Again 100 Structural Organisation In Animals MCQs | Biology
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Structural Organisation in Animals MCQs with Answers – Part 3 (Class 11 Biology)

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201. An earthworm is transferred from moist soil to a dry surface while air remains available. If water loss from the skin is not prevented, the most likely early consequence is:
ⓐ. reduced skin gas exchange as surface moisture is lost
ⓑ. increased diffusion as the body surface becomes drier
ⓒ. replacement of the skin by specialised respiratory organs
ⓓ. direct delivery of oxygen through nephridial tubules
202. Equal earthworms are placed at the same temperature and oxygen concentration. Group P remains on moist soil, while Group Q is placed on a drying surface. Over time, Q shows a marked decline in oxygen uptake, whereas P does not. The strongest inference is:
ⓐ. soil particles manufacture oxygen for Group P
ⓑ. specialised lungs become inactive in Group Q
ⓒ. blood vessels function only in wet soil
ⓓ. moist skin supports cutaneous gas exchange
203. Assertion: An earthworm can respire without possessing a specialised respiratory organ. Reason: Its moist body surface serves as the diffusion boundary through which gases enter or leave the bloodstream.
ⓐ. Assertion is true; Reason is true; explanatory link is valid
ⓑ. Assertion is true; Reason is true; explanatory link is invalid
ⓒ. Assertion is true; Reason is false; explanatory link is invalid
ⓓ. Assertion is false; Reason is true; explanatory link is invalid
204. A harmless coating keeps an earthworm’s surface moist but is nearly impermeable to respiratory gases. The hearts continue beating and the blood glands remain functional. The most likely outcome is:
ⓐ. improved oxygen entry due to reduced water loss
ⓑ. impaired gas exchange despite continued surface moisture
ⓒ. normal respiration since circulation alone supplies oxygen
ⓓ. increased oxygen uptake through the alimentary canal
205. Link each nephridial type with its characteristic location and route. Each Column II entry is used once.
Column IColumn II
P. Septal nephridiaW. Three paired tufts in segments \(4\), \(5\), and \(6\)
Q. Integumentary nephridiaX. Segment \(15\) to the last; discharge into the intestine
R. Pharyngeal nephridiaY. Segment \(3\) to the last; discharge outside
ⓐ. P-Y, Q-W, R-X
ⓑ. P-W, Q-X, R-Y
ⓒ. P-X, Q-Y, R-W
ⓓ. P-X, Q-W, R-Y
206. The nephridial records are shown below.
TypeRecorded locationRecorded outlet
P. SeptalSegment \(15\) to the lastIntestine
Q. IntegumentarySegment \(3\) to the lastBody exterior
R. PharyngealSegments \(4\), \(5\), and \(6\)Three paired tufts
S. SeptalSegments \(4\text{–}6\)External nephridiopores
The record requiring correction is:
ⓐ. Record S
ⓑ. Record P
ⓒ. Record Q
ⓓ. Record R
207. Damage is confined to segments \(4\text{–}6\) of an earthworm and destroys the paired nephridial tufts associated with the pharyngeal region. Which nephridial type is affected most directly?
ⓐ. septal nephridia extending from segment \(15\) backward
ⓑ. integumentary nephridia distributed through the body wall
ⓒ. pharyngeal nephridia occurring as anterior paired tufts
ⓓ. intestinal caeca arising at segment \(26\)
208. Read the arrangement described below. Set P is attached to septa from segment \(15\) backward and drains into the intestine. Set Q lies in the body wall from segment \(3\) backward and opens outside. Set R forms three paired anterior tufts. The correct identities are:
ⓐ. P integumentary; Q septal; R pharyngeal
ⓑ. P septal; Q integumentary; R pharyngeal
ⓒ. P pharyngeal; Q integumentary; R septal
ⓓ. P septal; Q pharyngeal; R integumentary
209. Let \(E\) represent nephridia whose waste route enters the digestive tube and \(X\) represent nephridia whose route opens directly outside. If \(S\) denotes septal nephridia and \(I\) denotes integumentary nephridia, the valid relation is:
ⓐ. \(S \in X\) and \(I \in E\)
ⓑ. \(S \in E\) and \(I \in E\)
ⓒ. \(S \in X\) and \(I \in X\)
ⓓ. \(S \in E\) and \(I \in X\)
210. Order the general stages of nephridial processing in an earthworm. P. Waste-containing material is conveyed through the nephridial tubule. Q. Excess coelomic fluid enters the nephridial funnel. R. Material is discharged through an external pore or into the digestive tube.
ⓐ. \(Q \rightarrow P \rightarrow R\)
ⓑ. \(P \rightarrow Q \rightarrow R\)
ⓒ. \(R \rightarrow Q \rightarrow P\)
ⓓ. \(Q \rightarrow R \rightarrow P\)
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