Exam-Style Mock Test | Class 11 Chemistry: Hydrocarbons

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Quiz: Hydrocarbons – Certificate Challenge
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1 / 50

1. A record of alkane structures is shown below.

Row	Molecular formula	Number of chain isomer skeletons stated
P
Q
R
S

The row that needs correction is

a) R

b) S

c) P

d) Q

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2. A learner says, “Eclipsed and staggered ethane must be different compounds because their energies are different.” The best correction is that they are

a) different conformations of the same molecule

b) different chain isomers of

c) different molecular formulas

d) different aromatic hydrocarbons

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3. A table compares alkane reaction types.

Row	Reaction	Broad description
P	Halogenation under light	free-radical substitution
Q	Nitration or sulfonation of alkanes	substitution under harsh conditions
R	Pyrolysis of higher alkanes	cracking into smaller hydrocarbons
S	Combustion in excess oxygen	formation of only alkyl halides

The row that needs correction is

a) R

b) P

c) Q

d) S

4 / 50

4. Match the hydrocarbon observation with the most suitable inference.

Observation	Inference
P. Bromine water decolourised	1. Unsaturation may be present
Q. Cold alkaline decolourised	2. Mild oxidation of unsaturation may occur
R. Ammoniacal gives precipitate	3. Terminal alkyne group may be present

a) P-1, Q-2, R-3

b) P-1, Q-3, R-2

c) P-2, Q-3, R-1

d) P-3, Q-1, R-2

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5. In the dehydrohalogenation of , the major alkene usually follows Saytzeff's rule. The major product is

a) but--ene

b) butane

c) ethene

d) but--ene

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6. For Kolbe electrolysis of , the main symmetrical alkane product contains how many carbon atoms?

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7. The solvent most suitable for dissolving an alkane is generally

a) a non-polar organic solvent

b) aqueous sodium hydroxide

c) water

d) dilute hydrochloric acid

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8. One mole of ethyne, , is completely hydrogenated to ethane, . The amount of required is

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9. A hydrocarbon has one tertiary hydrogen and nine primary hydrogens. On radical bromination, the major monobromo product is expected from replacement of

a) any hydrogen equally because bromine is non-selective

b) a carbon atom rather than a hydrogen atom

c) the tertiary hydrogen because bromination is highly selective

d) a primary hydrogen because there are more of them

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10. Ozonolysis of , followed by reductive work-up, gives

a) and

b) and

c) only

d) only

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11. A branched alkyl halide undergoes elimination with alcoholic . The major alkene is usually the one that is

a) least substituted around the double bond

b) more substituted and more stable

c) formed by replacing halogen with

d) formed by adding

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12. As the carbon number increases in a homologous series of straight-chain alkenes, the boiling point generally

a) increases as London dispersion forces strengthen

b) remains exactly constant for all members

c) decreases because the molecules become lighter

d) becomes zero because all alkenes are gases

13 / 50

13. A sample of ethene is completely converted into polyethene. If ethene molecules are joined in one polymer chain, the number of repeating units in that chain is

14 / 50

14. Complete combustion of of an open-chain alkane requires of . The alkane is

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15. Consider these statements about alkene preparation.
I. Alcohol dehydration removes .
II. Alkyl halide dehydrohalogenation removes .
III. Catalytic hydrogenation of an alkene prepares a more unsaturated hydrocarbon.

a) II and III only

b) I and II only

c) I and III only

d) I, II, and III

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16. If benzene is converted first to nitrobenzene and then nitrated again, the main disubstituted product is

b) only

17 / 50

17. Reductive ozonolysis of hydrocarbon gives of methanal and of propanone from of . Which structure of is most suitable?

18 / 50

18. The product formed when ethene undergoes complete catalytic hydrogenation is

a) methane,

b) ethyne,

c) benzene,

d) ethane,

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19. For complete combustion of propane, , the coefficient of in the balanced equation is

20 / 50

20. During electrophilic addition of to ethene, the product is

21 / 50

21. A pair of structures is described below.
Case 1:
Case 2:
The best comparison of these two hydrocarbons is that they

a) have the same structure written in two notations

b) have different molecular formulas and different carbon skeletons

c) differ only in the position of a double bond

d) have the same molecular formula but different carbon skeletons

22 / 50

22. A learner claims that but--yne should give a silver acetylide precipitate because it has a triple bond. The best correction is that but--yne

a) has a triple bond but no terminal alkyne hydrogen

b) is an alkane with only single bonds

c) contains an group instead of carbon

d) has no carbon atoms

23 / 50

23. Reduction of an alkyl halide to an alkane mainly involves replacing the halogen atom by

c) another halogen atom

d) hydrogen

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24. A butane Newman projection shows the two groups directly eclipsing each other. This conformation is best described as

a) gauche and lowest in energy

b) anti and most stable

c) staggered with no methyl-methyl repulsion

d) fully eclipsed and least stable

25 / 50

25. In the presence of peroxide, addition of to propene mainly gives

26 / 50

26. For propane, , a claim says that moving the middle carbon to a branch gives a second chain isomer. The flaw in this claim is that

a) propane is not a hydrocarbon compound

b) propane has a cyclic carbon skeleton

c) propane contains a carbon-carbon double bond

d) propane has no distinct branched skeleton

27 / 50

27. An alkene can show cis-trans isomerism only when each double-bonded carbon has

a) no substituents except oxygen

b) two identical groups attached

c) two different groups attached

d) only single bonds and no -bond

28 / 50

28. A limitation of using a mixture of two different carboxylate salts in Kolbe electrolysis is that

a) different radical couplings can give a mixture of alkanes

b) no radicals can form at the anode

c) only carbon dioxide is produced and no alkane can form

d) the reaction must give only one perfectly symmetrical product

29 / 50

29. A reaction comparison is shown below.

Reaction route	Typical carbon-count effect
P. reduction	carbon skeleton retained
Q. Wurtz reaction with one alkyl halide	alkyl group count effectively doubles
R. Soda-lime decarboxylation	alkane has one carbon fewer than the carboxylate salt

