Exam-Style Mock Test | Class 11 Chemistry: Hydrocarbons
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Hydrocarbons Mock Test – Class 11 Chemistry

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Hydrocarbons – Progressive Test

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1. Open-chain hydrocarbons such as straight-chain alkanes, alkenes, and alkynes are usually grouped under

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2. Markovnikov addition of to an unsymmetrical alkene is best interpreted as

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3. Complete combustion of of an open-chain alkane requires of . The alkane is

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4. A benzene ring already contains at position . If it undergoes chlorination under electrophilic substitution conditions, the major product is expected to have chlorine mainly at

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5. A desired alkane is propane, . Wurtz preparation from a single alkyl halide is not the best direct choice because

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6. The solvent most suitable for dissolving an alkane is generally

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7. Methane, , is used as a simple model for alkane bonding because its carbon atom

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8. Addition of to propene in the absence of peroxide mainly gives

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9. If benzene is converted first to nitrobenzene and then nitrated again, the main disubstituted product is

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10. In naming an alkene, the parent chain must be chosen so that it

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11. For straight-chain alkanes, the boiling point generally increases from methane to higher members because

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12. A claim says, “The formula proves a compound is but--yne.” The better conclusion is that

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13. A table compares roles in electrophilic addition of to an alkene.

Species or part Role
P. Alkene -bond electron-rich region
Q. electrophile
R. nucleophile
S. Carbocation electron-rich nucleophile

The entry that needs correction is

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14. Reductive ozonolysis gives two molecules of ethanal from hydrocarbon , and also has geometrical isomers. The most suitable identity of is

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15. A vicinal dibromide has the structure . Treatment with zinc dust gives

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16. A reagent list for converting an alkyl halide into an alkane includes

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17. The relatively higher acidity of terminal alkynes compared with alkenes is mainly due to the

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18. A table lists possible additions of hydrogen halides to alkenes.

Row Reaction condition Major orientation stated
P , no peroxide Markovnikov addition
Q , ordinary ionic condition Markovnikov addition
R , peroxide present anti-Markovnikov addition
S , peroxide present always anti-Markovnikov like

The row that needs correction is

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19. A compound decolourises both bromine water and dilute alkaline at room temperature. The most likely structural feature in is

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20. Ammoniacal silver nitrate can distinguish a terminal alkyne because a terminal alkyne forms

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21. Open-chain alkyne produces of on complete combustion of . Complete addition of bromine to the same amount of requires

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22. A reaction condition uses aqueous instead of alcoholic with an alkyl halide. The expected reaction tendency changes because aqueous more commonly favours

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23. Combustion results for hydrocarbon give of and of from of . It also consumes of per during complete hydrogenation. The formula of is

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24. A learner claims, “Every hydrocarbon with fewer hydrogen atoms than the corresponding alkane must behave like a simple alkene.” The best response is that

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25. Consider the following statements about hydrocarbon bonding.
I. Hydrocarbons contain covalent bonds.
II. Carbon atoms in hydrocarbons may join to other carbon atoms.
III. A hydrocarbon must contain oxygen if it is organic.

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26. A conformation record gives the following energy values for ethane:

Conformation Relative energy
P. Staggered
Q. Eclipsed

The rotational energy barrier from staggered to eclipsed is

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27. A record of alkane structures is shown below.

Row Molecular formula Number of chain isomer skeletons stated
P
Q
R
S

The row that needs correction is

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28. Nitration and flame observations identify compound , formula , which burns with a smoky flame and gives one mononitro product with . The most suitable identity is

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29. Among the following substances, the hydrocarbon is the one represented by

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30. In the name , the structural information is interpreted as

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31. Assertion: A methyl group directs incoming electrophiles mainly to ortho and para positions in benzene substitution.
Reason: The methyl group increases electron density at ortho and para positions through electron-releasing effects.

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32. A mixture of benzene and styrene, , contains total hydrocarbon. It consumes of in a rapid addition test and gives of on complete combustion. The moles of benzene in the mixture are

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33. Nitration of alkanes, when treated at the introductory level, is generally associated with

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34. A learner expects three different monobromobenzenes because benzene can be drawn with alternating double bonds. The best correction is that

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35. Ordinary and peroxide-controlled additions give different bromopropanes: without peroxide and with peroxide. The starting hydrocarbon is

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36. The balanced complete combustion equation for methane is

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37. A naming note gives two possible numberings for the same substituted alkane: substituent locants or . The preferred set is

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38. A reaction map is shown below.

Starting hydrocarbon Reagent or condition Expected main change
P. alkane formation
Q. cold alkaline vicinal diol formation
R. ethanal after tautomerism
S. bromine water only rapid ordinary alkene-type addition

The row that needs correction is

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39. A table compares alkyl halide conversion routes.

Row Starting compound Condition Main hydrocarbon outcome
P
Q
R reducing condition halogen replaced by hydrogen
S reducing condition as the alkane product

The row that needs correction is

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40. A Newman projection of ethane is drawn by looking

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41. The decolourisation of dilute alkaline by an alkene is used as a test for

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42. A molecule written as contains only carbon and hydrogen. At this stage, the safest classification from composition alone is that it is

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43. The expression “carbon skeleton” in a hydrocarbon mainly refers to

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44. An alkyne sample of reacts completely with excess bromine to form a tetrabromoalkane and consumes of . On combustion, the same amount of gives of . The molecular formula of is

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45. The pair and is best described as

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46. Ethyne reacts with sodium metal to form sodium acetylide and hydrogen gas. The reaction is best represented as

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47. A compound is heated with alcoholic . The alkene formed is

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48. A hydrocarbon has one tertiary hydrogen and nine primary hydrogens. On radical bromination, the major monobromo product is expected from replacement of

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49. In comparing ethene, propene, and butene under ordinary physical-property trends, the strongest reason for increasing boiling point is the increase in

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50. A graph compares relative reaction rate for electrophilic substitution of three aromatic compounds: toluene, benzene, and nitrobenzene. The highest bar should correspond to

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