Coordination Compounds Mock Test

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Quiz: Coordination Compounds – Progressive Test
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1 / 50

1. The pair and differs because:

a) sulphur and nitrogen are alternative donors of one ligand

b) the thiocyanate ligand becomes bidentate in one form

c) one compound contains a counter ion and the other does not

d) the metal has different coordination numbers

2 / 50

2. Ammonia can coordinate through nitrogen, whereas normally cannot coordinate through nitrogen. The best explanation is that:

a) ammonia is negatively charged but is neutral

b) ammonia has more nitrogen atoms than

c) has a free lone pair; has none

d) has an empty orbital but ammonia does not

3 / 50

3. A member of the cobalt(III) ammine series has the general formula

where may have values from to . The total number of dissolved species produced per formula unit on ideal dissolution is:

4 / 50

4. The ligand names for , , , and , in that order, are:

a) amine, hydro, carbonato, nitrato

b) ammine, aquato, carbonato, nitro

c) amino, aqua, carbonyl, nitrido

d) ammine, aqua, carbonyl, nitrosyl

5 / 50

5. In the neutral metal carbonyl , the oxidation state of nickel is:

6 / 50

6. Two compounds have the same overall composition, but a bromido ligand inside the coordination sphere of one compound is a bromide counter ion in the other. Before any stereochemical counting, the pair should be classified as:

a) geometrical isomers

b) optical isomers

c) rotated forms of one structure

d) structural isomers

7 / 50

7. The spin-only magnetic moment of a low-spin octahedral complex is approximately:

8 / 50

8. A coordination compound is known to be octahedral, low spin, coloured, and stabilised by before pairing terms are considered. Which theory provides the most direct unified explanation of the last three properties?

a) simple ionic theory

b) crystal-field model

c) valence bond theory

d) Werner’s theory

9 / 50

9. A complex has no obvious plane or centre of symmetry in a two-dimensional sketch. The safest conclusion is:

a) it cannot possess any stereoisomer

b) it must be a structural isomer

c) chirality remains possible; test superimposability

d) it must be optically active without further inspection

10 / 50

10. An octahedral complex contains three unpaired electrons for both weak-field and strong-field ligands. The electronic reason is that:

a) ligand field strength converts the ion from to

b) three electrons singly fill the lower orbitals first

c) two electrons enter before the set is filled

d) all three electrons pair in one orbital

11 / 50

11. The name of is:

a) tripotassium trioxalatocobalt(III)

b) potassium tris(oxalato)cobalt(III)

c) potassium tris(oxalato)cobaltate(II)

d) potassium tris(oxalato)cobaltate(III)

12 / 50

12. is named:

a) tripotassium hexacyanidoiron(III)

b) potassium hexacyanidoferrate(III)

c) potassium hexacarbonylferrate(III)

d) potassium hexacyanidoferrate(II)

13 / 50

13. A graph has absorbed wavelength on the horizontal axis and crystal-field splitting on the vertical axis. Which curve best represents the relation between them?

a) A straight line with increasing directly with

b) A horizontal line

c) A straight line through the origin with positive slope

d) A decreasing inverse curve

14 / 50

14. Match each octahedral-field feature in Column I with the appropriate description in Column II.

Column I	Column II
P.	1.
Q.	2. Twofold orbital degeneracy
R. Axial orbital lobes	3. Greater octahedral ligand repulsion
S. Between-axis orbital lobes	4. Lower octahedral ligand repulsion

a) P-4, Q-3, R-1, S-2

b) P-2, Q-1, R-3, S-4

c) P-3, Q-4, R-2, S-1

d) P-1, Q-2, R-4, S-3

15 / 50

15. Assertion: A octahedral complex is called an inner-orbital complex.
Reason: The two orbitals used in hybridisation belong to the shell.

a) Assertion is true, but Reason is false

b) Assertion is false, but Reason is true

c) Both Assertion and Reason are true, and Reason explains Assertion

d) Both Assertion and Reason are true, but Reason does not explain Assertion

16 / 50

16. The formula corresponds to which description?

a) Tetraamminecopper(II) sulfate; with one unpaired electron

b) Tetraamminecopper(IV) sulfate; is

c) Tetraamminecuprate(II) sulfate; the coordination entity is anionic

d) Tetraamminecopper(I) sulfate; is and diamagnetic

17 / 50

17. A four-coordinate square-planar complex accepts two additional ligands, one above and one below the original ligand plane. If all six donor atoms remain bonded, the new coordination polyhedron is:

a) octahedral

b) trigonal planar

c) square pyramidal

d) tetrahedral

18 / 50

18. Study the charge-balance table.

Compound	Coordination-entity charge	Counter ions per formula unit
P.		Three
Q.		Four
R.		One
S.		Two

