Surveying Online Test - Paper 3 » Winning Questions
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Surveying Online Test – Paper 3

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Created by 83a36dcfd5c4caff12bc80f0020c9c749e12cbbbdb7c406dc1dd39996cb85836?s=32&d=monsterid&r=g gkaimVikash chaudhary

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  • Total Questions: 50
  • Time Allotted: 50 minutes
  • Passing Score: 70%
  • Randomization: Yes
  • Certificate: Yes
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1. In a closed traverse, the algebraic sum of deflection angles is

2 / 50

2. In a closed traverse,

3 / 50

3. The contour lines merge or cross one another on the map in the case of

4 / 50

4. The area of the earth's surface is taken into account only if the extent of the survey is more than

5 / 50

5. If the distance between two points A and B is 1km, the combined correction for curvature and refraction will be

6 / 50

6. The resection by a two-point problem as compared to the three-point problem:

7 / 50

7. In the case of a telescopic alidade, the adjustment done is

8 / 50

8. The levels to which the earthwork will have to be carried out is known as

9 / 50

9. The angular error of closure or summation error should not exceed (Where N is the number of stations or sides.)

10 / 50

10. It is more difficult to obtain good results while measuring the horizontal distance by the stepping method

11 / 50

11. The direct method of contouring is

12 / 50

12. If the magnetic declination is (-)6°0' and the reduced bearing of a line is S40°01'E, the true bearing of the line is

13 / 50

13. The magnetic declination at a place is 7°20' W, the bearing given by the compass is S45°40'E, the true bearing of the place is

14 / 50

14. The perpendicular distance of the midpoint of the line from the reference meridian is known as

15 / 50

15. *Total station is

16 / 50

16. The quadrantal bearing of a line is determined by:

17 / 50

17. The needle is adjusted for

18 / 50

18. If the sum of northing of a traverse exceeds the sum of southing by 2m and the sum of easting exceeds the sum of westing by 2m, the resulting closing error will be

19 / 50

19. The main difference between an optical square and a prism square is

20 / 50

20. A 30m chain was found to be 20cm too long after chaining 1500m. The correct length of the total distance chained will be

21 / 50

21. The angle which the true meridian makes with the magnetic meridian is called

22 / 50

22. The three-point problem can be solved by:

23 / 50

23. If the staff is held vertical and the angle of elevation and depression are kept the same, then the horizontal distance between the instrument and staff station computed by observation will be

24 / 50

24. The quadrantal system confines the user to measure the bearings from

25 / 50

25. The contour lines are perpendicular to the

26 / 50

26. For a dumpy level in perfect adjustment, the horizontal cross hair should be in a plane

27 / 50

27. A relatively fixed point of known elevation above the datum is called

28 / 50

28. In the direct method of contouring, the process of locating points lying on a contour is known as

29 / 50

29. The RL of the benchmark is 1000.0 m, and the back sight reading at the benchmark is 2.555 m. Find the staff reading of IS if the RL of IS is 1000.055 m

30 / 50

30. Parallax may be eliminated by

31 / 50

31. The rise and fall method of leveling provides a complete check on

32 / 50

32. In tacheometric survey, the method which provides easy reading of the staff is

33 / 50

33. A bearing noted N45° E represents

34 / 50

34. The two-point problem as compared to the three-point problem is:

35 / 50

35. The types of instrument generally used in the survey of gravity water supply system are:

36 / 50

36. The permissible limits of error in chaining for measurement on rough or hilly ground are

37 / 50

37. The minimum horizontal distance between any two consecutive contours is known as

38 / 50

38. In compass surveying

39 / 50

39. If the image formed by the objective of the telescope is not in the plane of crosshairs, it is called

40 / 50

40. Hydrographic survey deals with the mapping of

41 / 50

41. The height of instrument method is

42 / 50

42. A Cadastral Map is a map having

43 / 50

43. The chord of curve less than peg interval is known as

44 / 50

44. An offset scale always has the zero mark at

45 / 50

45. The dip of the needle

46 / 50

46. If the bearing of AB is N 30° W and the bearing of BC is N 40° E, then find the angle < ABC

47 / 50

47. Pick up the odd statement

48 / 50

48. "A curve of varying radius introduced between two branches of a compound curve is called

49 / 50

49. The tie line is run through the survey to

50 / 50

50. Limiting the length of offset depends upon

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