Exam-Style Mock Test | Chapter: Classification Of Elements
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Classification of Elements and Periodicity in Properties Mock Test – Class 11 Chemistry

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Classification of Elements and Periodicity in Properties – Progressive Test

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1. Assertion: Actinoids are generally treated with awareness that many of them are radioactive.
Reason: Actinoids belong to the period inner-transition series associated mainly with filling.

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2. The main reason for classifying elements is to make the study of elements more systematic by grouping them according to similarities and trends. What does this achieve most directly?

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3. Consider the statements about blocks.
I. -block elements generally belong to groups and .
II. -block elements generally occupy groups to .
III. -block elements are associated with groups to .
IV. -block elements are the same as the halogen family.
The supported statements are

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4. A compound is an acidic oxide, and oxygen is assigned oxidation state . The oxidation state of is

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5. The high reactivity of alkali metals is best connected with their

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6. Use the arrangement described below: Element boxes are placed in rows and columns. Moving left to right along a row increases stepwise, while moving downward in one column keeps elements in the same family. This description identifies

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7. A claim states, “Second-period elements cannot show group similarity because they behave anomalously.” The best evaluation is that the claim is

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8. Mendeleev's approach was stronger than a simple increasing-mass list because it

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9. Match the cause in Column I with the consequence in Column II.

Column I Column II
P. Small atomic size 1. Stronger polarizing power or high charge density in some cases
Q. High electronegativity 2. Stronger attraction for bonding electrons
R. Absence of -orbitals 3. Restricted expansion of covalency
S. Similar diagonal charge/radius ratio 4. Partial similarity between diagonal pairs

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10. A data card for magnesium gives the symbol , atomic number , and atomic mass about . For placing magnesium in the modern periodic table, the most fundamental entry is

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11. In the modern view, is placed before because

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12. The table shows some claims about Newlands' law of octaves. Identify the row that needs correction.

Row Claim
P Elements were arranged in increasing order of atomic mass.
Q Every eighth element was expected to show similarity with the first.
R The law worked well for all elements including very heavy elements.
S The law used an analogy with musical notes.

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13. A third-period element such as sulfur can show higher covalency than oxygen in suitable compounds. The most suitable explanation is that sulfur

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14. A pair of isotopes has the same but different mass numbers. The modern periodic law places them in the same position because

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15. Assertion: The maximum covalency of oxygen is lower than that of sulfur in common basic-level periodicity discussions.
Reason: Oxygen is a second-period element without valence -orbitals, while sulfur is a third-period element.

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16. A period oxide sequence is written as , , , , , , and . The general change in acidic character along this sequence is

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17. A group of representative elements forms hydrides of the type and oxides of the type . This formula pattern most strongly suggests that the elements belong to

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18. For a neutral atom with atomic number , this number is central to periodic classification because it fixes

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19. Consider the statements about metals, non-metals, and metalloids in the periodic table.
I. Metals occupy much of the left and central part of the table.
II. Non-metals are concentrated mainly toward the upper right.
III. Metalloids commonly lie along a zig-zag boundary.
IV. All elements in the -block are metals.
The supported statements are

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20. The oxide is best described as

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21. The table connects periodic position with likely bonding character.

Row Periodic situation Likely bonding tendency
P Group metal with group non-metal High ionic character
Q Two similar non-metals from the right side Covalent character
R Large electronegativity difference High ionic character
S Very small electronegativity difference Compulsory full ionic transfer in every case

The row that needs correction is

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22. A mixed trend comparison gives four statements.
I. is larger than .
II. has higher first ionization enthalpy than .
III. is more electronegative than .
IV. is more strongly basic than .
The supported statements are

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23. A graph is described as follows.

The x-axis shows increasing atomic number . The y-axis shows a property that rises and falls in a repeating pattern as new periods begin and end.

