Oscillations Mock Test – Class 11 Physics

1. A pendulum of length is in a lift accelerating upward with acceleration . Its small-oscillation period compared with its period in a stationary lift is

2. For a spring oscillator, and repeat their values twice during each complete displacement cycle. This happens because

3. The elastic potential energy of a spring oscillator displaced by from equilibrium is

4. A block of mass is attached to two springs in parallel with force constants and . The time period of small horizontal oscillations is

5. A spring oscillator has , , and total energy . Its amplitude is

6. For a linear oscillator obeying , the constant represents

7. A SHM particle moving from the mean position to the positive extreme covers the first half of the displacement, from to , in time , and the second half, from to , in time . The correct comparison is

8. A lightly damped oscillator is driven at resonance. The amplitude does not become infinite in a real system because

9. A table compares speed and displacement in SHM.

The row that is not compatible with ideal SHM is

10. A spring oscillator of mass has speed at a certain instant. Its kinetic energy then is

11. A graph is plotted between acceleration and displacement for a body in SHM. The graph is a straight line through the origin with negative slope. The slope represents

12. A spring oscillator has , , and total mechanical energy . When the block is at and moving toward the mean position, its velocity is

13. A SHM particle has time period . The time interval between a mean-position crossing and the next extreme position is

14. A displacement equation is , where is in and is in . The maximum speed is

15. The slope of a velocity-time graph for a SHM particle gives

16. Use the arrangement described below. A point moves anticlockwise with uniform angular speed on a reference circle. Its projection on the horizontal diameter gives SHM with . When the rotating radius makes from the positive horizontal direction, the projection has

17. The amplitudes of the , , and graphs for a SHM particle are respectively

18. A spring is stretched by and exerts a restoring force of magnitude . The force constant of the spring is

19. A driven oscillator is operating at resonance. If damping is made larger while the driving force amplitude remains the same, the maximum steady amplitude generally

20. A spring oscillator has total energy . At one instant its potential energy is . The kinetic energy at that instant is

21. A spring oscillator has amplitude . At one instant the kinetic energy is of the total energy. The magnitude of displacement at that instant is

22. A forced oscillator is driven at angular frequency , while its natural angular frequency is . The resonance condition is approximately

23. A note about an oscillator says: “The body is at the extreme position when .” This statement means that

24. A torsional pendulum has restoring torque . The SI unit of is

25. The potential energy graph is symmetric about . This symmetry means that

26. A displacement is given by , where is in and is in . At , the initial velocity and initial acceleration are respectively

27. A simple pendulum is to have its time period reduced to half at the same place. Its length should be changed to

28. A tuning fork can make a nearby air column sound loudly when its frequency matches one of the air column’s natural frequencies. This large response is an example of

29. A body has acceleration , where is displacement from the mean position. The motion is simple harmonic because

30. A spring oscillator has total energy . At a certain position, . The magnitude of displacement at that position is

31. Study the table for a simple pendulum performing small oscillations.

The row that needs correction is

32. A torsional pendulum executes angular oscillations because a twisted wire provides a restoring torque. If , the negative sign shows that the torque

33. Read the situation below and answer the question.

The two observations have

34. A spring oscillator has total energy . When , the kinetic energy is

35. A mass hangs from a vertical spring of force constant . The static extension of the spring at equilibrium is

36. A solution satisfies the SHM differential equation because its second derivative is

37. For a set of spring-block systems with the same mass , is plotted against . The graph is a straight line through the origin. Its slope is

38. A pendulum clock has correct period at a place where gravitational acceleration is . It is taken to a place where gravitational acceleration is . To keep the same period, the new length should be

39. A particle executing moves from to for the first time after starting from the mean position. The time taken for this part is

40. A spring oscillator has . At a certain displacement, its kinetic energy is three times its potential energy. The potential energy at that instant is

41. Two springs of force constants and are connected in series to a block of mass . The time period of small oscillations is

42. A student says, “Since SHM can be obtained from uniform circular motion, the SHM particle must also have constant speed.” The best correction is that

43. Study the table for an ideal horizontal spring-block oscillator.

The row that needs revision is

44. For a block of mass attached to an ideal spring of force constant , the time period of horizontal oscillations is

45. For the projection of uniform circular motion, the acceleration of the projection is

46. A body executes SHM with amplitude . The distance travelled in one complete oscillation, starting from an extreme position, is

47. A pendulum clock runs correct at a place where . It is taken to a place where , and its length is not changed. The clock

48. In SHM, the acceleration-displacement graph is useful because it directly shows

49. In an ideal spring oscillator, . The potential energy varies with time as

50. A horizontal spring-block system on a frictionless surface executes SHM mainly because the spring force