Amines Mock Test – Class 12 Chemistry
GKaim: Measure | Improve | Achieve

Amines Mock Test – Class 12 Chemistry

Progressive Test — Guest First Round

0%

Amines – Progressive Test

Welcome to the Progressive Test.

Click Start Test to begin the loaded practice round.

Good luck!

1 / 50

1. When aniline is first treated with concentrated sulphuric acid at room temperature, the principal initial product is:

2 / 50

2. The nitrogen atom of aniline tends to be more nearly planar than the nitrogen atom of a typical alkylamine because planarity:

3 / 50

3. Three reaction vessels are arranged as follows.
Vessel P contains -dimethylaniline with its para position free.
Vessel Q contains -methyl--dimethylaniline.
Vessel R contains trimethylamine.
All three are treated separately with cold nitrous acid under conditions suitable for their standard reactions. The principal outcomes for P, Q, and R, respectively, are:

4 / 50

4. A graph plots the wavelength of maximum absorption, , against the extent of conjugation in a related series of azo compounds. Which broad trend is most reasonable?

5 / 50

5. Complete the overall diazotisation equation:

The missing coefficient is:

6 / 50

6. The equilibrium representing the basic behaviour of a neutral amine in water is:

7 / 50

7. Nitrous acid is supplied in an amount of , and increasing amounts of a primary aliphatic monoamine are added. A graph plots the volume of dry nitrogen produced at STP against moles of amine added. Assuming quantitative reaction and at STP, the graph is described by:

8 / 50

8. A mixture of of triethylamine and of bromoethane is heated to form tetraethylammonium bromide. The limiting reagent reacts completely, but only of the salt formed is isolated. Using molar masses , , and , respectively, the isolated salt mass and the mass of unreacted triethylamine are:

9 / 50

9. In the secondary-amine Hinsberg reaction, the missing product is identified from:

10 / 50

10. A sample of aniline is treated with bromine water. The chemical conversion to -tribromoaniline is , and the product is isolated in yield. Using and , the isolated product mass is:

11 / 50

11. Match each factor in Column I with its principal effect in Column II.

Column I Column II
P. Positive inductive effect 1. Can reduce hydration of a bulky conjugate acid
Q. Hydration 2. Raises electron density at nitrogen
R. Steric crowding 3. Stabilises the protonated amine in water
S. Gas phase 4. Removes solvent stabilisation from the comparison

12 / 50

12. A tertiary amine contains propyl, ethyl, and methyl groups directly attached to nitrogen. The preferred parent and substituent arrangement is:

13 / 50

13. Use the arrangement described below. A nitrogen atom lies at the centre of four approximately tetrahedral electron-domain directions. Three directions contain bonded atoms, while the fourth contains no atom. The fourth direction contains:

14 / 50

14. The mixture contains methylamine and dimethylamine. Complete neutralisation requires of hydrochloric acid. When a separate identical mixture is treated with excess nitrous acid, of nitrogen is obtained at STP. Assuming at STP, the amounts of methylamine and dimethylamine and the mass percentage of methylamine are:

15 / 50

15. The structure is named:

16 / 50

16. For a conjugate pair at a fixed temperature, the correct relation is:

17 / 50

17. A graph plots moles of trimethylammonium nitrite and moles of nitrogen gas against moles of nitrous acid added to of trimethylamine. Under ordinary cold conditions, the graph shows:

18 / 50

18. Acylation of an amine generally makes the nitrogen less nucleophilic because:

19 / 50

19. Base P has , while base Q has . Which comparison is correct?

20 / 50

20. Assertion: Nitrogen gas is evolved during Sandmeyer chlorination of benzenediazonium chloride.
Reason: The diazonium group leaves as stable molecular nitrogen while chlorine replaces it on the aromatic ring.

21 / 50

21. Complete conversion of a methylamine–propan--amine mixture gives the corresponding -acetyl derivatives. The total product mass is . Each mole of amine gains during acetylation. Using amine molar masses and , respectively, the amounts of methylamine and propan--amine are:

22 / 50

22. Compare the predicted reactions below.

Row Secondary amine Predicted nitrous-acid product Rapid evolution
P No
Q No
R No
S Yes

The valid rows are:

23 / 50

23. Benzamide is treated successively with , cold , and . The principal final product is:

24 / 50

24. Among the following compounds, the one that is not an amine is:

25 / 50

25. An unknown amine forms no sulphonamide with Hinsberg reagent, remains unreacted in excess alkali, and dissolves when dilute acid is added. The amine is:

26 / 50

26. Catalytic hydrogenation of nitrobenzene to aniline may be carried out using:

27 / 50

27. In Hoffmann bromamide degradation, the primary amine product contains ______ carbon atom than the starting primary amide.

