Gravitation Mock Test – Class 11 Physics

1. A satellite at orbital radius has gravitational acceleration . For a circular orbit, this acceleration must equal

2. The negative sign in mainly indicates that

3. A body is projected from a planet with a speed greater than the escape speed. In the ideal case, it will

4. A formula sheet writes the unit of gravitational potential as . The correct repair is

5. The following statements refer to gravitational potential and field.
I. Potential is a scalar quantity.
II. Field is a vector quantity.
III. A steeper graph means a larger field magnitude at that region.
The suitable choice is

6. The proportionality form of Newton’s law of gravitation is completed as

7. The escape speed from a planet does not depend on the direction of projection in the ideal model because

8. A book resting on a table experiences Earth’s gravitational pull downward and the table’s normal reaction upward. The gravitational force differs from the normal reaction because gravitational force

9. The graph of total mechanical energy for a projectile launched from Earth is used to classify its motion. If , , and , the corresponding ideal cases are

10. A small artificial satellite keeps moving around Earth instead of travelling in a straight line because

11. A satellite has period in a circular orbit of radius around a planet of mass . If another planet has mass and a satellite moves in a circular orbit of the same radius , its period is

12. A formula-use check gives the following pairs.
I. , attractive along the joining line.
II. , circular orbital speed.
III. , escape speed.
IV. , circular-orbit period.
The pair or pairs needing correction are

13. In a uniform solid Earth model, the gravitational potential is most negative at

14. The constant for circular satellites around the same planet is

15. A student applies at a point inside a uniform solid Earth with , using the full Earth mass . The correct repair is to use

16. For a satellite in a circular orbit, its gravitational potential energy is and its kinetic energy is . Therefore,

17. A graph is drawn with on the vertical axis and on the horizontal axis for circular satellites around one planet. The slope of the straight line is

18. Four equal masses are placed at the corners of a square of side . A mass is placed at the centre. If one corner mass is removed, the magnitude of the net force on becomes

19. Two satellites move in circular orbits of the same radius , one around planet of mass and one around planet of mass . The ratio is

20. A satellite orbits Earth in a circle at radius . If a near-surface circular orbital speed is , the satellite’s orbital speed is

21. A graph is drawn for a fixed arrangement of several source masses. The horizontal axis is the test mass , and the vertical axis is the net gravitational force magnitude on it. If the source masses and distances are unchanged, the graph should be

22. The total mechanical energy of a satellite in a circular orbit is

23. A gravitational field around a body means a region where another mass

24. In a circular satellite orbit, the acceleration is toward Earth’s centre while the velocity is tangential. The angle between acceleration and velocity is

25. Using and , the speed of a geostationary satellite is closest to

26. A graph of total mechanical energy of a circular satellite orbit against orbital radius is described. The curve lies below the -axis and approaches as increases. This matches

27. In the equality , the cancellation of means that

28. A planet has uniform density and radius . Its surface gravity is

29. Taking and , the time period of a satellite just above Earth’s surface is closest to

30. A common statement says, “Tides happen because the Moon pulls only the water nearest to it.” The best correction is that the Moon

31. Assertion: The gravitational field inside a thin uniform spherical shell is zero everywhere. Reason: At an interior point, vector contributions from different parts of the shell cancel due to spherical symmetry.

32. The following table compares force and field for a test mass near a source mass .

The table shows that

33. A planet has the same mass as Earth but half Earth’s radius. Its surface gravity is

34. A nearly circular planetary orbit may still be treated as a special case of Kepler’s first law because

35. A satellite moves in a circular orbit with speed at radius . Its centripetal acceleration is closest to

36. A body is taken from the surface of a planet to a point where the escape speed is half the surface escape speed. The height above the surface is

37. Using , Earth’s escape speed can also be written as

38. A planet has times Earth’s mass and times Earth’s radius. If Earth’s escape speed is , the planet’s escape speed is

39. A note says, “A planet in a larger orbit has a longer period because , so doubling doubles .” The useful correction is that doubling makes

40. A student claims, “A geostationary satellite stays fixed because Earth’s gravity is zero at that height.” The best evaluation is that the claim is

41. A planet has uniform density . At a point inside it at distance from the centre, the gravitational field is

42. Kepler’s second law states that the line joining a planet and the Sun sweeps out

43. A mixed calculation gives for a satellite at some height above Earth. The corresponding centre-distance and height are

44. Two metal spheres are placed far apart in deep space, away from other bodies. Their mutual gravitational force is best described as

45. A circular satellite orbit has . After a maneuver, the satellite just escapes from the same radius. The minimum extra energy supplied by the engine is

46. Assertion: A planet in an elliptical orbit moves faster when it is nearer the Sun. Reason: The line joining the planet and the Sun sweeps equal areas in equal time intervals.

47. At a height above Earth’s surface, the distance from Earth’s centre to a body is

48. The formula used to find the orbital radius of a geostationary satellite is based on

49. A passage says: “A spacecraft at radius has . Therefore it can escape because gravity exactly provides centripetal force.” The missing condition is that escape from the same radius requires

50. A circular satellite has period and total energy . Another satellite of the same mass around the same planet has period . Its total energy is