Exam-Style Mock Test | Class 11 Chemistry: Hydrocarbons
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Hydrocarbons Mock Test – Class 11 Chemistry

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Hydrocarbons – Progressive Test

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1. During complete hydrogenation, of an open-chain hydrocarbon absorbs of at and gives an alkane of formula . The formula of is

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2. The simplest member of the alkyne series is

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3. In the classification map below, the missing entry at is most suitable for which hydrocarbon type?

Hydrocarbon feature Broad class
Open-chain, only single bonds Alkane
Open-chain, at least one
Open-chain, at least one Alkyne

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4. A benzene ring carrying a group is commonly named

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5. A preparation route is represented as . This route is useful for preparing alkanes because it

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6. In the monochlorination of propane, substitution at a terminal carbon gives

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7. The molecular formula of benzene is

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8. For monochlorination of methane, the overall reaction is . If of methane is completely converted only to , the amount of consumed is

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9. A monohalogenation calculation for propane uses relative reactivities . If propane has primary hydrogens and secondary hydrogens, the approximate percentage of in the monochloro product mixture is

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10. The solvent most suitable for dissolving an alkane is generally

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11. In the reaction , the role of in soda lime is best described as

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12. A preparation scheme changes into an alkane without changing the carbon skeleton. The product is

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13. A limitation of using a mixture of two different carboxylate salts in Kolbe electrolysis is that

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14. A sample decolourises bromine water, decolourises cold dilute alkaline , and gives no precipitate with ammoniacal . The most reasonable possibility is

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15. A route planner wants to prepare butane as the main product. Two possible routes are shown.
Case 1: with
Case 2: by Kolbe electrolysis
The correct comparison is that

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16. A hydrocarbon has formula and is known to be an open-chain compound with one triple bond. Its family is

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17. A reaction sequence is written as


The products and are respectively

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18. Excess adds to ethyne to give a product best represented as

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19. In a Newman projection of butane, an eclipsed form with eclipsing is generally

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20. In a carbon-carbon double bond of an alkene, the bonding consists of

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21. The balanced complete combustion equation for methane is

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22. Ethyne reacts with excess bromine. The final saturated product is best represented as

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23. A hydrocarbon has one tertiary hydrogen and nine primary hydrogens. On radical bromination, the major monobromo product is expected from replacement of

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24. A hydrocarbon is written as . This formula alone tells us

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25. A learner claims, “Every hydrocarbon with fewer hydrogen atoms than the corresponding alkane must behave like a simple alkene.” The best response is that

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26. The usual stability order of alkyl radicals formed during alkane halogenation is

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27. Assertion: Alkenes decolourise bromine solution and alkaline , but the products are not the same.
Reason: Bromine adds bromine atoms across , while alkaline introduces hydroxyl groups under mild oxidation.

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28. A hydrocarbon is converted into by adding of per mole of using a controlled catalyst. then consumes of per mole. Complete hydrogenation of would consume of per mole. The best description of and is

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29. In ozonolysis, an alkene is first treated with , followed by reductive work-up such as . The reaction is mainly useful for

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30. A table compares structural statements about benzene.

Row Statement
P Benzene is planar.
Q Each carbon in benzene is -hybridised.
R The -electrons are delocalised over the ring.
S Benzene behaves exactly like an ordinary alkene in all reactions.

The row that needs correction is

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31. The characteristic addition reactions of alkenes are mainly due to the presence of

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32. Dehydrohalogenation of a vicinal dihalide can prepare an alkyne when

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33. Consider these statements about alkene nomenclature.
I. The suffix indicates a carbon-carbon double bond.
II. The parent chain should include the bond.
III. The double bond is numbered to receive the highest possible locant.

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34. A table of hydrogenation changes is shown below.

Row Reactant type Hydrogenation product under complete saturation
P Alkene Alkane
Q Alkyne Alkane with sufficient
R Alkane Alkene by adding
S Unsaturated hydrocarbon More saturated hydrocarbon

The row that needs correction is

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35. A compound is called a hydrocarbon only when its composition is limited to which elements?

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36. Cold dilute alkaline reacts with an alkene to form

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37. In naming a branched alkane, the parent chain is selected as the

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38. A table compares roles in electrophilic addition of to an alkene.

Species or part Role
P. Alkene -bond electron-rich region
Q. electrophile
R. nucleophile
S. Carbocation electron-rich nucleophile

The entry that needs correction is

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39. A terminal alkyne and an internal alkyne both decolourise bromine solution, but only the terminal alkyne gives a precipitate with ammoniacal silver nitrate. The difference is due to

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40. An alkene can show cis-trans isomerism only when each double-bonded carbon has

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41. Reduction of an alkyl halide to an alkane mainly involves replacing the halogen atom by

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42. A hydrocarbon sample is described as a chain compound with one carbon-carbon triple bond. Its first broad placement should be

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43. The nitro group, , already present on a benzene ring generally directs further electrophilic substitution mainly to the

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44. A table compares possible monochlorination outcomes.

Alkane Key hydrogen environments Number of distinct monochloro products
P. all hydrogens equivalent
Q. all hydrogens equivalent
R. terminal and middle hydrogens differ
S. all hydrogens equivalent

The row that needs correction is

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45. Formula-and-hydrogenation clues show that hydrocarbon has molecular formula , consumes of per , and has no ring. The most suitable structural class of is

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46. A mechanism list contains these steps:
I.
II.
III.
The correct classification is

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47. In the conversion sequence , the reagents or conditions for the two steps are respectively

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48. A compact passage is given below.

Compound P has formula . Compound Q also has formula . P rapidly adds bromine under ordinary unsaturation-test conditions, while Q is a saturated ring hydrocarbon.

The comparison mainly shows that

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49. The relatively higher acidity of terminal alkynes compared with alkenes is mainly due to the

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50. Polynuclear aromatic hydrocarbons are best described as aromatic compounds that contain

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