Plant Kingdom Mock Test – Class 11 Biology
GKaim: Measure | Improve | Achieve

Plant Kingdom Mock Test – Class 11 Biology

Progressive Test — Guest First Round

0%

Plant Kingdom – Progressive Test

Welcome to the Progressive Test.

Click Start Test to begin the loaded practice round.

Good luck!

1 / 50

1. Destruction of every archegonium in a pteridophyte prothallus will most directly prevent:

2 / 50

2. Pyrenoids in green algae are:

3 / 50

3. A learner claims that microphylls are the small gametophytes of Selaginella. The claim should be corrected because microphylls are:

4 / 50

4. From the protoplast outward, the most appropriate description of a brown-algal cell boundary is:

5 / 50

5. A lateral bud formed on the secondary protonema of a moss normally develops into:

6 / 50

6. Pinus mycorrhiza and Cycas coralloid roots are similar because both:

7 / 50

7. The usual habitat description for many pteridophytes is:

8 / 50

8. Chlorophyceae demonstrate body-form diversity through:

9 / 50

9. A motile reproductive cell settles on a surface and develops into a new algal thallus without fusing with another cell. It is functioning as a:

10 / 50

10. Consider the following statements about numerical taxonomy.
I. Observable characters are coded numerically.
II. Computers can process a large character matrix.
III. Characters are given equal importance in the described method.
IV. Only chromosome characters are permitted in the analysis.

11 / 50

11. A treatment prevents flagellar movement in freshly released algal zoospores but does not kill them. The most immediate effect is expected to be:

12 / 50

12. An algal class shows vegetative fragmentation, non-motile asexual spores, non-motile sexual cells and oogamy followed by complex post-fertilisation development. This reproductive combination belongs to:

13 / 50

13. If a liverwort capsule belongs to a sporophyte, the spores produced after meiosis will be:

14 / 50

14. An unknown large spore from a heterosporous pteridophyte begins developing while associated with the parent plant. The strongest prediction is that it will form:

15 / 50

15. A comparative bryophyte illustration shows Structure P as a cup containing multicellular propagules on a flat thallus and Structure Q as a capsule elevated above an upright leafy plant. The correct interpretation is:

16 / 50

16. Referring to the holdfast, stipe and frond as true root, stem and leaf is biologically misleading mainly because:

17 / 50

17. Consider the following statements about gymnosperms.
I. They are vascular seed plants.
II. Their ovules are not enclosed within ovaries.
III. Their seeds are enclosed within fruits.
IV. Their dominant plant body is the sporophyte.

18 / 50

18. A mature fern sporophyte survives a dry season, but its spores fail to establish prothalli and no surface water is present during the reproductive period. Population renewal will be limited mainly by:

19 / 50

19. A gymnosperm has a largely unbranched stem, persistent pinnate leaves and coralloid roots containing nitrogen-fixing cyanobacteria. Male and female reproductive structures occur on separate plants. It is:

20 / 50

20. A mutation allows normal meiosis in gymnosperm microsporangia but prevents the resulting microspores from undergoing further mitosis. The plant will form:

21 / 50

21. Consider the following statements about gymnosperm fertilisation.
I. Pollination occurs before pollen-tube growth.
II. The pollen tube carries male gametes toward the archegonia.
III. External water is required for male gametes to swim from the male cone to the ovule.
IV. Fusion of a male gamete with an egg forms a zygote.

22 / 50

22. Equal moss protonemata are placed under two treatments. Treatment P allows normal bud formation, while Treatment Q blocks bud initiation without damaging the filaments. After several weeks, the most likely observation is:

23 / 50

23. Compact cones formed by aggregated sporophylls are commonly seen in:

24 / 50

24. In a gymnosperm, an archegonium is located:

25 / 50

25. Study the comparative records.

Class Major pigments Reserve food Motile-cell flagella
Chlorophyceae Chlorophyll a and b Starch Equal and apical
Phaeophyceae Chlorophyll a and c Laminarin or mannitol Unequal and lateral
Rhodophyceae Chlorophyll a, chlorophyll d and phycoerythrin Floridean starch Equal and apical

