Chemical Kinetics MCQs With Answers – Part 5 (Class 12 Chemistry)
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Chemical Kinetics MCQs with Answers – Part 5 (Class 12 Chemistry)

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411. Two energy-distribution curves P and Q correspond to the same gas sample at different temperatures. Curve Q has a lower maximum, is broader, and is shifted toward higher energy. Which comparison is correct?
ⓐ. \(T_Q\lt T_P\)
ⓑ. \(T_Q=T_P\)
ⓒ. \(T_Q\gt T_P\)
ⓓ. Temperature cannot be inferred from the curve shapes
412. Assertion: Raising the temperature can produce a large increase in reaction rate even when the average molecular energy increases only moderately. Reason: The fraction of molecules lying beyond the activation-energy threshold can increase substantially.
ⓐ. Both Assertion and Reason are true, but Reason does not explain Assertion
ⓑ. Assertion is true, but Reason is false
ⓒ. Assertion is false, but Reason is true
ⓓ. Both Assertion and Reason are true, and Reason explains Assertion
413. A catalyst is added to a reaction mixture without changing its temperature. On a molecular-energy distribution graph, the immediate effect is best represented by:
ⓐ. shifting the entire distribution curve toward higher energy
ⓑ. increasing the total area under the curve
ⓒ. moving the activation-energy threshold toward lower energy
ⓓ. making all molecules possess the same energy
414. Match each change in Column I with its effect in Column II.
Column IColumn II
P. Increase in temperature1. Activation-energy line shifts left
Q. Addition of a catalyst at fixed temperature2. Distribution becomes broader with a lower peak
R. Increase in activation energy at fixed temperature3. Smaller area lies beyond the threshold
S. Normalising the distribution4. Total area becomes \(1\)
ⓐ. P-1, Q-2, R-4, S-3
ⓑ. P-2, Q-1, R-3, S-4
ⓒ. P-2, Q-3, R-1, S-4
ⓓ. P-4, Q-1, R-3, S-2
415. At temperature \(T_1\), \(2\%\) of molecules have energy at least equal to \(E_a\). At a higher temperature \(T_2\), this fraction becomes \(8\%\). If collision frequency and orientation factor are assumed unchanged, the energetic contribution to the rate increases by a factor of:
ⓐ. \(2\)
ⓑ. \(3\)
ⓒ. \(4\)
ⓓ. \(6\)
416. Consider the following statements about molecular-energy distributions. Statement I: At any non-zero temperature, molecules do not all possess the same kinetic energy. Statement II: Increasing temperature increases the area under the normalised curve. Statement III: Increasing temperature increases the fraction of molecules with energy above a fixed \(E_a\). The valid statements are:
ⓐ. I, II and III
ⓑ. I and II only
ⓒ. II and III only
ⓓ. I and III only
417. The peak of a molecular-energy distribution curve does not directly represent:
ⓐ. the energy possessed by the largest number of molecules
ⓑ. the most probable molecular energy
ⓒ. the activation energy for every reaction
ⓓ. a value that shifts when temperature changes
418. Which observation is not explained adequately by the simplest collision theory alone?
ⓐ. Increasing gas concentration increases collision frequency
ⓑ. A multistep solution reaction with solvent stabilisation
ⓒ. Energetic collisions are more common at higher temperature
ⓓ. Unfavourable orientation can prevent reaction
419. Assertion: Collision theory is more successful qualitatively than quantitatively for many complex reactions. Reason: Real molecules may have complicated energy redistribution, intermolecular forces, and multistep pathways.
ⓐ. Both Assertion and Reason are true, and Reason explains Assertion
ⓑ. Both Assertion and Reason are true, but Reason does not explain Assertion
ⓒ. Assertion is true, but Reason is false
ⓓ. Assertion is false, but Reason is true
420. A reaction proceeds through three elementary steps and contains two detectable intermediates. Why can a single-collision description be inadequate?
ⓐ. The observed rate may depend on the sequence and relative rates of several elementary events
ⓑ. Each elementary step loses its activation barrier after the first intermediate is formed
ⓒ. Detectable intermediates prevent further collisions between the original reactant molecules
ⓓ. All elementary steps must have the same rate constant for the overall process to occur
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