The inconsistent row is:

a) R

b) S

c) Q

d) P

19 / 50

19. Carbon monoxide contains both carbon and oxygen, yet a terminal ligand is normally classified as monodentate because:

a) carbon monoxide becomes a monatomic ion on bonding

b) one carbonyl donor atom binds the metal

c) only one atom of the ligand can possess electrons

d) oxygen is removed before coordination occurs

20 / 50

20. A student argues that cannot form a coordinate bond because it is a neutral molecule. Which correction is most appropriate?

a) first loses an electron and becomes

b) Only charged ligands possess lone pairs

c) Neutral ligand donation need not change formal charge

d) The metal supplies both electrons of every metal–carbon bond

21 / 50

21. Electron pairing may occur before hybridisation primarily to:

a) convert every ligand into a bidentate ligand

b) leave two inner orbitals vacant

c) increase the oxidation state of the metal

d) reduce the coordination number from to

22 / 50

22. A neutral compound contains only metal atoms and carbonyl ligands. Spectroscopic bonding analysis shows donation from a filled carbon-centred orbital of into a vacant orbital on each metal. The bonding analysis supports the description:

a) It is mononuclear, the metal is , and the donation is metal to ligand

b) It is polynuclear, the metal is , and carbon monoxide is an anionic ligand

c) It is polynuclear, each metal is formally , and carbon is the -donor atom

d) It is mononuclear, the metal is , and oxygen is the donor

23 / 50

23. Consider the following statements about optical isomers.
Statement I: They have the same metal–ligand connectivity.
Statement II: They are non-superimposable mirror images.
Statement III: They necessarily have different oxidation states.
Statement IV: They may rotate plane-polarised light in opposite directions.
The valid statements are:

a) I, II and IV only

b) II and III only

c) I, II, III and IV

d) I and III only

24 / 50

24. An octahedral complex has and configuration . Its CFSE is:

25 / 50

25. Study the nomenclature table.

Entity	Proposed metal portion
P.	Cobalt(III)
Q.	Nickel(0)
R.	Plumbate(IV)
S.	Iron(II)

The fully supported rows are:

a) P, Q, R and S

b) P, Q and R

c) P and S only

d) Q and S only

26 / 50

26. The tetrahedral paramagnetism of can be represented by:

a) VBT as , and CFT as

b) VBT as with no unpaired electrons, and CFT as

c) VBT as , and CFT as

d) VBT as with two unpaired electrons, and CFT as

27 / 50

27. Five-membered and six-membered chelate rings are often especially stable because they:

a) prevent the metal from interacting with any donor atom

b) guarantee greater stability than every other complex under all conditions

c) often give favourable geometry with little ring strain

d) contain no covalent bonds within the ligand

28 / 50

28. A hard metal ion such as is offered two otherwise comparable ligands, one coordinating through oxygen and the other through sulphur. Which interaction is generally favoured by the hard-soft compatibility principle?

a) Both interactions must have exactly the same stability

b) Hard-soft compatibility applies only to neutral metals

c) with oxygen, because hard acids prefer hard bases

d) with the sulphur donor because hard acids prefer soft bases

29 / 50

29. Two drawings of a tetrahedral entity show the ligands at apparently different corners. If rotation of one model makes all corresponding ligands overlap, the drawings represent:

a) one tetrahedral structure

b) two geometrical-isomer structures

c) two optical-isomer structures

d) two linkage-isomer structures

30 / 50

30. An energy-level diagram contains a lower group of metal orbitals and a higher group separated by . An upward arrow labelled joins the two groups. The arrow represents:

a) photon absorption followed by electron promotion

b) removal of a ligand from the complex

c) emission of a photon while an electron moves upward

d) electron pairing within the lower orbital set

31 / 50

31. The cis form of can be optically active, whereas the standard trans form is achiral. The best structural explanation is that:

a) optical activity depends only on the oxidation state and not on spatial arrangement

b) the trans form contains only one ligand

c) cis can lack improper symmetry, while trans commonly retains it

d) the cis form has coordination number , while the trans form has coordination number

32 / 50

32. Two octahedral complexes contain the same metal ion in the same oxidation state but different ligands. Their values of are unequal mainly because:

a) the number of metal electrons changes with ligand identity

b) ligands generate crystal fields of different strengths

c) coordination number alone fixes the splitting energy

d) every ligand contributes the same electrostatic field

33 / 50

33. A learner names as “chloride hexaamminecobalt(III).” The principal error is that:

a) the anion has been named before the complex cation

b) the oxidation state should be written before cobalt

c) ammonia should be treated as an external counter ion

d) chloride should be included among the six coordinated ligands

34 / 50

34. Complexes and have the same overall charge. Compared with , the oxidation state of in is:

a) lower by one unit

b) lower by two units

c) unchanged

d) higher by one unit

35 / 50

35. A measured spin-only moment near is obtained for an octahedral iron(III) complex. Which ligand and configuration best fit the observation?

