Class 11 Physics: Oscillations Mock Test | Exam Bashed
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Oscillations Mock Test – Class 11 Physics

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Oscillations – Progressive Test

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1. Study the table of formula-use conditions.

Row Formula Condition or meaning
P Simple pendulum with small angular displacement
Q Ideal spring SHM with no mechanical energy loss
R Linear restoring force in Hooke's-law range
S Speed at every point of SHM

The row that needs correction is

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2. The relation connecting angular frequency and ordinary frequency is best completed as .

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3. A seconds pendulum is one whose time period is

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4. A body in SHM has maximum acceleration magnitude and amplitude . Its angular frequency is

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5. A lightly damped oscillator has an graph whose successive positive peaks decrease in height, but the time gaps between successive peaks remain nearly equal. This graph shows that

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6. In the small-angle derivation of the simple pendulum, the tangential acceleration is related to arc displacement by

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7. A spring oscillator has total energy . At a certain instant, its potential energy is equal to its kinetic energy. The speed at that instant is

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8. For a physical pendulum with moment of inertia about the suspension axis and centre of mass at distance from the axis, the small-oscillation period is

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9. A pendulum of length is inside an elevator. In Case 1, the elevator is at rest. In Case 2, it accelerates upward with . Take . The ratio is

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10. Use the graph description below.

For a simple pendulum at a fixed place, is plotted against length . The graph is a straight line through the origin.

The slope of the graph is

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11. The approximation used in the simple pendulum derivation requires to be measured in

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12. Study the table and identify the row that gives the most suitable restoring-tendency description.

Row Displacement from mean position Restoring tendency
P To the right Toward the right
Q To the right Toward the left
R To the left Toward the left
S On either side Away from the mean position

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13. If the amplitude of an ideal spring oscillator is doubled while remains unchanged, the total energy becomes

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14. Use the graph description below.

For a SHM particle, the graph is at a positive maximum at . The motion follows .

At , the corresponding and graph values are

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15. A SHM particle has and . The amplitudes of its and graphs are respectively

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16. A SHM particle starts from the positive extreme position. After , it will be at

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17. Study the table for an ideal horizontal spring-block oscillator.

Row Change made Effect on
P Mass is made , unchanged becomes
Q Spring constant is made , unchanged becomes
R Amplitude is doubled in ideal range remains unchanged
S Mass and spring constant are both made times becomes

The row that needs revision is

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18. In a damped oscillator, the amplitude gradually decreases mainly because

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19. For , the velocity of the oscillator is

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20. A spring oscillator has total energy . At a certain position, . The magnitude of displacement at that position is

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21. Read the situation below and answer the question.

A particle in SHM is at . In one observation it is moving toward the positive extreme. In another observation at the same , it is moving back toward the mean position.

The two observations have

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22. A block of mass is attached to two identical springs in series, each of force constant . The time period of small oscillations is

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23. Use the graph description below.

For an ideal spring oscillator, and are plotted against time. Both curves are always non-negative, and whenever one curve is maximum, the other is zero. Their sum is a horizontal line.

The correct interpretation of the graph is

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24. A rotating fan blade seen at a fixed mark crosses the mark at regular intervals. The crossing pattern is periodic because

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25. In SHM, the magnitude of acceleration is maximum when the body is

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26. A displacement-time record shows that an oscillator crosses the mean position many times, but the peak displacement after each crossing is smaller than before. The motion is best classified as

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27. A pendulum of length is in a lift accelerating upward with acceleration . Its small-oscillation period compared with its period in a stationary lift is

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28. A forced oscillator is driven at angular frequency , while its natural angular frequency is . The resonance condition is approximately

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29. Study the table for energy in ideal SHM.

Row Position Kinetic energy Potential energy
P Mean position Maximum Minimum
Q Extreme position Zero Maximum
R Between mean and extreme Nonzero Nonzero
S Every position Maximum Maximum

The row that is not compatible with ideal SHM is

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30. A mass-spring system is pulled farther from its equilibrium position before release, while the spring remains in its ideal range. The immediate effect on amplitude is that it

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31. A spring oscillator has . At a certain displacement, its kinetic energy is three times its potential energy. The potential energy at that instant is

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32. Use the graph description below.

A SHM displacement-time graph has a horizontal tangent at a positive crest. The graph then descends and crosses the mean line.

At the positive crest, the velocity and acceleration are best described as

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33. For a simple pendulum of length making small oscillations near Earth’s surface, the time period is

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34. A body has acceleration , where is displacement from the mean position. The motion is simple harmonic because

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35. A body in SHM has displacement and angular frequency . Its acceleration is

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36. Use the graph description below.

For an ideal spring oscillator, , , and total energy graphs are drawn on the same axes.

The total energy graph should appear as

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37. A note says: “Resonance occurs whenever an oscillator is forced, and damping only changes the period.” The best correction is that

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38. A body passes through its mean position during an oscillation. At that instant, its displacement from the mean position is

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39. A body in SHM has . When its displacement is , its acceleration is

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40. A pendulum has period in a stationary lift. The lift then accelerates upward with acceleration . The new period is

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41. A block attached to an ideal spring on a smooth horizontal surface has amplitude . If its amplitude is changed to without changing or , the quantity that changes is

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42. A simple pendulum has time period at a place where gravitational acceleration is . At another place, becomes , while the length is unchanged. The new time period is

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43. A pendulum has length . Another pendulum at the same place has length . The ratio of their frequencies is

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44. Use the graph description below.

The displacement-time graph of an oscillator reaches positive maxima at , , and . The shape of the graph repeats between successive positive maxima.

The angular frequency of the oscillator is

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45. The graph of speed against displacement for ideal SHM is described by . The graph in the allowed interval is best described as

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46. A body in SHM has . When the body is at , the magnitude of its acceleration is

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47. Assertion: Increasing damping can make a resonance curve less sharp.
Reason: Greater damping dissipates more energy and reduces the ability of the oscillator to build a large response near one frequency.

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48. A final rescue-check statement says: “In oscillations, the same formula can always be used if the motion is repeated.” The best correction is that formula choice depends on

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49. A spring oscillator has total energy , mass , and spring constant . At a certain instant its potential energy is . The speed of the block at that instant is

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50. A physical pendulum has , , and . Its equivalent simple pendulum length is

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