Class 11 Physics: Thermodynamics Mock Test | Exam Bashed
GKaim: Measure | Improve | Achieve

Thermodynamics Mock Test – Class 11 Physics

Progressive Test — Guest First Round

0%

Thermodynamics – Progressive Test

Welcome to the Progressive Test.

Click Start Test to begin the loaded practice round.

Good luck!

1 / 50

1. In a piston-cylinder system, the gas pressure is , and the piston moves outward so that the volume increases by at approximately constant pressure. The work done by the gas is

2 / 50

2. For a fixed amount of ideal gas heated at constant pressure from to , its volume

3 / 50

3. A derivation note is shown below.

For moles of an ideal gas heated at constant pressure, . The internal-energy change is . The work done is .

Using the first law , the note leads to

4 / 50

4. The derivation of for an ideal gas uses the fact that constant-pressure expansion work for a temperature change is

5 / 50

5. A gas is heated at constant volume and receives of heat. What is the change in internal energy?

6 / 50

6. A note says, “Since , its value can be used without specifying the kind of gas or the model.” The best correction is:

7 / 50

7. A closed system receives of heat. Its internal energy increases by . What work is done by the system?

8 / 50

8. A gas loses of heat to the surroundings while of work is done on the gas. Using , find .

9 / 50

9. A heat pump supplies heat to a warm room by taking heat from a cold outside region and using work . Its coefficient of performance as a heat pump is

10 / 50

10. A heat engine operating between and rejects of heat per cycle. If it were Carnot, the heat absorbed would be

11 / 50

11. A refrigerator and a heat pump operate reversibly between the same two reservoirs and , where . If the refrigerator coefficient of performance is and heat-pump coefficient of performance is , then

12 / 50

12. A thermometer is first placed in a beaker of water and later in an oil bath. In both cases, the final steady reading is . What would happen if the water and oil were brought into thermal contact under these conditions?

13 / 50

13. A substance has specific heat capacity and molar mass . Its molar heat capacity for the same process is

14 / 50

14. An ideal gas with and expands adiabatically from to . The work done by the gas is

15 / 50

15. A reversible heat pump works between outside and inside. If it delivers of heat to the room, the work input and heat taken from outside are respectively

16 / 50

16. Use the graph description below.

For a fixed amount of ideal gas, a graph of internal energy on the vertical axis against absolute temperature on the horizontal axis is shown as a rising straight line.

The graph mainly represents that

17 / 50

17. Use the graph description below.

For a fixed -mole sample undergoing a specified process, a graph of heat supplied on the vertical axis against temperature rise on the horizontal axis is a straight line through the origin.

If the process has molar heat capacity , the slope of the graph is

18 / 50

18. A refrigerator removes of heat from its cold chamber in one cycle and requires of work input. Its coefficient of performance is

19 / 50

19. A gas does of work while its internal energy decreases by . The heat for the process is

20 / 50

20. Assertion: A quasistatic process can be represented by a smooth path on a - diagram.
Reason: The system has well-defined thermodynamic variables at each stage of a quasistatic process.

21 / 50

21. A reversible adiabatic expansion of an ideal gas has , , and . The final temperature is

22 / 50

22. An adiabatic compression raises the temperature of of an ideal gas from to . If , the work done by the gas is

23 / 50

23. For a reversible adiabatic process of an ideal gas, a useful temperature-volume relation is

24 / 50

24. A gas is heated at constant pressure, and its temperature rises. The relation for gases is mainly because

25 / 50

25. A process has and . Using , the change in internal energy is

26 / 50

26. Thermodynamics is most directly concerned with the relation among which physical ideas?

27 / 50

27. A ideal gas at expands isothermally from to , then is compressed adiabatically back to volume . If , , and , the net work done by the gas over the two steps is closest to

28 / 50

28. A cyclic device takes from a cold body and rejects to a hot body. The most suitable interpretation is

29 / 50

29. A gas is taken through the following two-step process: Step P is isochoric heating from to , and Step Q is isothermal expansion at . For the whole two-step process, the internal-energy change of the ideal gas is determined by

30 / 50

30. A proposed engine absorbs from a reservoir at , rejects to a reservoir at , and produces of work. Which judgement is most suitable?

31 / 50

31. Two isothermal expansions of the same ideal gas start at the same temperature. In Case P, the volume changes from to . In Case Q, it changes from to . The ratio of works is

32 / 50

32. No engine operating between the same two reservoirs can be more efficient than a Carnot engine because the Carnot engine is

33 / 50

33. A refrigerator has and removes of heat from the cold chamber in each cycle. The work input required per cycle is

34 / 50

34. A Carnot engine works between and . If a real engine between the same reservoirs claims efficiency, the claim is

35 / 50

35. A gas sample has , , and . Using , the number of moles is

36 / 50

36. Specific heat capacity of a substance is the heat required

37 / 50

37. A full formula check gives the following entries.

Entry Statement
P and depend on path, while depends only on end states.
Q applies to any insulated expansion, reversible or not.
R for a refrigerator.
S can be calculated directly with Celsius temperatures.

The correct entry is

38 / 50

38. A fixed ideal gas is taken through a process in which , , and for of gas. The temperature change is

39 / 50

39. For a Carnot engine, the ratio of heat rejected to heat absorbed is related to reservoir temperatures by

40 / 50

40. A Carnot cycle consists of which sequence of reversible processes?

41 / 50

41. Assertion: A real process involving heat flow through a finite temperature difference is irreversible.
Reason: The reverse transfer from colder body to hotter body would not occur by itself without some additional effect.

42 / 50

42. A gas in a closed vessel is at rest as a whole, but its molecules are moving randomly. The energy connected with this random molecular motion contributes to

43 / 50

43. A Carnot engine is best described as

44 / 50

44. A fixed amount of ideal gas expands isothermally and does of work. Using , the heat supplied to the gas is

45 / 50

45. The SI unit of the gas constant in is obtained as

46 / 50

46. Use the arrangement described below: a gas in a cylinder is compressed once by a rough piston and once by a frictionless piston, both very slowly. The two paths have the same initial and final volumes.
The rough-piston process is less reversible mainly because

47 / 50

47. Study the table and identify the row in which both classifications are correct.

Row Extensive variable Intensive variable
P
Q
R
S Density Mass

48 / 50

48. A proposed refrigerator removes from a cold chamber and rejects to a hotter room with no work input. The proposal is impossible mainly because

49 / 50

49. Use the arrangement described below: a gas is enclosed in a cylinder with a frictionless movable piston. In Case 1, the piston is moved outward very slowly by reducing the external pressure in tiny steps. In Case 2, the piston is suddenly released against a much lower external pressure. The better comparison is

50 / 50

50. A smooth - curve is normally drawn for a quasistatic process because

Your score is

Share your achievement!

LinkedIn Facebook
0%

Complete 100% of the Progressive Test coverage to unlock Mistake Review.
Complete 100% of the Progressive Test coverage to unlock Certificate Challenge.

Subscribe
Notify of
guest
0 Comments
Scroll to Top