Biomolecules Mock Test – Class 12 Chemistry
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Biomolecules Mock Test – Class 12 Chemistry

Progressive Test — Guest First Round

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Biomolecules – Progressive Test

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1. Assertion: Starch and cellulose give glucose on complete hydrolysis but show different digestibility in humans.
Reason: Starch contains mainly -glycosidic linkages, whereas cellulose contains glycosidic linkages that human digestive enzymes cannot efficiently hydrolyse.

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2. A single linear polynucleotide chain contains nucleotide residues. The combined number of --glycosidic bonds and phosphodiester bonds in the intact chain is . Nine phosphodiester bonds are then hydrolysed. Find the original nucleotide count and the number of phosphodiester bonds remaining.

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3. Glycogen differs from amylopectin mainly because glycogen:

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4. The condition that enables fructose to reduce Tollens or Fehling reagent is mainly:

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5. A short carbohydrate chain contains four monosaccharide units joined by condensation. The whole chain and each incorporated monosaccharide unit are best described, respectively, as:

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6. Match each structural feature in Column I with its suitable protein-structure description in Column II.

Column I Column II
P. Exact residue sequence 1. Primary structure
Q. Regular coiled backbone 2. -Helix
R. Extended aligned segments 3. -Pleated sheet
S. Parallel or antiparallel arrangement 4. Feature of a -sheet

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7. Match the number of independent stereogenic centres in Column I with the corresponding maximum stereoisomer count in Column II, assuming no symmetry reduction.

Column I Column II
P. 1.
Q. 2.
R. 3.
S. 4.

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8. The equation representing mild oxidation of glucose to gluconic acid is:

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9. Consider the following claims.
Statement I: A non-reducing sugar must contain no oxygen atoms.
Statement II: Some RNA molecules can act as catalysts.
Statement III: Excessive intake of some fat-soluble vitamins may cause accumulation-related toxicity.
Statement IV: Hormones regulate cells by changing equilibrium constants through direct catalytic action.
The acceptable statements are:

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10. A patient has normal digestive-enzyme production and adequate vitamin intake, but a gland releases too little of a blood-borne messenger that normally binds receptors on distant tissues. Which conclusion is most appropriate?

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11. Assertion: Complementary base pairing enables a nucleic-acid strand to guide formation of another strand with a related sequence.
Reason: Each base shows selective pairing with a suitable complementary base.

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12. Glucose, fructose and mannose form the same osazone mainly because:

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13. Read the situation below and answer the question.
A globular enzyme is heated briefly. Its amino-acid sequence remains unchanged, and analysis shows no release of free amino acids. However, several -helical regions unfold, the active-site residues no longer have their original spatial arrangement and catalytic activity is lost.
The best interpretation is:

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14. Match each glycogen feature in Column I with its suitable consequence in Column II.

Column I Column II
P. Frequent branching 1. Compact glucose storage
Q. Many non-reducing ends 2. Rapid simultaneous enzyme action
R. Liver storage 3. Support of blood-glucose availability
S. Muscle storage 4. Local energy supply

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15. The row in which the disaccharide, constituent monosaccharides, glycosidic linkage and reducing behaviour are all correctly stated is:

Option Disaccharide Constituent units Glycosidic linkage Behaviour
A Lactose Galactose and glucose Reducing
B Maltose Two glucose units Reducing
C Sucrose Glucose and fructose Reducing
D Lactose Galactose and glucose Reducing

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16. A standard B-DNA molecule contains approximately complete helical turns. Use base pairs per turn and rise per base pair. What are its approximate axial length and total nucleotide count?

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17. Assertion: A denatured enzyme may retain its amino-acid sequence but lose catalytic activity.
Reason: Disruption of higher structure can alter the shape and chemical environment of its active site.

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18. D-Glucose and D-mannose are related as:

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19. An open-chain monosaccharide has six carbon atoms and its carbonyl group is located at . It is classified as:

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20. A mixture contains nucleotide units. DNA nucleotides constitute of the mixture and belong to double-stranded DNA in which adenine forms of the DNA nucleotides. The remaining units are single-stranded RNA nucleotides with . What is the sum of the total hydrogen bonds in the DNA portion and the number of -hydroxyl groups in the RNA portion?