The final entry should be replaced by:

26 / 50

26. A hypothetical gymnosperm continues producing microspores and megaspores but loses ovule formation and releases every megaspore before gametophyte development. Its condition would most closely resemble:

27 / 50

27. A spherical organism consists of many cells organised into a coordinated colony. Among the standard algal examples, this body form is represented by:

28 / 50

28. A pear-shaped motile cell released by a brown alga bears two flagella of unequal length inserted on its side. It is most appropriately identified as a:

29 / 50

29. A bryophyte gametophyte and a fern prothallus possess mature sex organs, but both surfaces remain dry. The common immediate limitation is:

30 / 50

30. Match each part of a Funaria plant with its generation or function. A Column II entry is used once.

Column I Column II
P. Rhizoids 1. Elevates the capsule
Q. Leafy axis 2. Spore-producing region
R. Seta 3. Anchors the gametophyte
S. Capsule 4. Main photosynthetic gametophyte

31 / 50

31. A student treats dicotyledons and monocotyledons as plant groups separate from angiosperms. The best correction is that they are:

32 / 50

32. A flowering plant is labelled “monocotyledon” in a figure. From that label alone, the justified conclusion is that it:

33 / 50

33. A moss spore begins germination by forming:

34 / 50

34. The group containing only marine algae cited as food sources is:

35 / 50

35. Fusion occurs between two gametes that are similar in size and both possess flagella, as in Ulothrix. The sexual condition is:

36 / 50

36. A heterosporous pteridophyte and a gymnosperm both retain a female gametophyte containing a young embryo. The gymnosperm condition differs more completely by including:

37 / 50

37. Genetically similar plants are raised under high light and deep shade. Leaf size and growth habit differ, but their reproductive structures remain alike. The strongest inference for classification is that:

38 / 50

38. Plants P and Q look similar because both evolved thick leaves in dry habitats. New anatomical and reproductive evidence shows that P shares a recent common ancestor with Plant R rather than Q. A phylogenetic system should:

39 / 50

39. Pollen grains are found at the openings of numerous gymnosperm ovules, but no zygotes have formed. The observation proves that:

40 / 50

40. Vegetative reproduction in liverworts may occur through:

41 / 50

41. The free-living nature of a typical pteridophyte prothallus means that it:

42 / 50

42. A reproductive cell has two unequal lateral flagella and germinates independently after settling. The most appropriate classification is:

43 / 50

43. Compared with bryophytes and pteridophytes, gymnosperms are less dependent on external water for fertilisation mainly because:

44 / 50

44. In a described Equisetum figure, an underground horizontal axis gives rise to an upright jointed shoot with nodes, internodes, lateral branches and a compact terminal structure. The underground axis and terminal structure are:

45 / 50

45. A student states, “An organism can be an alga only when it remains completely submerged in fresh or marine water.” The statement needs correction since algae:

46 / 50

46. Arrange the following steps in the most logical order for numerical-taxonomic analysis.
P. Process the completed matrix with a computer.
Q. Record observable characters in the selected plants.
R. Convert character states into numerical codes.
S. Assemble the coded observations into a data matrix.

47 / 50

47. Study the reproductive records.

Plant Spore types produced
P One uniform type
Q Small microspores and large megaspores
R One uniform type

The correct classification of P, Q and R is:

48 / 50

48. A plant forms flowers normally, but a developmental defect prevents formation of ovaries around the ovules. The resulting reproductive organisation would fail to satisfy the defining angiosperm condition of:

49 / 50

49. Consider the following statements about sexual reproduction in brown algae.
I. Isogamy, anisogamy and oogamy may occur.
II. Gamete fusion may take place in water.
III. Fusion may occur within the oogonium in oogamous forms.
IV. Every sexual gamete is non-motile.

50 / 50

50. Angiosperms contribute directly to human needs by providing:

Your score is

Share your achievement!

LinkedIn Facebook
0%

Complete 100% of the Progressive Test coverage to unlock Mistake Review.
Complete 100% of the Progressive Test coverage to unlock Certificate Challenge.

Subscribe
Notify of
guest
0 Comments
Scroll to Top