Motion in a Plane Mock Test – Class 11 Physics

1. A graph is plotted for two fixed vector magnitudes and , with changing as changes. The graph has its largest value at and smallest value at . This behaviour is mainly due to:

2. A path is described as follows: near point , the body’s curve is momentarily horizontal, and the body is moving from left to right. The instantaneous velocity at is:

3. The centripetal acceleration can also be written in terms of angular speed as:

4. The average velocity in a plane is defined as:

5. A row-based comparison of horizontal and oblique projection is shown.

The row that is not consistent with the stated case is:

6. A particle has displacement in . Its average velocity is:

7. A vector has components and . Its magnitude is:

8. The angular speed , period , and frequency in uniform circular motion are related by:

9. Study the table of velocity functions and claimed accelerations.

The row that contains a differentiation error is:

10. A body undergoes two displacements, and . The magnitude of the net displacement is:

11. A displacement is drawn as an arrow on paper. In this representation, the length of the arrow is used to show:

12. A particle starts from the origin with constant acceleration. Its position vectors at and are and , respectively. Its position at is:

13. A projectile is launched with speed at above the horizontal. Taking , its horizontal range on returning to the same level is:

14. A vector has components and . Its magnitude and direction are best described as:

15. A graph is plotted between centripetal acceleration and radius for a fixed angular speed . The graph is:

16. Rain falls vertically downward at , while a person runs east at . Taking east as and upward as , the velocity of rain relative to the person is:

17. A runner completes one full round of a circular track and returns to the starting point. For the complete round, the distance covered and displacement are best described as:

18. A particle moves uniformly along a circular path of radius . After three-fourths of a revolution, the magnitude of its displacement from the starting point is:

19. If the instantaneous velocity of a body is , its instantaneous speed is:

20. A rotating platform has two marks and at radii and and the same angular speed...

21. A particle moving uniformly in a circle of radius completes one revolution in . Using , its average speed over one revolution is:

22. A cyclist moving east at observes another cyclist moving west at . Taking east as , the velocity of the west-moving cyclist relative to the east-moving cyclist is:

23. Assertion: If a vector makes an angle with the positive -axis, the formulas and can give negative component values.
Reason: The signs of and depend on the quadrant in which the vector lies.

24. A component method calculation gives and for a resultant force . The resultant force is:

25. Two vectors and are added graphically by the triangle law. A common wrong diagram draws the resultant from the head of back to the tail of . The error in this diagram is that:

26. A projectile has trajectory , where and are in . Taking , the speed of the projectile when is:

27. A vector of magnitude is directed at above the positive -axis. Its components are:

28. Two vectors of magnitudes and make an angle of . The resultant magnitude and the value of , where is measured from the vector, are:

29. A particle in uniform circular motion moves through half a revolution. If its speed is , the magnitude of the change in velocity during this half revolution is:

30. A table gives component-wise results for and .

The row that contains the component error is:

31. Use the scale information below.

The physical displacement represented by the arrow is:

32. Equal vectors of magnitude make an angle of with each other. Their resultant magnitude is:

33. The same projectile has , , and reaches the ground after . Taking , its speed just before hitting the ground is:

34. Two vectors have components and . They have the same value of , but their directions are different because:

35. A particle moves in a circle of radius with angular speed . Its linear speed is:

36. A projectile is launched from level ground with speed . The angle that gives maximum range is , but the angle that gives maximum height for the same speed is:

37. A position equation is written as , where is in and is in . The acceleration vector is:

38. In deriving the resultant formula for two vectors and , the angle between the two vectors is , but the angle used inside the triangle formed by head-to-tail placement becomes . This leads to the term because:

39. The dimensional formula of centripetal acceleration is:

40. A particle covers a total path length of in , but its displacement is east. Its average speed and average velocity are:

41. A velocity-time graph description is given below.

The acceleration vector is:

42. A table records positions in a plane.

The row that miswrites the position vector is:

43. The component method and graphical method are compared for adding vectors in a plane. The component method is more analytical because it:

44. A motion record states that , , and . The velocity at is:

45. Use the arrangement described below: two position vectors and are drawn from the same origin to points and respectively. The vector represents:

46. A projectile is launched from a cliff with horizontal component and vertical component upward. The ground is below the launch point. Taking , the time to hit the ground is:

47. A stone is thrown obliquely upward from the ground. Its motion is usually treated as motion in a plane because:

48. A formula table for constant acceleration in a plane is shown below.

The row that misses the required coefficient is:

49. The row that correctly distinguishes a vector magnitude from rectangular components is:

The row that should be corrected is:

50. Use the arrangement described below: a projectile is launched from the origin, reaches point at the highest point, and lands at point on the same horizontal level. Air resistance is neglected.
At point , the acceleration vector points: