Motion in a Plane Mock Test – Class 11 Physics

1. A formula table for constant acceleration in a plane is shown below.

The row that misses the required coefficient is:

2. A projectile is launched with and . Taking , the horizontal distance covered by the time it reaches the highest point is:

3. Three statements about equal, negative, and zero vectors are given.
I. Equal vectors must have the same magnitude and the same direction.
II. Negative vectors must have the same magnitude and opposite directions.
III. A zero vector has a definite direction along the positive -axis.
The supported statements are:

4. The vectors and have equal magnitudes but opposite directions. The value of is:

5. Two particles have velocities and . The velocity of relative to is:

6. A table gives formula forms for uniform circular motion.

The row that contains the incorrect formula is:

7. Study the table of velocity functions and claimed accelerations.

The row that contains a differentiation error is:

8. A displacement vector in a plane has -component and -component . Its vector form is:

9. Two vectors and are added graphically by the triangle law. A common wrong diagram draws the resultant from the head of back to the tail of . The error in this diagram is that:

10. A learner states that the centripetal acceleration of a particle in uniform circular motion is constant because and are constant. The most accurate response is:

11. The table below lists some physical quantities.

The row that does not fit the usual scalar-vector classification is:

12. Use the graph description below.

The direction of the instantaneous velocity at is:

13. Match the basic plane-motion quantities with their usual SI units.

The suitable matching is:

14. Two displacement vectors are arranged head-to-tail: ends where begins. The resultant is represented by the arrow drawn:

15. The expression represents:

16. Assertion: At the highest point of an ideal projectile, the speed is not necessarily zero.
Reason: Only the vertical component of velocity becomes zero there, while the horizontal component remains unchanged.

17. Match the unit-vector symbols with their usual coordinate-axis directions.

The suitable matching is:

18. A particle moves with constant speed along a circular arc. The instantaneous acceleration is perpendicular to the velocity because:

19. A vector polygon has sides representing , , and in head-to-tail order. The final point lies east of the starting point on a diagram with scale . The magnitude of is:

20. A body can have non-zero acceleration even when its speed is constant if:

21. A river is wide and flows east at . A boat has speed relative to water. If the boat heads straight north relative to water, and then instead aims to land exactly opposite the starting point, the two crossing times are respectively:

22. A motion record states that , , and . The velocity at is:

23. A body moves with constant speed along a curved path. Its acceleration may be non-zero because:

24. Use the scale information below.

The physical displacement represented by the arrow is:

25. Instantaneous velocity in a plane is best described as:

26. Three statements about scalars and vectors are given.
I. A scalar may have a unit.
II. A vector must have a direction.
III. A negative sign always proves that a quantity is a vector.
The supported statements are:

27. A vector has components and . Its magnitude and direction are best described as:

28. A table records positions in a plane.

The row that miswrites the position vector is:

29. Two bodies have velocities east and north. Their speeds are the same, but their velocities are not the same because:

30. A particle moves uniformly in a circle. Over a very small time interval , the arc length covered is , and the speed is . In the derivation of centripetal acceleration, the step is used because:

31. A displacement record is shown below.

The row that describes the resultant incorrectly is:

32. For a particle moving uniformly in a circle of radius with angular speed , the linear speed is:

33. A wheel rotates uniformly at . The angular speed of the wheel is:

34. A unit check is made for . If has unit and has unit , then has unit:

35. Assertion: In uniform circular motion, centripetal acceleration changes the direction of velocity but not its magnitude.
Reason: Centripetal acceleration is perpendicular to the instantaneous velocity.

36. A learner writes that if , then has “negative magnitude.” The better repair of this statement is:

37. A particle moves anticlockwise in a circle of radius with speed . It moves from the rightmost point to the topmost point. The average acceleration vector during this motion is:

38. A velocity changes from to in . The average acceleration is:

39. The velocities of two bodies are and . The magnitude of the velocity of relative to is:

40. A particle moves in a circle and its speed is increasing with time. Which comparison with uniform circular motion is correct?

41. A notation record contains the entries below.

The row that misreads the notation is:

42. A particle moves in a circle of radius and completes one revolution in . Its centripetal acceleration is:

43. When two vectors are perpendicular, the resultant formula reduces to because:

44. Two vectors are and . Their sum is:

45. Subtracting a vector from another vector is best understood as:

46. A graph is described below.

The graph should be:

47. A report claims that two vectors of magnitudes and have a resultant of . The report is:

48. A particle has initial velocity and constant acceleration . Its velocity after is:

49. A projectile is launched obliquely and air resistance is neglected. Its horizontal component of velocity remains constant because:

50. If the acceleration due to gravity becomes while the same projectile is launched with the same speed and angle on level ground, its horizontal range becomes: