Moving Charges And Magnetism Mock Test

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Quiz: Moving Charges and Magnetism – Progressive Test
Total questions: 360
Questions in this round: 50
Time allotted: 70 minutes
Pass score: 60%
Total rounds: 8
Current round: 1^st
Rounds passed: 0 / 8
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Quiz: Moving Charges and Magnetism – Certificate Challenge
Total questions: 360
Questions to attempt: 100 random
Time allotted: 100 minutes
Certificate pass score: 70%
Random questions: Yes
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Progressive Test — Guest First Round

Moving Charges and Magnetism – Progressive Test

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1 / 50

1. Study the table for perpendicular motion of a charged particle in a uniform magnetic field.

Row	Quantity	Relation or dependence
P	Radius
Q	Radius in terms of
R	Centripetal acceleration
S	Speed	Increases continuously due to magnetic work

The row that does not fit magnetic-field-only circular motion is

a) Row P

b) Row R

c) Row Q

d) Row S

2 / 50

2. A magnetic field alone is compared with an electric field alone for a charged particle. The best distinction is that

a) both forces always keep kinetic energy constant

b) both forces are always perpendicular to velocity

c) magnetic force can change speed directly, while electric force never can

d) electric force can do work, while magnetic force alone does no work

3 / 50

3. For a circular loop carrying current , let be the magnetic field at its centre. At an axial point where , the magnetic field is

4 / 50

4. Study the table for a straight current-carrying conductor in a uniform magnetic field.

Row	Condition	Force magnitude
P
Q
R
S

The row that contains an incorrect force magnitude is

a) Row R

b) Row S

c) Row Q

d) Row P

5 / 50

5. A charged particle moves only under the action of a magnetic field. Its kinetic energy remains constant because the magnetic force

a) is perpendicular to velocity

b) is parallel to velocity

c) is opposite to velocity

d) is zero for every moving charge

6 / 50

6. In a moving-coil galvanometer, the soft iron core is used mainly to

a) convert the galvanometer directly into a voltmeter without resistance

b) stop current from flowing through the coil

c) make the restoring torque independent of deflection

d) make the magnetic field radial and stronger near the coil

7 / 50

7. A square loop of side carries current and is placed in a uniform magnetic field. If the field lies in the plane of the loop and is parallel to one pair of opposite sides, then the force on those parallel sides is

a) on each of them

b) on each of them

c) on each of them

d) on each of them

8 / 50

8. In a moving-coil galvanometer, a radial magnetic field is used so that

a) the coil current reverses every half turn

b) the restoring torque becomes zero

c) the coil plane remains parallel to

d) the torque becomes independent of current

9 / 50

9. Use the graph description below.

For a fixed charge moving with fixed speed in a fixed magnetic field, a graph is plotted between magnetic force magnitude and , where is the angle between and . The graph is a straight line through the origin.

The slope of the graph represents

10 / 50

10. For the vector product , the direction is

a) perpendicular to both and

b) opposite to for every charge

c) along , in the plane of the two vectors

d) along , in the plane of the two vectors

11 / 50

11. The instantaneous power delivered by magnetic force on a moving charge is

12 / 50

12. A graph of against for a particle moving perpendicular to a magnetic field has slope . If the particle speed is , the charge-to-mass ratio is

13 / 50

13. For a charged particle moving perpendicular to a uniform magnetic field, the radius of the circular path is

14 / 50

14. Use the graph description below.

For a circular coil of fixed radius and fixed number of turns , a graph of magnetic field at the centre against current is drawn.

The graph is expected to be

a) a rectangular hyperbola with decreasing

b) a straight line through the origin

c) a horizontal line through a non-zero field value

d) a parabola opening upward

15 / 50

15. A galvanometer of resistance is converted into a voltmeter by adding in series. If , the voltmeter range is

16 / 50

16. A current-carrying wire is placed parallel to a uniform magnetic field. If the current and magnetic field are both non-zero, the force on the wire is

a) opposite to the current

b) zero

c) maximum

d) equal to

17 / 50

17. A galvanometer coil has , , , and . The current required for a deflection of is

18 / 50

18. The quantity is often used in Biot-Savart law. Its numerical value in SI units is

19 / 50

19. A closed path is chosen near a long straight wire, but the wire lies outside the closed path. For that path, Ampere’s law gives

c) at every point of the path

20 / 50

20. If the separation between two long parallel wires is doubled while both currents remain unchanged, the force per unit length becomes

a) half of its earlier value

b) twice its earlier value

c) unchanged

d) one-fourth of its earlier value

21 / 50

21. A negative charge moves through a region where the vector sum points along the positive -axis. The direction of the Lorentz force on the charge is

a) negative -axis

b) positive -axis

c) positive -axis

d) along

22 / 50

22. Two long parallel wires are apart and carry currents and in the same direction. Taking , the force per unit length between them is

a) , repulsive

b) , attractive

c) , attractive

d) , repulsive

23 / 50

23. A cyclotron has magnetic field and final orbit radius . A particle with and reaches the outer edge. Its maximum speed is

24 / 50

24. A circular current loop is viewed from one side, and the current appears anticlockwise. The face seen by the observer behaves like

a) a north pole face

b) a neutral face with no magnetic polarity

c) an electric positive plate

d) a south pole face

25 / 50

25. A finite straight conductor carrying current produces magnetic field at a point a perpendicular distance away. In the usual angle form, the magnitude is

26 / 50

26. A rectangular current loop is arranged so that the plane of the loop is parallel to a uniform magnetic field. The area vector of the loop is then perpendicular to , so the torque is

a) maximum

b) half of maximum

c) zero

d) opposite to the current on every side

27 / 50

27. Two particles enter the same uniform magnetic field with the same velocity. Particle P has charge , while particle Q has charge . If the magnetic force on P is , the magnetic force on Q is

28 / 50

28. Read the case below.

A proton and an electron enter the same uniform magnetic field at the same point. Their velocities are identical and perpendicular to . Ignore any interaction between the particles.

