Atoms Mock Test – Class 12 Physics
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Atoms Mock Test – Class 12 Physics

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Atoms – Progressive Test

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1. The energy of a photon emitted in a Bohr transition depends on

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2. If is doubled and is kept unchanged in a hydrogen-like atom, the orbital radius becomes

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3. A table lists changes in head-on scattering conditions.

Case Nuclear charge factor Alpha kinetic energy factor Effect on
P unchanged doubled of original
Q doubled unchanged times original
R doubled doubled unchanged
S unchanged halved of original

The row that gives the wrong effect on is

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4. A symbolic derivation uses two relations:
I.
II.
Together, these relations show that allowed radii are not arbitrary because

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5. An -particle approaching a gold nucleus is deflected because

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6. A hydrogen atom in is just ionised by a photon whose threshold wavelength is closest to , using . The energy threshold used in this calculation is

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7. In atomic physics, a photon is best described as

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8. The radius of the orbit of , where , is

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9. The energy of the level of hydrogen is

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10. Rutherford’s nuclear model could not explain atomic stability because a revolving electron is

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11. The expected path of an electron in Rutherford’s model under classical radiation loss is best described as

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12. For , an electron moves from an orbit of radius to an orbit of radius . The emitted photon energy is

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13. The kinetic energy of the electron in the Bohr orbit is related to its speed by

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14. Compare the hydrogen-like species in the table.

Species Same transition
P
Q
R

For the emitted photon energies, the correct order is

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15. If an electron wave around a proposed circular orbit contains wavelengths around the circumference, the orbit is not allowed in the Bohr-de Broglie picture because

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16. For , an electron occupies the orbit whose radius is . The total energy of the electron is

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17. A hydrogen atom changes from an energy level to . The energy of the emitted photon is

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18. A graph description is given below.

For a fixed target and fixed alpha-particle energy, the number of alpha particles detected is plotted against scattering angle . The curve falls rapidly as increases.

The rapid fall of with indicates that

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19. The Rydberg constant appears in the hydrogen spectrum formula. Its usual SI unit is

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20. A neutral atom has . The number of electrons in it is

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21. In alpha scattering, the closest-approach condition for a head-on case is based on the idea that, momentarily,

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22. For corresponding transitions in hydrogen and , such as , the wavelength for is

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23. Compare two Bohr orbits:

Case Species Orbit
P Hydrogen,
Q ,

The ratio is

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24. A hydrogen atom in absorbs a photon of energy . The best conclusion is that

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25. For a fixed value of , increasing in the Rydberg formula makes the spectral lines of that series approach

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26. For a fixed target nucleus, an -particle passing closer to the nucleus suffers a larger deflection mainly because

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27. A hydrogen line has wavenumber . The transition is represented by

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28. The hydrogen line has wavelength approximately . For the corresponding transition in , the wavelength is approximately

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29. A student compares kinetic energy and potential energy in atomic models. Kinetic energy is most directly associated with

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30. If a hydrogen atom in the ground state absorbs a photon of energy , the kinetic energy of the freed electron is

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31. For the same transition, a one-electron ion emits a photon whose frequency is times the hydrogen frequency. The ion’s nuclear charge number is

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32. A compact conclusion that correctly compares the three early atomic models is

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33. Bohr’s radius formula and speed formula show opposite dependences on because

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34. Assertion: Thomson’s model was able to explain the electrical neutrality of atoms.
Reason: In Thomson’s model, electrons were embedded in a sphere of positive charge.

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35. Two alpha particles have the same kinetic energy and approach the same nucleus. Particle P has impact parameter , while particle Q has impact parameter . The more strongly deflected particle is

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36. Consider the two statements below.
I. Thomson’s model could explain the overall neutrality of an atom.
II. Thomson’s model could explain large-angle alpha-particle scattering by a tiny dense nucleus.

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37. Bohr’s first postulate about stationary orbits was needed because classical theory predicted that a revolving electron should

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38. The first line of a hydrogen spectral series has the

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39. Starting from the Bohr relations and , the reason finally varies as is that

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40. For the Balmer first line of hydrogen, and . The wavenumber is

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41. A table compares observations with models.

Row Observation or feature Best model-level explanation
P Rare alpha-particle backscattering Rutherford’s small positive nucleus
Q Stability of allowed electron orbits Bohr’s stationary-state postulate
R Hydrogen line wavelengths Bohr energy levels and transitions
S Fine structure and field splitting in full detail Simple Bohr model alone

The row that needs correction is

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42. The Bohr radius is the radius of

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43. An atomic model that includes charged particles, circular motion, and radiation must be able to deal with all of the following ideas except

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44. For hydrogen, compare the photon emitted in with the photon emitted in . The ratio of their energies is

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45. Assertion: In Bohr’s model, angular momentum of the electron is quantised.
Reason: The allowed values satisfy , where .

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46. As increases for hydrogen, the total energy

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47. In atomic calculations, the energy unit is commonly used because atomic energy changes are

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48. A spectral line is produced by a transition ending at in hydrogen. The line belongs to the

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49. A head-on alpha-scattering case has initial kinetic energy . The target nucleus has charge . The alpha particle has charge . The electrostatic potential energy at closest approach is

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50. The direction of force on an -particle near a positive nucleus is

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