Coordination Compounds Mock Test – Class 12 Chemistry
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Coordination Compounds Mock Test – Class 12 Chemistry

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Coordination Compounds – Progressive Test

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1. Assertion: A standard square-planar complex is often diamagnetic.
Reason: Electron pairing can place eight electrons in four orbitals and leave one inner orbital vacant for hybridisation.

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2. The supported conclusions for are:

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3. Suitable metal ions commonly form square-planar complexes with strong-field ligands because the ligands can:

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4. For , the charge on the coordination entity and the oxidation state of platinum are respectively:

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5. A coordination entity has the general formula , where every is neutral and every carries charge . The oxidation state of is:

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6. Study the ligand comparisons made for the same metal ion under similar conditions.

Row Ligand system Feature Likely stability influence
P Six monodentate donors Six separate ligand molecules No chelate rings
Q Three bidentate donors Three ligand molecules Three chelate rings may form
R One hexadentate donor One ligand molecule Several donor atoms hold the metal
S One monodentate donor One donor atom Must always be more stable than every chelate

The inconsistent row is:

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7. A pair of enantiomers placed in an achiral environment generally has:

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8. Which formula corresponds to diamminedichloridoplatinum(II)?

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9. A chelating agent is administered in a case of metal poisoning. Its intended function is to:

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10. A complex has three unpaired electrons. Its spin-only magnetic moment is closest to:

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11. Three statements describe how denticity affects coordination. Identify the valid combination.
Statement I: An ambidentate ligand may possess two potential donor atoms.
Statement II: A bidentate ligand normally uses two donor atoms simultaneously to bind one metal centre.
Statement III: Each ambidentate ligand necessarily contributes to the coordination number.
The valid statements are:

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12. Match each metal ion in Column I with its -electron configuration in Column II.

Column I Column II
P. 1.
Q. 2.
R. 3.
S. 4.

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13. The name of is:

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14. A metal has oxidation state in . The complex is combined with nitrate counter ions to form a neutral compound. The value of and the complete formula are:

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15. Consider the following statements about fac–mer isomerism.
Statement I: It is commonly shown by octahedral complexes of the type .
Statement II: In the fac form, the three identical ligands are mutually cis.
Statement III: In the mer form, one pair of identical ligands is trans.
Statement IV: The coordination number changes between the fac and mer forms.
The valid statements are:

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16. Match each cobalt compound in Column I with the number of chloride ions precipitated immediately by excess per formula unit.

Column I Column II
P. 1. Zero
Q. 2. One
R. 3. Two
S. 4. Three

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17. Which formula represents tetraammineaquachloridocobalt(III) chloride?

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18. Assertion: donation and back-bonding in a metal carbonyl reinforce one another.
Reason: donation increases electron density at the metal for back donation, while back donation removes some metal electron density and allows continued ligand-to-metal donation.

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19. Consider the following statements about optical isomers.
Statement I: They have the same metal–ligand connectivity.
Statement II: They are non-superimposable mirror images.
Statement III: They necessarily have different oxidation states.
Statement IV: They may rotate plane-polarised light in opposite directions.
The valid statements are:

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20. Two ligands, and , each attach to a metal through one donor atom. The comparison demonstrates that:

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21. A coordination entity and its mirror image are found to overlap completely after suitable rotation. The entity is:

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22. Match each description in Column I with the appropriate designation in Column II.

Column I Column II
P. Right-handed tris-chelate helix 1. Achiral
Q. Left-handed tris-chelate helix 2.
R. Mirror images that cannot overlap 3. Enantiomers
S. Mirror image superimposable on the original 4.

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23. A metal ion is initially surrounded by six separate monodentate ligands. They are replaced by one ligand, and all six donor atoms of bind to the metal. The replacement changes:

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24. Complex absorbs at , while complex absorbs at . The ratio is:

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25. An analyst adds a ligand that forms a stable soluble complex with an interfering metal ion . The target ion is then precipitated without precipitation of . The role of is best described as:

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26. A six-coordinate complex contains a metal ion. Strong ligand-induced pairing leaves two inner orbitals vacant. Which set of properties is predicted by the standard valence bond treatment?

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27. A metal complex is converted completely into . If of reacts according to

the total moles of free released and consumed are respectively:

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28. Consider the following statements about naming the central metal.
Statement I: A metal in a neutral coordination entity retains its ordinary name.
Statement II: A metal in a complex cation retains its ordinary name.
Statement III: A metal in every complex anion also retains its ordinary name without modification.
The valid statements are:

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29. The tetrahedral crystal-field configuration of in is:

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30. For low-spin , the VBT and CFT descriptions, respectively, are:

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31. Match each description in Column I with the appropriate classification in Column II.

Column I Column II
P. One joins two metal ions 1. Terminal monodentate
Q. One binds one metal through two nitrogen atoms 2. Bridging
R. One binds one metal through nitrogen 3. Chelating
S. One connects two metal atoms 4. Bridging carbonyl

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32. Cisplatin and transplatin have the same formula, , but differ in:

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33. A target ligand forms a stable complex , but a second ligand is added and binds the same metal even more strongly. What may happen to the concentration of ?

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34. A student claims that a complex cannot absorb electromagnetic radiation because all its orbitals are filled. Which correction is best?

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35. Study the descriptions of the crystal field model.

Row Feature Description
P Free metal ion Five degenerate orbitals
Q Ligand approach Produces directional electrostatic repulsion
R Crystal field splitting Removes -orbital degeneracy
S Barycentre Moves upward by the full splitting energy

The inconsistent row is:

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36. Multiplying the equilibria

and

gives which overall equilibrium and constant relation?

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37. Use the arrangement described below.
A filled orbital on the carbon end of points directly toward an empty metal orbital along the metal–carbon axis.
Which bond is primarily formed by this overlap?

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38. Assertion: Oxidation of the central metal ion can change the colour of a coordination compound even when its ligands and geometry remain unchanged.
Reason: Oxidation can change both the metal -electron count and the magnitude of crystal-field splitting.

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39. Use the two arrangements described below.
Case 1: One ligand is bonded to two metal centres.
Case 2: One ligand uses both nitrogen atoms to bind the same metal centre.
The ligand roles in Case 1 and Case 2 are respectively:

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40. Assertion: Simple valence bond theory can predict that two complexes have different numbers of unpaired electrons but may not explain the energetic origin of that difference.
Reason: The theory assigns pairing and hybridisation without quantitatively comparing orbital splitting energy with pairing energy.

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41. Which octahedral configuration does not have distinct high-spin and low-spin arrangements?

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42. Which sequence is arranged from weaker field to stronger field in the spectrochemical series?

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43. A tetrahedral high-spin ion has which CFSE and unpaired-electron count?

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44. Study the ligand-name table.

Row Ligand Proposed ligand name
P Ammine
Q Aqua
R Cyanide
S Carbonyl

The inconsistent row is:

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45. Assertion: A complex with a larger spin-only magnetic moment generally contains more unpaired electrons.
Reason: The quantity increases as the allowed integral value of increases.

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46. For the equilibrium

which expression represents ?

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47. In , the metal has oxidation state . The values of and the coordination number are:

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48. Assertion: Formation of can cause solid to dissolve.
Reason: Complex formation lowers the concentration of free , shifting the dissolution equilibrium of toward the ions.

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49. The stepwise constants for formation of are , , and . The value of is:

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50. In , the oxidation state and -electron configuration of cobalt are respectively:

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