Surveying Online Test - Paper 3 » Winning Questions
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Surveying Online Test – Paper 3

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Created by 83a36dcfd5c4caff12bc80f0020c9c749e12cbbbdb7c406dc1dd39996cb85836?s=32&d=monsterid&r=g gkaimVikash chaudhary

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  • Total Questions: 50
  • Time Allotted: 50 minutes
  • Passing Score: 70%
  • Randomization: Yes
  • Certificate: Yes
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1. If the sights are vertical

2 / 50

2. Contours are used to determine

3 / 50

3. In a prismatic compass,

4 / 50

4. The contour lines merge or cross one another on the map in the case of

5 / 50

5. Magnetic declination

6 / 50

6. The difference between a level line and a horizontal line is that

7 / 50

7. Find the RL of the collimation line. If the RL of BM is 100 m & BS staff reading is 5.35 m

8 / 50

8. The scale used to measure and to set out the angles is

9 / 50

9. Height of the instrument is equal to:

10 / 50

10. The Philadelphia rod is a type of

11 / 50

11. True meridians

12 / 50

12. For the route survey of a contour map, the method used is

13 / 50

13. The maximum permissible difference allowed while taking down the fore bearing and back bearing of a line is

14 / 50

14. In a survey, it was recorded that Σrise = 0, then

15 / 50

15. The number of horizontal cross wires in a stadia diaphragm is

16 / 50

16. The chain length which is not the standard metric chain length is

17 / 50

17. The rise and fall method of leveling provides a complete check on

18 / 50

18. A building is an obstacle to

19 / 50

19. Theodolite traverse is plotted more accurately by

20 / 50

20. The sensitivity of the bubble tube can be increased by

21 / 50

21. *The two-peg method is used to check the parallelism between the

22 / 50

22. The types of errors that are of a cumulative nature and can be corrected are known as

23 / 50

23. Orientation is the operation of keeping the table at successive stations such that:

24 / 50

24. The angular and linear measurement of the part of the traverse can be checked by

25 / 50

25. A series of straight, parallel, and widely spaced contours on a map represent a

26 / 50

26. The limiting length of an offset does not depend upon

27 / 50

27. In the case of a telescopic alidade, the adjustment done is

28 / 50

28. During chaining along a straight line, the leader of the survey party has three arrows, and while the follower has five arrows. The distance of the follower from the starting point will be

29 / 50

29. The function of the leveling head is

30 / 50

30. Find the length of curve if the radius of the curve is 50 m, and the angle of deflection is 60°

31 / 50

31. A contour map of the area is essential before proceeding with the construction of

32 / 50

32. The image of the objectives formed should lie

33 / 50

33. The angular error of closure or summation error should not exceed (Where N is the number of stations or sides.)

34 / 50

34. A scale representing either three units or only one unit and its fractions up to the second place of the decimal point is

35 / 50

35. The orientation of the table is done by

36 / 50

36. If the image formed by the objective of the telescope is not in the plane of crosshairs, it is called

37 / 50

37. The angle that can be set by a French cross-staff is

38 / 50

38. If the bearing of AB is N 30° W and the bearing of BC is N 40° E, then find the angle < ABC

39 / 50

39. Sensitivity of a level tube is expressed by

40 / 50

40. The shape of the vertical curve generally used is

41 / 50

41. The sensitivity of the bubble tube expressed in terms of the angular value of one division of the bubble is given by

42 / 50

42. The maximum number of omitted measurements that can be calculated from latitudes and departures of a closed traverse is

43 / 50

43. Different grades are joined together by a

44 / 50

44. Contour interval, within the limits of a map

45 / 50

45. Butt rods are used for measuring

46 / 50

46. A field is measured with a 1.0 percent too-long chain is found to be 10,000 acres. The corrected area of the field will be

47 / 50

47. Azimuth and altitude of a star

48 / 50

48. An anallatic lens is a.... used to remove an additive constant in a tacheometer.

49 / 50

49. Find the R.F. of 1cm = 5m

50 / 50

50. Size of a theodolite is specified by

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