Electric Charges And Fields Mock Test – Class 12 Physics
GKaim: Measure | Improve | Achieve

Electric Charges and Fields Mock Test – Class 12 Physics

Progressive Test — Guest First Round

0%

Electric Charges and Fields – Progressive Test

Welcome to the Progressive Test.

Click Start Test to begin the loaded practice round.

Good luck!

1 / 50

1. Study the table for a fixed pair of charges in the same medium and identify the row that does not follow Coulomb proportionality.

Row Change made Predicted force
P doubled
Q tripled
R doubled
S tripled

2 / 50

2. A charge is placed at the centre of a square. Four identical positive charges are fixed at the four corners. If the centre charge is removed, the electric field at the centre due to the four corner charges is

3 / 50

3. A negatively charged rod is brought near the cap of a neutral electroscope without touching it. The leaves diverge during the approach, but the electroscope is not earthed. This observation is best explained by

4 / 50

4. A non-uniformly charged rod is divided mentally into very small pieces. The use of in is helpful because

5 / 50

5. A dipole of moment is in a uniform electric field . It rotates slowly from to . The change in potential energy is

6 / 50

6. A statement says, “A dielectric medium increases the Coulomb force because is placed in the formula.” The suitable correction is that the medium

7 / 50

7. A student writes . This value represents

8 / 50

8. A square surface of side has area vector . A uniform field makes with . If the surface is then rotated so that the angle becomes , the change in flux is

9 / 50

9. A small pillbox Gaussian surface is drawn across the surface of a charged conductor in electrostatic equilibrium. The field just outside is , the surface charge density is , and the field inside the conductor is zero. Gauss’s law gives

10 / 50

10. Study the Gauss-law table and identify the row that is incorrect.

Row Situation Net flux through closed surface
P Encloses
Q Encloses
R Encloses and
S Encloses no charge but has outside charges nearby

11 / 50

11. Consider the following statements about electric charge.
I. Electric charge can be positive or negative.
II. The sign of charge gives a fixed spatial direction.
III. A neutral body has zero net charge.
IV. Like charges repel each other.
The supported set is

12 / 50

12. For an infinite uniformly charged plane sheet with surface charge density , the electric field is directed

13 / 50

13. Three identical isolated conducting spheres have initial charges , , and . First, sphere P touches sphere Q and separates. Then sphere P touches sphere R and separates. The final charge on sphere P is

14 / 50

14. In the derivation of the point-charge field using Gauss’s law, the step is valid because

15 / 50

15. Study the constant-symbol table and identify the mismatched row.

Row Symbol Meaning Approximate value or relation
P Coulomb constant
Q Vacuum permittivity
R Elementary charge magnitude
S Linear charge density

16 / 50

16. Two charges and are fixed on a line. At any point between them, the electric field contributions due to the two charges are

17 / 50

17. A charged conductor touches a neutral conductor. The final charge acquired by the neutral conductor depends on the

18 / 50

18. A graph of versus for a dipole in a uniform field is based on . The graph has a maximum at

19 / 50

19. In the arrangement of two large parallel sheets with surface charge densities and , the electric field in the region exactly between the sheets is

20 / 50

20. A record of a rubbing experiment is shown below.

Case Action Final observation
P Glass rubbed with silk Glass is positive, silk is negative
Q Ebonite rubbed with wool Ebonite is negative, wool is positive
R Two neutral bodies rubbed in isolation Total charge of the pair remains unchanged
S Ordinary solid bodies rubbed Protons move freely from one solid to the other

The row that does not fit ordinary charging by friction is

21 / 50

21. The sign acquired by a body during rubbing depends mainly on

22 / 50

22. A student compares , , and for a Gaussian surface. The correct statement is

23 / 50

23. If the separation between two fixed point charges is tripled, while the charges and medium are unchanged, the magnitude of Coulomb force becomes

24 / 50

24. The orientation for a dipole in a uniform electric field is called stable equilibrium because

25 / 50

25. Study the comparison table for a far electric dipole field and identify the mismatched row.

Row Location Approximate magnitude Direction
P Axial line Along
Q Equatorial line Opposite to
R Axial line Twice the equatorial magnitude at the same far Along
S Equatorial line Along

26 / 50

26. Study the table for a dipole in a uniform electric field and identify the row that needs correction.

Row Angle between and Torque magnitude
P
Q
R
S

27 / 50

27. Charges and are fixed apart in vacuum. What is the magnitude of the electric field at the midpoint between them? Take .