At the instant of entry, their magnetic forces have

a) unequal magnitudes and the same direction

b) zero magnitudes because the particles have opposite charges

c) equal magnitudes and opposite directions

d) equal magnitudes and the same direction

29 / 50

29. A voltmeter made from a galvanometer has range and total resistance . The full-scale galvanometer current is

30 / 50

30. A current loop behaves like a magnetic dipole in a uniform magnetic field. Its stable equilibrium occurs when

a) is parallel to

b) is anti-parallel to

c) is zero while current is non-zero

d) is perpendicular to

31 / 50

31. A magnetic-field graph for a long solenoid gives a straight line of slope when is plotted against . Taking , the turn density is closest to

32 / 50

32. A cyclotron is designed for protons. If an alpha particle is used in the same magnetic field, its cyclotron frequency compared with that of the proton is approximately

a) equal to the proton frequency

b) four times the proton frequency

c) half the proton frequency

d) twice the proton frequency

33 / 50

33. Use the graph description below.

A charged particle of fixed mass , charge magnitude , and speed moves perpendicular to different uniform magnetic fields. A graph of circular-path radius against is drawn.

The graph is a straight line whose slope is

34 / 50

34. A voltmeter is made by adding a series resistance to a galvanometer. If the added resistance is smaller than the required value for a given voltage range, the voltmeter will

a) draw exactly zero current

b) draw more than and over-deflect

c) become an ideal voltmeter

d) automatically become an ammeter

35 / 50

35. A current loop has its plane perpendicular to a uniform magnetic field. The torque on it is zero because

a) every side has zero magnetic force

b) area vector is perpendicular to

c) current in the loop becomes zero

d) area vector is parallel to the field

36 / 50

36. Use the graph description below.

For a long straight wire carrying fixed current , a graph is plotted between magnetic field and , where is the perpendicular distance from the wire. The graph is a straight line through the origin.

The slope of this graph is

37 / 50

37. A long straight wire carries current into the page. The magnetic field pattern on the page is

a) anticlockwise circles

b) radial lines outward from the wire

c) clockwise circles

d) straight horizontal lines

38 / 50

38. A magnetic dipole is slightly displaced from its stable equilibrium in a uniform magnetic field. The torque that appears tends to

a) make the magnetic field vanish

b) turn toward

c) increase its potential energy

d) keep perpendicular to

39 / 50

39. A pair of long parallel wires apart carry equal currents of in vacuum. The force per unit length between them is

40 / 50

40. A velocity selector has . Particles of speed must pass undeflected. The required magnetic field magnitude is

41 / 50

41. The starting idea behind magnetic effects of currents is that they are closely connected with ______.

a) neutral bodies kept in vacuum

b) gravitational attraction between masses

c) moving charges and electric currents

d) charges only when they are at rest

42 / 50

42. A current in wire P creates a magnetic field at the position of wire Q. Wire Q then experiences force because

a) a current-carrying conductor in a magnetic field experiences force

b) every conductor in air experiences magnetic force even without current

c) magnetic force requires only resistance and no current

d) parallel wires attract only due to electrostatic charging

43 / 50

43. Use the graph description below.

For a fixed straight wire carrying a fixed current in a fixed uniform magnetic field, a graph is plotted between force magnitude and , where is the angle between and . The graph is a straight line through the origin.

The slope of this graph is

44 / 50

44. A current element is directed along , and the observation point is located along from the element. The magnetic field contribution points along

45 / 50

45. A straight wire carries current toward the east, and a uniform magnetic field is directed toward the south. Taking east as , north as , and upward as , the force on the wire is directed

a) downward

b) upward

c) toward the south

d) toward the east

46 / 50

46. A charged particle moves through a magnetic field along a curved path. During a short displacement , the magnetic force is . The work done in that short displacement is zero because

a) is always equal to

b) is always zero

47 / 50

47. Study the region description for an ideal toroid with inner radius , outer radius , total turns , and current .

Region	Position of Amperian circle	Ideal magnetic field
P		Approximately zero
Q
R		Approximately zero

The reason region Q has a non-zero field is that the Amperian circle there

a) is outside the toroidal winding completely

b) has no current linkage at all

c) makes vanish in the core

d) links the current turns of the toroid

48 / 50

48. A current loop is placed so that its area vector is parallel to a uniform magnetic field . The torque on the loop is

a) equal to

b) equal to

c) maximum

d) zero

49 / 50

49. A charged particle moving in a magnetic field has its velocity split as and relative to . If is doubled while , , , and remain unchanged, then

a) the radius doubles and pitch remains unchanged

b) the radius and pitch both double

c) the radius remains unchanged and pitch doubles

d) the radius becomes half and pitch remains unchanged

50 / 50

50. Use the table for crossed electric and magnetic fields.

Row	Condition	Result
P		Undeflected motion is possible
Q		Selected speed
R	Electric and magnetic forces are in the same direction	Undeflected motion
S		Electric force is larger than magnetic force in magnitude

The row that contains a wrong crossed-field interpretation is

a) Row S

b) Row P

c) Row R

d) Row Q

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Moving Charges and Magnetism Mock Test – Class 12 Physics

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