The comparison supports the conclusion that

a) Wurtz reaction always gives one carbon fewer

b) decarboxylation involves loss of the carboxyl carbon

c) all three routes have the same carbon-count effect

d) alkyl halide reduction always doubles the chain

30 / 50

30. A member of an open-chain monoalkyne series has carbon atoms. The formula expected from the general relation is

31 / 50

31. Polynuclear aromatic hydrocarbons are best described as aromatic compounds that contain

a) only one carbon atom and four hydrogen atoms

b) a single open-chain carbon-carbon triple bond only

c) fused or multiple aromatic ring systems

d) sodium carboxylate groups as the main skeleton

32 / 50

32. A comparison of propene addition products is given below.

Reagent condition	Major product
P. , no peroxide
Q. , peroxide
R.
S.	becomes more unsaturated

The entry that needs correction is

a) P

b) R

c) Q

d) S

33 / 50

33. Bromination of alkanes is generally more selective than chlorination because bromine radicals are

a) less reactive and more influenced by radical stability

b) unable to abstract hydrogen atoms from alkanes

c) more reactive and less influenced by radical stability

d) converted into before reaction

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34. A hydrocarbon has formula and is known to be open-chain with one double bond. Its family is

a) arene

b) alkane

c) alkyne

d) alkene

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35. A text-described arrangement around one carbon atom has four single bonds directed toward the corners of a tetrahedron. The hydrocarbon family most directly represented by this local arrangement is

a) alkenes at the double-bond carbon

b) benzene ring carbons only

c) alkynes at the triple-bond carbon

d) alkanes

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36. A mixture contains ethene and ethyne. It is completely hydrogenated to ethane. The total volume of required at is

37 / 50

37. The electrophile in nitration of benzene is

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38. The best reason dry ether is specified in Wurtz reaction is that

a) ether oxidises the alkyl halide to a carboxylate

b) ether supplies the carbon atoms of the product

c) sodium coupling needs a dry, non-aqueous medium

d) water is needed to dissolve sodium completely

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39. In and , the main difference is the

a) number of carbon atoms

b) replacement of hydrogen by chlorine

c) presence of a benzene ring

d) position of the carbon-carbon double bond

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40. A table compares alkyl halide conversion routes.

Row	Condition	Main hydrocarbon outcome
P
Q
R	reducing condition	halogen replaced by hydrogen
S	reducing condition	as the alkane product

The row that needs correction is

a) Q

b) R

c) P

d) S

41 / 50

41. A table of hydrogenation changes is shown below.

Row	Reactant type	Hydrogenation product under complete saturation
P	Alkene	Alkane
Q	Alkyne	Alkane with sufficient
R	Alkane	Alkene by adding
S	Unsaturated hydrocarbon	More saturated hydrocarbon

The row that needs correction is

a) P

b) Q

c) S

d) R

42 / 50

42. Combustion results for hydrocarbon give of and of from of . It also consumes of per during complete hydrogenation. The formula of is

43 / 50

43. The Wurtz reaction uses alkyl halides with sodium metal in

a) aqueous ethanol

b) dry ether

c) cold alkaline potassium permanganate

d) concentrated sulfuric acid

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44. The formula is assigned to hydrocarbon , which consumes of per mole on complete hydrogenation. Reductive ozonolysis is not applicable because does not contain a bond before hydrogenation. The most suitable identity is

a) cyclobutane or methylcyclopropane

b) butane or -methylpropane

c) but--ene or but--ene

d) but--yne or but--yne

45 / 50

45. The pair and has

a) same formula and connectivity, different arrangement

b) different numbers of carbon atoms

c) no carbon-carbon double bond

d) different formulas and different carbon skeletons

46 / 50

46. Nitration of toluene usually gives mainly

a) ortho- and para-nitrotoluene

b) benzoic acid only

c) nitrobenzene only

d) meta-nitrotoluene only

47 / 50

47. A table compares possible monochlorination outcomes.

Alkane	Key hydrogen environments	Number of distinct monochloro products
P.	all hydrogens equivalent
Q.	all hydrogens equivalent
R.	terminal and middle hydrogens differ
S.	all hydrogens equivalent

The row that needs correction is

a) P

b) S

c) Q

d) R

48 / 50

48. Assertion: Gauche butane is less stable than anti butane.
Reason: In gauche butane, the two groups are closer than in the anti conformation.

a) Assertion is true, but Reason is false

b) Both Assertion and Reason are true, but Reason does not explain Assertion

c) Both Assertion and Reason are true, and Reason explains Assertion

d) Assertion is false, but Reason is true

49 / 50

49. A compact reaction case is given below.

Benzene is treated with in the presence of . The product contains one bromine atom attached to the benzene ring.

The most suitable equation pattern is

d) as the usual substitution product

50 / 50

50. A structure is described as . Its IUPAC name is

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Hydrocarbons Mock Test – Class 11 Chemistry

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