Home» Online Test » Civil Engineering » Mechanics of Materials & Structures Online Test » Paper 1 » Paper 2 » Paper 3 0% Sorry, time's up. To complete the online test, please restart it. Created by Vikash chaudhary This is a FREE online test. Beware of scammers who ask for money to attend this test. Total Questions: 20 Time Allotted: 30 minutes Passing Score: 40% Randomization: No Certificate: No Do not refresh the page! 👍 All the best! 1 / 20 1. *The forces which meet at one point, but their lines of action do not lie in a plane, are called: a) co-planer non-concurrent forces b) non-coplanar concurrent forces c) non-coplanar non-concurrent forces d) none of the above 2 / 20 2. *The velocity of a moving body is: a) A vector quantity b) A scalar quantity c) A constant quantity d) None of the above 3 / 20 3. *Hooke's law holds good up to: a) Yield point b) Plastic limit c) Elastic limit d) Breaking point 4 / 20 4. *Moment of inertia of an object having rectangular section of 'b' as width and 'd' as depth is given by: a) bd^3/12 b) bd^2/24 c) b^2d^2/12 d) db^3/24 5 / 20 5. *The unit failure stress is taken as : a) rupture stress b) ultimate stress c) failure stress d) fracture stress 6 / 20 6. The stress in the member subjected to a force is a) continued deformation under sustained loading b) load per unit area c) the resistance offered by the material per unit area to a force d) the strain per unit length 7 / 20 7. *Proof resilience is the greatest stored energy at a) limit of proportionality b) elastic limit c) plastic limit d) yield point 8 / 20 8. The strain energy stored by a member when strained within the elastic limit is known as a) resilience b) proof resilience c) potential strain d) none of the above 9 / 20 9. Strain energy of a member may be defined as work done on it a) to deform it b) to resist elongation c) to resist shortening d) all of the above 10 / 20 10. What is strain energy? a) stress x strain b) volume x stress x strain c) energy that is spent for straining a body d) energy stored in a body because of being strained 11 / 20 11. The beam strongest in flexure will have the maximum a) moment of inertia b) section modulus c) area of cross-section d) none of the above 12 / 20 12. The radius of gyration of a rectangular section is not proportional to a) the square root of the moment of inertia b) the square root of the inverse of the area c) the square root of the moment of inertia divided by the area of the section d) none of the above 13 / 20 13. The square root of the ratio of moment of inertia and cross-section area of the member is known as a) least lateral dimension b) second moment of inertia c) radius of gyration d) section modulus 14 / 20 14. The moment of inertia of an area will be least with respect to a) central axis b) horizontal axis c) vertical axis d) none of the above 15 / 20 15. A body having similar properties throughout a) homogeneous b) isomorphic c) isotropic d) anisotropy 16 / 20 16. *The simple bending equation is a) M/y = σ/I = E/R b) M/I = σ/y = E/R c) M/R = σ/y = E/R d) none of the above 17 / 20 17. Along the neutral axis of a simply supported beam a) fibers do not undergo strain b) fibers undergo very little strain c) the fibers are subjected to maximum stress d) none of the above 18 / 20 18. In simple bending theory, the assumption that a plane section before bending remains plane after bending implies that a) stress is proportional to strain at all sections b) strain is proportional to the distance from the neutral axis c) stress is uniform in the cross-section d) none of the above 19 / 20 19. *The relation between the radius of curvature (R), bending moment (M), and flexural rigidity (EI) is given by a) M = EI/R b) M = E/IR c) EI = R/M d) MI/R = E 20 / 20 20. The relation between deflection (y) and bending moment (M) is a) M = EI(dy/dx) b) M =-EI(d²y/dx²) c) M = EI(d²y/dx] d) none of the above Your score is Share your achievement! LinkedIn Facebook Twitter 0% Restart Test Please provide your feedback. Thank you for your valuable feedback. Send feedback Share the above MCQs:Click to share on Facebook (Opens in new window)Click to share on WhatsApp (Opens in new window)Click to share on X (Opens in new window)Click to share on LinkedIn (Opens in new window)Click to share on Reddit (Opens in new window)