a) and

b) and

c) and

d) and

36 / 50

36. Complex and complex are octahedral, contain the same ligand, and involve analogous metal ions. The metal–ligand distance in is shorter than that in . Which prediction is most reasonable?

a) generally has the larger

b) and must have identical splitting because the ligand is the same

c) must be low spin because its ligands are farther away

d) must have a smaller coordination number

37 / 50

37. Study the ligand comparisons made for the same metal ion under similar conditions.

Row	Ligand system	Feature	Likely stability influence
P	Six monodentate donors	Six separate ligand molecules	No chelate rings
Q	Three bidentate donors	Three ligand molecules	Three chelate rings may form
R	One hexadentate donor	One ligand molecule	Several donor atoms hold the metal
S	One monodentate donor	One donor atom	Must always be more stable than every chelate

The inconsistent row is:

a) S

b) Q

c) R

d) P

38 / 50

38. Why are the octahedral orbital-energy coefficients and , rather than equal values?

a) The orbitals interact with exactly of the ligands

b) The orbitals contain of the metal electrons in every complex

c) The pairing energy is always

d) Weighted orbital shifts balance about the barycentre across

39 / 50

39. Study the proposed magnetic-property assignments.

Row	Octahedral configuration	Spin description	Unpaired electrons	Approximate moment
P		High-spin
Q		Low-spin
R		Low-spin
S		High-spin

The inconsistent row is:

a) S

b) P

c) R

d) Q

40 / 50

40. Study the proposed properties of fully deprotonated EDTA.

Row	Property	Proposed description
P	Charge
Q	Denticity	Hexadentate
R	Common metal-to-ligand ratio
S	Number of donor atoms used	Four

The inconsistent row is:

a) P

b) R

c) Q

d) S

41 / 50

41. Suitable metal ions commonly form square-planar complexes with strong-field ligands because the ligands can:

a) convert every metal electron into a ligand electron

b) force the coordination number to become

c) prevent the and orbitals from participating

d) pair electrons to free one inner orbital

42 / 50

42. Study the supplied formation data.

Row	Stepwise constants	Proposed overall constant
P
Q
R
S

The inconsistent row is:

a) R

b) P

c) S

d) Q

43 / 50

43. A -electron transition occurs when the energy of the absorbed photon satisfies:

c) in every complex

44 / 50

44. In the coordination entity , the central species and the surrounding ligands are respectively:

a) and six nitrogen atoms

b) and

c) atoms and three molecules

d) and six molecules

45 / 50

45. A four-coordinate complex is known to be tetrahedral and high spin. Which property is least consistent with this information?

a) No compulsory pairing of inner electrons

b) All electrons paired in a arrangement

c) Four equivalent ligand directions

d) hybridisation

46 / 50

46. Consider the following statements about metal carbonyls.
Statement I: is treated as a neutral ligand.
Statement II: Neutral homoleptic metal carbonyls commonly contain metals in oxidation state .
Statement III: Polynuclear carbonyls contain more than one metal atom.
Statement IV: Coordination of requires the ligand to become in oxidation-state calculations.
The valid statements are:

a) II and IV only

b) I, II and III

c) I, II, III and IV

d) I and IV only

47 / 50

47. Compare the total crystal-field and pairing contributions for octahedral , counting for each paired orbital. The high-spin and low-spin expressions are respectively:

a) and

b) and

c) and

d) and

48 / 50

48. In a coordination-compound name, the oxidation state of the central metal is normally written as:

a) an Arabic numeral without brackets before the ligand names

b) a Roman numeral in parentheses after the metal name

c) a superscript written after the entire compound name

d) a subscript attached to the counter-ion name

49 / 50

49. Study the optical-isomerism table.

Row	Observation	Conclusion
P	Mirror images are non-superimposable	Chiral pair possible
Q	A plane of symmetry is present	Entity is ordinarily achiral
R	Mirror image overlaps after rotation	Same achiral structure
S	Enantiomers have different molecular formulas	Optical isomerism confirmed

The inconsistent row is:

a) S

b) Q

c) P

d) R

50 / 50

50. Match each description in Column I with the appropriate classification in Column II.

Column I	Column II
P. One joins two metal ions	1. Terminal monodentate
Q. One binds one metal through two nitrogen atoms	2. Bridging
R. One binds one metal through nitrogen	3. Chelating
S. One connects two metal atoms	4. Bridging carbonyl

a) P-4, Q-1, R-3, S-2

b) P-3, Q-2, R-4, S-1

c) P-2, Q-4, R-1, S-3

d) P-2, Q-3, R-1, S-4

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Coordination Compounds Mock Test – Class 12 Chemistry

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