28 / 50

28. Study the table for two charges on the -axis. In each case, is at , is at , and . Identify the row with a mismatched force direction for .

Row Direction of force on
P
Q
R
S

29 / 50

29. Charges , , and a small positive charge lie on a straight line. The charge is at , is at , and is placed at between them so that the net force on is zero. The value of is

30 / 50

30. A surface is tilted so that the electric field makes an angle with the plane of the surface. The angle to be used in is

31 / 50

31. Two identical isolated conducting spheres initially carry and . After touching and separating, one of them is touched to a third identical neutral sphere and then separated. The final charge on the first sphere after the second contact is

32 / 50

32. Assertion: In charging by contact, a neutral conductor can acquire the same sign of charge as the charged conductor that touches it.
Reason: During contact, charge can flow and redistribute through the conducting connection.

33 / 50

33. Two charges are fixed at the ends of a line segment. The force direction is being decided before calculating the force magnitude. The most reliable first step is to

34 / 50

34. A claim says, “Induction and polarization are exactly the same because both begin with charge separation.” The best evaluation is that the claim is

35 / 50

35. The area vector of a plane surface is drawn

36 / 50

36. A dipole of moment is in a uniform electric field . At an angle , its torque magnitude is and potential energy is . If and , then equals

37 / 50

37. The order of operations matters in induction. For a conductor to be left charged using a nearby positive rod, the suitable sequence is

38 / 50

38. Read the case below.

A small positive charge is placed at a point where two fields act simultaneously. One field is toward east, and the other is toward north. The charge magnitude is .

The magnitude of the net electric force on the charge is

39 / 50

39. A charge distribution has spherical symmetry, but the charge enclosed by a spherical Gaussian surface of radius changes with . The correct Gauss-law strategy is to use

40 / 50

40. A negatively charged rod is held near a neutral metal sphere on an insulating stand. The sphere is then connected briefly to earth while the rod remains nearby. During earthing, electrons tend to flow

41 / 50

41. The linear charge density of a charged wire is defined as charge per unit

42 / 50

42. A far dipole field is compared with the field of a single point charge. The dipole field decreases faster with distance because it varies as

43 / 50

43. A charge is placed at the centre of a spherical Gaussian surface of radius . The electric field magnitude on the surface is

44 / 50

44. A pair of charges experiences a force in vacuum. When the space between them is filled with a dielectric of constant , the force becomes

45 / 50

45. A charged conducting plane surface in electrostatic equilibrium has surface charge density . Just outside the conductor, the electric field is

46 / 50

46. A charged body is brought near a neutral conductor, and the conductor moves slightly toward it. This motion should not be confused with charge movement because

47 / 50

47. Study the table for Gauss-law applications and identify the row with the wrong distance dependence.

Row Charge distribution Electric field dependence
P Point charge
Q Infinitely long line charge
R Infinite plane sheet independent of
S Infinite plane sheet

48 / 50

48. A body has both charge and mass, but a nearby neutral massive object exerts gravitational attraction while a nearby charged object exerts electrostatic force. The property paired correctly with the force is

49 / 50

49. In electrostatics, electric charge is treated as a scalar quantity, while electrostatic force is treated as

50 / 50

50. The dimensional formula of can be obtained from . Taking charge dimension as , the dimension of is

Your score is

Share your achievement!

LinkedIn Facebook
0%

Complete at least one Progressive Test round with incorrect or unanswered questions to unlock Mistake Review.
Complete at least 25% of the Progressive Test to unlock the Certificate Challenge Section.

Subscribe
Notify of
guest
0 Comments
Scroll to Top