Class 11 Physics: Oscillations Mock Test | Exam Bashed
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Oscillations Mock Test – Class 11 Physics

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Oscillations – Progressive Test

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1. A SHM particle is at the mean position at and starts moving in the negative direction. A suitable displacement equation is

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2. In a spring oscillator, the kinetic energy at displacement can be written as

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3. A physical pendulum has moment of inertia , mass , and centre-of-mass distance from the suspension axis. If the suspension axis is moved so that becomes smaller while about the new axis is assumed unchanged, the period tends to

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4. A spring oscillator has , , and it passes through the mean position with speed . Its amplitude is

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5. In SHM, the acceleration-displacement graph is useful because it directly shows

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6. A final synthesis record gives these statements.
I. The projection of uniform circular motion on a diameter can represent SHM.
II. In ideal spring SHM, total energy is proportional to .
III. A simple pendulum follows exactly for all amplitudes.
IV. Resonance response is limited in real systems by damping.
The valid statements are

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7. A driven oscillator is tested with three different damping settings. The resonance curve is sharp and tall for setting P, broader and lower for setting Q, and almost flat for setting R. The damping is greatest in

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8. For a simple pendulum, the angular frequency for small oscillations is

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9. A body passes through its mean position during an oscillation. At that instant, its displacement from the mean position is

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10. For an oscillator with time period , the frequency is

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11. A damped oscillator has initial amplitude . After several oscillations, its amplitude is . If the oscillator behaves like a spring system with the same force constant, the ratio of its mechanical energy then to its initial energy is

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12. A learner writes that and are the same because both describe “how fast oscillation happens.” The best correction is that

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13. A torsional pendulum executes angular oscillations because a twisted wire provides a restoring torque. If , the negative sign shows that the torque

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14. A SHM particle starts from the positive extreme position. After , it will be at

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15. A final rescue-check statement says: “In oscillations, the same formula can always be used if the motion is repeated.” The best correction is that formula choice depends on

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16. A SHM particle moves from the positive extreme position to the mean position. The time taken is

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17. A mass is attached to a vertical spring and released from the spring’s natural length position. If the static extension is , and damping is negligible, the amplitude of the resulting vertical oscillation about the new equilibrium is

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18. A displacement equation is , where is in and is in . At , the displacement is

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19. A displacement equation is , with in and in . At , the displacement, velocity, and acceleration are respectively

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20. Assertion: Uniform circular motion is periodic.
Reason: In uniform circular motion, the body returns to the same position after every fixed time interval.

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21. Match the mathematical statement with its physical meaning.

Column I Column II
P. 1. Mean position
Q. 2. Restoring acceleration condition
R. 3. Differential equation of SHM
S. 4. Extreme position

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22. Two oscillators have frequencies and . The ratio of their time periods is

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23. A body oscillates between two extreme positions separated by . Its amplitude is

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24. A spring oscillator has and amplitude . At the instant when kinetic energy equals potential energy, the magnitude of displacement is

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25. Consider the following statements about phase in harmonic motion.
I. Phase tells the stage of oscillation.
II. Initial phase depends on the chosen starting instant and representation.
III. Same displacement always means same direction of motion.
Select the valid set.

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26. Assertion: A stable equilibrium position can act as the mean position for oscillations.
Reason: Near stable equilibrium, a small displacement usually gives a restoring tendency toward the equilibrium position.

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27. Read the situation below and answer the question.

Two particles execute SHM with the same amplitude . Particle P starts from the positive extreme and completes one full oscillation. Particle Q starts from the mean position, reaches the positive extreme, returns through the mean position, reaches the negative extreme, and comes back to the mean position.

The distances travelled by P and Q are respectively

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28. A spring oscillator has total energy , mass , and angular frequency . Its amplitude is

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29. Study the table about a seconds pendulum.

Row Statement Decision
P Full time period is Correct
Q Time from one extreme to the other is Correct
R Approximate length near Earth is Correct
S Full time period is Correct

The row that needs correction is

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30. A one-dimensional motion is described by . The time period of the motion is

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31. Study the table and identify the row that correctly reads the equation , where is in and is in .

Row Amplitude Angular frequency Initial phase
P
Q
R
S

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32. For a simple oscillator, and represent

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33. A simple pendulum has period in a stationary lift. The lift then accelerates downward with acceleration . The new period is

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34. A spring oscillator has total energy . At one instant its potential energy is . The kinetic energy at that instant is

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35. The phase in is dimensionless because

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36. A light spring-mass oscillator has natural angular frequency . If the mass is made and the same spring is used, the new natural angular frequency is

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37. The statement “damping always changes an oscillator’s amplitude but has no connection with energy” is best corrected by saying that damping

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38. The initial phase in represents

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39. Use the graph description below.

For a simple pendulum at a fixed place, is plotted against length . The graph is a straight line through the origin.

The slope of the graph is

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40. A spring oscillator has amplitude . Its maximum potential energy is

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41. For a spring oscillator, the potential energy at and is

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42. A signal repeats its entire pattern every . Its time period and frequency are respectively

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43. The motion of a simple pendulum with a large angular amplitude is not exactly SHM mainly because

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44. An oscillator has frequency . Its time period is

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45. A spring oscillator has and amplitude . The maximum elastic potential energy is

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46. A particle executes . The time taken to go from while moving in the positive direction to while moving in the negative direction is

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47. A torsional pendulum has time period and moment of inertia . Taking , its torsional constant is

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48. A body of mass moves under a force , where is in and is in . Its angular frequency is

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49. A student says, “Since SHM can be obtained from uniform circular motion, the SHM particle must also have constant speed.” The best correction is that

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50. Two spring-mass systems have the same mass, but spring has a larger force constant than spring . If both behave ideally, spring gives

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