Hydrocarbons Mock Test – Class 11 Chemistry

1. A sample of ethyne absorbs of at during complete hydrogenation. Using , the amount of ethyne hydrogenated is

2. A naming attempt calls as pent--ene. The better name is pent--ene because

3. Kolbe electrolysis prepares alkanes by electrolysing sodium or potassium salts of carboxylic acids, mainly through

4. The molar mass difference between two successive members of the same hydrocarbon homologous series is

5. The statement that best compares complete and incomplete combustion of alkanes is

6. A hydrocarbon is described as open-chain and contains only single bonds. Its most likely broad reaction family at the introductory level is

7. A compact passage is given below.

The comparison mainly shows that

8. A learner expects three different monobromobenzenes because benzene can be drawn with alternating double bonds. The best correction is that

9. Use the arrangement described below for ethane viewed along the bond.
Case 1: each rear bond lies directly behind a front bond.
Case 2: each rear bond lies halfway between two front bonds.
The names of Case 1 and Case 2 respectively are

10. A graph of potential energy versus dihedral angle for ethane has repeating minima every . This periodicity occurs because

11. The suitable IUPAC name for is

12. The solvent most suitable for dissolving an alkane is generally

13. Catalytic hydrogenation of ethene produces ethane because

14. In the monochlorination of propane, substitution at a terminal carbon gives

15. Friedel-Crafts alkylation of benzene using gives mainly

16. The formula-test record for gives , rapid bromine-water decolourisation, and plus on reductive ozonolysis. The best identity of is

17. The decolourisation of dilute alkaline by an alkene is used as a test for

18. A reaction note says: “An unsaturated hydrocarbon is passed with excess over heated , and the product contains only carbon-carbon single bonds.” The product type is most likely

19. An alkyne sample of reacts completely with excess bromine to form a tetrabromoalkane and consumes of . On combustion, the same amount of gives of . The molecular formula of is

20. Nitration and flame observations identify compound , formula , which burns with a smoky flame and gives one mononitro product with . The most suitable identity is

21. The carbon atoms directly involved in the bond of an alkyne are generally

22. In a carbon-carbon double bond of an alkene, the bonding consists of

23. In the reaction pattern , the carbon chain is usually

24. A table lists possible additions of hydrogen halides to alkenes.

The row that needs correction is

25. Ethene, , does not show geometrical isomerism because

26. Reductive ozonolysis of alkene gives of propanone and of ethanal. The molecular formula of and the minimum needed for complete hydrogenation are

27. Rotation about a single bond in alkanes is possible mainly because the bond is a

28. Reduction of an alkyl halide to an alkane mainly involves replacing the halogen atom by

29. Alkenes are hydrocarbons that contain at least one

30. The pair that can belong to the same homologous series of open-chain alkanes is

31. A comparison of two alkane isomers is given below.

The more likely boiling-point order is

32. A hydrogen atom attached to a carbon bonded to two other carbon atoms is described as a

33. Benzene is classified as an aromatic hydrocarbon because it contains

34. Use the arrangement described below for a benzene ring with two identical substituents.
Case 1: substituents at positions and
Case 2: substituents at positions and
Case 3: substituents at positions and
The names of these relative arrangements, in order, are

35. In the reaction , the role of in soda lime is best described as

36. Combustion of hydrocarbon gives of and of . It reacts with exactly of on complete hydrogenation. The most suitable formula and hydrogenatable unsaturation count are

37. A table compares local bonding in hydrocarbons.

The row that needs correction is

38. A hydrocarbon has formula . Its straight-chain isomer has a higher boiling point than its highly branched isomer. The best reason is that the straight-chain isomer has

39. In the dehydrohalogenation of , the major alkene usually follows Saytzeff's rule. The major product is

40. Alkenes are generally insoluble in water mainly because they are

41. Incomplete combustion of alkanes may produce dangerous because

42. Propene and cyclopropane form a mixture that gives of on complete combustion. The mixture consumes of on catalytic hydrogenation. The moles of cyclopropane are

43. Methane, ethene, and ethyne form a mixture that gives of on complete combustion. Complete hydrogenation of the same mixture consumes of . The moles of methane in the mixture are

44. A reaction planner wants to prepare as one of the major ring-substitution products. The starting aromatic compound and reagent set most consistent with this goal is

45. Complete combustion of of an open-chain alkane requires of . The alkane is

46. The best reason dry ether is specified in Wurtz reaction is that

47. A table compares possible products from monosubstituted benzene derivatives.

The entry that needs correction is

48. Polynuclear aromatic hydrocarbons are best described as aromatic compounds that contain

49. In butane, the conformations commonly compared are obtained by rotation mainly around the

50. A hydrocarbon gives and in equimolar amounts on reductive ozonolysis. If of is ozonolysed completely, the total moles of carbonyl products formed are