. Two long parallel wires carry currents and in the same direction. At the position of wire , the magnetic field due to wire is perpendicular to wire . The force per unit length on wire is obtained from

35 / 50

35. Study the table for a straight current-carrying conductor in a uniform magnetic field.

Row Change made Effect on force magnitude
P doubled doubles
Q doubled doubles
R doubled doubles
S changed from to doubles

The row that contains an incorrect effect is

36 / 50

36. A voltmeter made from a galvanometer has range and total resistance . The full-scale galvanometer current is

37 / 50

37. A galvanometer has and . It is converted into an ammeter using a shunt . The full-scale range of the ammeter is

38 / 50

38. Assertion: A current loop in a uniform magnetic field can have zero net force but non-zero torque.
Reason: Forces on opposite sides may cancel in translation while forming a couple.

39 / 50

39. A galvanometer has and full-scale current . A shunt of is connected. The approximate ammeter range is

40 / 50

40. A proposed solution says: “A closed current loop in a uniform magnetic field has zero net force, so it cannot have torque.” The error in this claim is that

41 / 50

41. Use the graph description below.

For two long parallel wires carrying fixed currents and , a graph of force per unit length against is drawn, where is the separation between the wires.

The slope of this graph is

42 / 50

42. A current element produces at a point. If the current is doubled and the distance of the point from the element is also doubled, with and unchanged, the new magnetic field contribution is

43 / 50

43. Three long parallel wires are perpendicular to the page. Wire P carries out of the page, wire Q carries out of the page, and wire R carries into the page. Q is midway between P and R, with equal separation from each. The net force on wire Q is

44 / 50

44. Read the two statements below.
I. A magnetic field can exert force on a moving charge.
II. A magnetic field always changes the speed of a charged particle.
For motion under magnetic field alone, the best evaluation is

45 / 50

45. A current loop has its plane perpendicular to a uniform magnetic field. The torque on it is zero because

46 / 50

46. The magnetic field contribution due to a small current element is described by the Biot-Savart law. Its vector form is

47 / 50

47. To convert a galvanometer into a voltmeter of range , a resistance is connected in series. The purpose of this series resistance is to

48 / 50

48. A circular loop carries current clockwise as seen from the right side of its axis. The magnetic field at the centre, as seen from that right side, is directed

49 / 50

49. A galvanometer of resistance and full-scale current is converted into a voltmeter of range . The required series resistance is

50 / 50

50. A circular loop of radius carries current . At a point on the axis, the magnetic field is half of the field at the centre. The axial distance satisfies

Your score is

Share your achievement!

LinkedIn Facebook
0%

Complete 100% of the Progressive Test coverage to unlock Mistake Review.
Complete 100% of the Progressive Test coverage to unlock Certificate Challenge.

Subscribe
Notify of
guest
0 Comments
Scroll to Top