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21. The open-chain structure contains:

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22. A graph of specific rotation against time is recorded after pure -D-glucose is dissolved in water. The curve starts at a high positive value, decreases gradually and reaches a constant plateau. The plateau represents:

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23. Assertion: The open-chain structural framework of glucose can have a maximum of stereoisomers.
Reason: Open-chain glucose contains only three independent stereogenic centres.

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24. The cyclic form produced by interaction of the hydroxyl group with the aldehyde group of glucose is called glucopyranose because it contains:

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25. Sample P contains nucleotides, of which are ribonucleotides and contain purines. Sample Q contains nucleotides, of which are ribonucleotides and contain purines. After mixing P and Q, determine the total moles of -hydroxyl groups and nitrogenous rings.

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26. Consider the following statements about maltose.
Statement I: It contains an glycosidic linkage.
Statement II: It is a reducing disaccharide.
Statement III: Both anomeric carbons are involved in the glycosidic bond.
The acceptable statements are:

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27. A sample contains glucose, vitamin C, glycine and starch. The macromolecule in this set is:

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28. Classify the monosaccharide represented by :

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29. Evaluate the following statements about -pleated sheets.
Statement I: Their backbone segments may be parallel or antiparallel.
Statement II: Their side chains commonly alternate above and below the sheet.
Statement III: They are stabilised only by covalent peptide bonds between neighbouring strands.
The acceptable statements are:

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30. A vitamin deficiency lowers the activity of several enzymes even though the enzyme proteins are still being synthesised normally. A suitable explanation is that the vitamin:

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31. For a linear carbohydrate containing monosaccharide residues, the number of water molecules required for complete hydrolysis is:

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32. A molecule contains one tetrahedral carbon bonded to four different substituents and has no internal symmetry that removes chirality. Pure mirror-image forms of this molecule are expected to:

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33. Maltose shows both mutarotation and reducing behaviour, whereas sucrose shows neither. The common structural reason for this difference is that maltose:

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34. Evaluate the following statements.
Statement I: Formation of a glycosidic bond is a condensation process.
Statement II: Hydrolysis of a glycosidic bond consumes water.
Statement III: Every molecule containing a glycosidic bond is necessarily non-reducing.
The acceptable statements are:

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35. Reduction of the carbonyl group of glucose produces:

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36. A patient has megaloblastic anaemia caused by inadequate availability of a cobalt-containing vitamin. The deficient vitamin is:

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37. In the hydrolysis of a peptide bond, water provides:

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38. Two stereoisomeric sugars that differ in configuration at exactly one stereogenic carbon are called:

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39. Three biomolecules are described below.
Molecule P is a polymer whose sequence stores hereditary information.
Molecule Q is a small non-polymeric substance that assists biochemical regulation.
Molecule R is a polymer of amino-acid residues and may act as a catalyst.
The identities of P, Q and R, respectively, are:

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40. Ribose and glucose are placed in different carbon-number classes because:

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41. Excessive long-term intake is more likely to cause accumulation-related toxicity for fat-soluble vitamins because they:

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42. A nucleotide is formed from:

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43. The open-chain structure most suitable for D-fructose is:

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44. Vitamin A is most directly associated with:

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45. Lactose yields on complete hydrolysis:

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46. A single linear cellulose chain contains glucose residues. Complete hydrolysis of every glycosidic linkage in this chain consumes:

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47. Assertion: For one connected acyclic glycogen molecule containing glucose residues, branching does not change the total glycosidic-linkage count from .
Reason: Changing an connection into an branch connection changes the linkage type but not the number of connections required to join residues in one acyclic molecule.

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48. The correctly completed comparison is:

Option DNA RNA
A Protein polymer Carbohydrate polymer
B Always catalytic Never carries information
C Main hereditary material in most organisms May perform informational, structural, catalytic or adaptor roles
D Made from amino acids Made from monosaccharides only

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49. A patient has severely impaired absorption of dietary fats. The vitamins whose absorption is most directly at risk are:

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50. Four unknown biological substances give the observations below.

Substance Observation
P Hydrolysis yields amino acids; heating destroys activity without releasing free amino acids
Q Hydrolysis yields ribose, phosphate and nitrogenous bases including uracil
R Hydrolysis yields only glucose; the polymer contains linkages
S Required in small amounts; prolonged excessive intake may cause accumulation in adipose tissue

The correct identification is:

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