28 / 50

28. The valid amide-reduction pair is:

29 / 50

29. The preferred conditions for preparing a primary alkylamine by ammonolysis of a haloalkane are:

30 / 50

30. Consider the following statements about amine nomenclature.
Statement I: An -locant shows that a substituent is attached directly to nitrogen.
Statement II: A numerical carbon locant identifies a position on the selected parent chain.
Statement III: Two identical substituents on nitrogen may be written using -notation.
Select the applicable combination.

31 / 50

31. An organic mixture of mass contains aniline and a neutral compound. The aniline is completely extracted as its hydrochloride, regenerated with base, and isolated. The recovered aniline has a mass of , corresponding to an overall recovery. The original mass percentage of aniline and the minimum volume of hydrochloric acid required for extraction are:

32 / 50

32. Compare the diazonium conversions below.

Row Diazonium replacement Carbon-count consequence
P replaced by One carbon added
Q replaced by Carbon count unchanged
R replaced by One carbon removed
S replaced by Aromatic ring destroyed

The valid rows are:

33 / 50

33. -Bromopropane is converted into butanenitrile, which is hydrolysed to butanoic acid. The acid is converted into butanamide, and the amide undergoes Hoffmann degradation. The final product and its carbon count are:

34 / 50

34. Aniline, , is acetylated quantitatively. The resulting acetanilide is nitrated using of nitric acid, of which only reacts. Assume one mole of nitric acid produces one mole of mononitroacetanilide, of the nitrated material is the para isomer, and hydrolysis of that isomer gives -nitroaniline in yield. Using and , the final product mass is:

35 / 50

35. A mixture contains a primary, a secondary, and a tertiary amine. A suitable Hinsberg separation sequence is:

36 / 50

36. In an arenediazonium ion, the charge on the group is ______.

37 / 50

37. Match each name in Column I with the corresponding structure in Column II.

Column I Column II
P. -Methylethanamine 1.
Q. -Dimethylethanamine 2.
R. -Ethylpropan-1-amine 3.
S. -Ethyl--methylpropan-1-amine 4.

38 / 50

38. A graph shows against moles of strong acid added during titration of a weak amine solution. Which feature is expected at the equivalence point?

39 / 50

39. A reaction mixture contains of aniline, of ethanoyl chloride, and of sodium hydroxide. Only of the ethanoyl chloride reacts, all the acetanilide formed is isolated, and hydrolysis of unreacted ethanoyl chloride is neglected. Using molar masses , , , and , respectively, the mass of acetanilide formed and the mass of sodium hydroxide remaining are:

40 / 50

40. Evaluate the three statements below.
Statement I: Ammonia is not classified as a primary amine because no carbon group is bonded to nitrogen.
Statement II: A species of the form is a quaternary ammonium ion.
Statement III: Every tertiary amine must contain three bonds.
Select the applicable combination.

41 / 50

41. Examine the predicted carbylamine-test results below.

Row Amine Predicted result
P Formation of
Q Formation of
R Formation of
S Negative test

The valid rows are:

42 / 50

42. Ethyldimethylamine, , is classified as:

43 / 50

43. An unknown amine has molecular formula . It gives a positive carbylamine test. With cold nitrous acid it evolves nitrogen and produces an alcohol that is oxidised to propanone. The unknown amine is:

44 / 50

44. Match each preparation route in Column I with its carbon-count feature in Column II.

Column I Column II
P. Haloalkane nitrile amine 1. Carbon count unchanged
Q. Primary amide amine 2. One carbon added
R. Nitro compound amine 3. One carbon removed
S. Amide amine 4. Carbonyl carbon retained as a methylene carbon

45 / 50

45. Assertion: Diethylamine is a simple amine even though it is secondary.
Reason: The terms simple and secondary refer to different structural features.

46 / 50

46. Use the inversion pathway described below. A pyramidal amine begins with nitrogen above the plane defined by its three substituents, passes through an intermediate arrangement, and ends with nitrogen below that plane. The correct interpretation is:

47 / 50

47. Match each name in Column I with its structural description in Column II.

Column I Column II
P. -Methylaniline 1. Methyl group directly bonded to nitrogen
Q. -Methylaniline 2. Methyl group para to
R. -Methylaniline 3. Methyl group ortho to
S. -Methylaniline 4. Methyl group meta to

48 / 50

48. A tertiary amine has three different carbon groups attached to a pyramidal nitrogen atom. It is usually difficult to isolate its two mirror-image forms at room temperature because:

49 / 50

49. Examine the Hoffmann-degradation products below.

Row Starting primary amide Assigned primary amine
P
Q
R
S

The valid row is:

50 / 50

50. The pair containing a common name followed by its corresponding IUPAC name is:

Your score is

Share your achievement!

LinkedIn Facebook
0%

Complete 100% of the Progressive Test coverage to unlock Mistake Review.
Complete 100% of the Progressive Test coverage to unlock Certificate Challenge.

Subscribe
Notify of
guest
0 Comments
Scroll to Top