Class 11 Physics: Thermodynamics Mock Test | Exam Bashed
GKaim: Measure. Improve. Achieve.

Thermodynamics Mock Test – Class 11 Physics

Progressive Test — Guest First Round

0%

Thermodynamics – Progressive Test

Welcome to the Progressive Test.

Click Start Test to begin the loaded practice round.

Good luck!

1 / 50

1. A claim says, “A refrigerator with coefficient of performance greater than violates energy conservation because it removes more heat than the work supplied.” The best correction is:

2 / 50

2. Assertion: For a gas, is usually greater than .
Reason: For gases, because constant-pressure heating includes expansion work.

3 / 50

3. A proposed shortcut says, “For any ideal-gas expansion, compare only the initial and final volumes to decide the work.” The best correction is:

4 / 50

4. A final comparison table is checked for process conditions and energy results.

Row Process Condition Energy result for ideal gas where applicable
P Isothermal ideal gas
Q Adiabatic process
R Isochoric process
S Cyclic process final state initial state

The accurate judgement is

5 / 50

5. For isothermal expansion of a fixed amount of ideal gas from to , the work done by the gas is

6 / 50

6. The SI unit of the gas constant in is obtained as

7 / 50

7. A proposed engine between and has efficiency . The proposal is best judged as

8 / 50

8. A graph is described below.

The horizontal axis represents time . The vertical axis represents the readings of two thermometers placed in two bodies kept in thermal contact. One curve decreases, the other increases, and the two curves finally meet at a common steady value.

What does the common steady value represent?

9 / 50

9. A proposed cyclic heat engine receives from a hot reservoir, rejects no heat, and delivers of work. The proposal

10 / 50

10. A refrigerator extracts from a cold chamber and rejects to the surroundings in one cycle. The work input is

11 / 50

11. A Carnot engine and a Carnot refrigerator operate between the same reservoirs at and . The engine efficiency and refrigerator COP are respectively

12 / 50

12. A gas follows two reversible expansion paths from the same initial state to the same final volume: one is isothermal and the other is adiabatic. The work done is larger for the isothermal path because

13 / 50

13. In an isobaric expansion, the rectangular area under the horizontal line on a - graph equals

14 / 50

14. Assertion: When a hot cup is placed in a cooler room, heat transfer is from the cup to the room.
Reason: Heat transfer across a boundary occurs due to temperature difference and naturally proceeds from higher temperature to lower temperature in ordinary thermal contact.

15 / 50

15. A triangular - cycle has vertices , , and . The cycle is traversed . The net heat supplied in one cycle is

16 / 50

16. A reversible adiabatic compression of an ideal gas changes its volume from to . If , the pressure ratio is

17 / 50

17. A gas is cooled at constant volume, and of heat leaves the gas. Using , the work done by the gas and the change in internal energy are respectively

18 / 50

18. A heat engine absorbs , rejects , and delivers work . A refrigerator removes heat from a cold chamber and needs work input . The row that gives dimensionless performance ratios is

19 / 50

19. A process record says: , , and the gas is ideal with . The temperature change of the gas is

20 / 50

20. Assertion: Internal energy is a state function.
Reason: The change in internal energy between two equilibrium states depends only on those states, not on the path joining them.

21 / 50

21. A ideal gas is compressed isothermally at from to . Take and . The heat supplied to the gas is closest to

22 / 50

22. A thermodynamic path is drawn as a vertical line upward on a - graph. For a fixed ideal gas, the process represented is

23 / 50

23. A gas absorbs of heat and does of work on the surroundings. Using , what is ?

24 / 50

24. Work in thermodynamics is most directly associated with energy transfer caused by

25 / 50

25. Two isothermal expansions of the same ideal gas start at the same temperature. In Case P, the volume changes from to . In Case Q, it changes from to . The ratio of works is

26 / 50

26. A gas sample is heated at constant pressure. If and , the heat supplied is

27 / 50

27. A cup of tea and the surrounding air are at the same temperature. Which statement follows most directly?

28 / 50

28. A gas in a closed vessel is at rest as a whole, but its molecules are moving randomly. The energy connected with this random molecular motion contributes to

29 / 50

29. Consider the following statements about an isothermal process of a fixed amount of ideal gas.
I. remains constant.
II. .
III. Heat exchange must be zero.

30 / 50

30. Use the graph description below.

A Carnot engine cycle is drawn on a - diagram. The upper curve is an isothermal expansion at , followed by an adiabatic expansion to a lower isotherm at . The lower curve is an isothermal compression at , followed by an adiabatic compression back to the start.

The net work output of the engine is represented by

31 / 50

31. Study the table and identify the row that best represents complete thermodynamic equilibrium.

Row Temperature condition Mechanical condition Chemical condition
P No temperature gradient No unbalanced pressure No ongoing macroscopic chemical change
Q Temperature gradient present No unbalanced pressure No chemical change
R No temperature gradient Piston accelerating No chemical change
S No temperature gradient No unbalanced pressure Reaction proceeding visibly

32 / 50

32. During a reversible adiabatic compression, an ideal gas changes from to . If , the work done by the gas is

33 / 50

33. A sample is doubled by adding an identical sample at the same pressure and temperature. Which set shows the variables that double?

34 / 50

34. Heat , work , and internal energy share the feature that they are

35 / 50

35. Study the table and select the row that matches the usual ideal-gas values.

Row Gas type
P Monatomic ideal gas
Q Monatomic ideal gas
R Diatomic ideal gas near room temperature
S Diatomic ideal gas near room temperature

36 / 50

36. A fixed amount of ideal gas is taken through a cycle consisting of an isobaric expansion, an isochoric cooling, and a return path. Over the complete cycle, the internal energy change is

37 / 50

37. The zeroth law is placed before the first law in logical importance because it

38 / 50

38. Use the arrangement described below: a gas in a cylinder is compressed once by a rough piston and once by a frictionless piston, both very slowly. The two paths have the same initial and final volumes.
The rough-piston process is less reversible mainly because

39 / 50

39. A gas is taken from state to state by two paths. Along Path P, and . Along Path Q, and . Using , what is the value of for the change from to ?

40 / 50

40. A note says, “Since , its value can be used without specifying the kind of gas or the model.” The best correction is:

41 / 50

41. Use the table below and select the row that correctly compares isothermal and adiabatic ideal-gas processes.

Row Isothermal ideal gas Adiabatic process
P , ,
Q , ,
R always
S Heat exchange impossible Temperature cannot change

42 / 50

42. For a fixed amount of ideal gas undergoing an isothermal process, the change in internal energy is zero because

43 / 50

43. A heat pump delivers of heat to a room while consuming of work. Its coefficient of performance is

44 / 50

44. The statement “heat cannot flow from cold to hot” is incomplete because

45 / 50

45. A metal block at is placed in contact with another block at . Before thermal equilibrium is reached, heat transfer is mainly from

46 / 50

46. Internal energy of a gas refers mainly to

47 / 50

47. Friction makes a mechanical thermodynamic process irreversible because it

48 / 50

48. A Carnot engine operates between and . A Carnot refrigerator operates between the same two reservoirs. The refrigerator COP and engine efficiency are respectively

49 / 50

49. The molar heat capacity at constant volume, , is defined by

50 / 50

50. A vertical line on a - graph represents an isochoric process because

Your score is

Share your achievement!

LinkedIn Facebook
0%

Complete at least one Progressive Test round with incorrect or unanswered questions to unlock Mistake Review.
Complete at least 25% of the Progressive Test to unlock the Certificate Challenge Section.
Subscribe
Notify of
guest
0 Comments
Scroll to Top