The graph description is best interpreted as showing

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24. Consider the statements about Newlands' law of octaves.
I. It used increasing atomic mass as the arranging basis.
II. It succeeded mainly for lighter elements.
III. It deliberately left gaps for undiscovered elements and predicted their properties.
IV. It sometimes placed dissimilar elements together.
The supported statements are

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25. The row that best explains why carbon commonly forms strong multiple bonds compared with silicon is

Row Explanation
P Carbon has compact -orbitals that overlap effectively.
Q Carbon has -orbitals available for multiple bonding.
R Silicon and carbon have identical atomic sizes.
S Silicon has no valence-shell orbitals.

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26. A data set shows that atomic radius generally decreases from to , then becomes large again at . This pattern is best described as

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27. The family name chalcogens is commonly associated with

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28. A configuration note mentions filling along with outer electrons. The safest classification is

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29. The highest first ionization enthalpy in a period is generally shown by a noble gas because it has

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30. A note says: “The unknown element below boron should resemble boron in some group properties but should not be identical to boron.” This statement is chemically sound because elements in a group

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31. Match the period with its usual number of elements in the long-form periodic table.

Column I Column II
P. Period 1.
Q. Period 2.
R. Period 3.
S. Period 4.

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32. A compact family-description card says: “Group elements generally form ions; group elements commonly form ions.” The difference is mainly due to

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33. The table gives successive ionization enthalpies for three elements in arbitrary units.

Element
P
Q
R

The element most likely having two valence electrons is

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34. Diagonal relationship refers to similarity between certain elements that are

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35. The row with the most suitable block assignment is

Row Configuration ending Assigned block
P -block
Q -block
R -block
S -block

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36. A configuration ends in . Without identifying the element by name, its period can be determined as

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37. For the configuration , the claim “it is in group because the shell number is ” is best evaluated as

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38. Assertion: Elements with valence-shell configurations and are placed in the same group.
Reason: Both have the same highest principal quantum number .

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39. A record of period lengths is given below.

Period Number of elements
P First period:
Q Second period:
R Third period:
S Fourth period:

The row that needs correction is

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40. Consider the statements below.
I. Mendeleev left gaps for undiscovered elements.
II. He predicted properties of elements such as eka-aluminium and eka-silicon.
III. He placed noble gases by removing all alkali metals.
IV. He used chemical properties to support placement decisions.
The supported statements are

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41. The oxidation state of phosphorus in , taking chlorine as , is

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42. Assertion: is smaller than , although both have electrons.
Reason: has a greater nuclear charge than , so it pulls the same number of electrons more strongly.

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43. A graph is described below.

On the x-axis, elements are arranged in increasing atomic number. The y-axis shows a property that decreases across one period, then rises sharply at the beginning of the next period, and again decreases across that period.

This graph most likely represents a periodic trend because

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44. An element has the configuration ending . The safest block assignment is

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45. Consider the statements about hydrides and oxides as periodic indicators.
I. Hydride formulae can reflect valency patterns.
II. Oxide formulae can help infer oxidation state.
III. Similar oxide and hydride formulae were useful in Mendeleev's grouping.
IV. Hydride formulae always prove that two elements are isotopes.
The supported statements are

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46. The row with the most suitable -block family identification is

Row Valence-shell configuration Family or group idea
P group , halogen family
Q group , halogen family
R group , boron family
S group , noble gases

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47. A limitation of Newlands' law becomes clear when it is applied to elements heavier than calcium because

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48. Group elements are often discussed with possible oxidation states and . The reason this group can show both signs in simple periodic discussion is that its atoms have

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49. A set of elements forms oxides with similar formula patterns and also shows related chemical behaviour. In Mendeleev's classification, this evidence would mainly support

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50. Use the short passage below.

Element is very small, has no available -orbitals in its valence shell, and forms compounds in which its covalency does not exceed . Its heavier group member can form compounds with higher covalency under suitable conditions.

The most suitable inference is that is likely a

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